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This lesson decodes how AQA marks chemistry answers. Understanding mark scheme conventions — particularly for calculations, organic mechanisms, and extended responses — can be the difference between a grade boundary. You will learn exactly how marks are allocated for different question types, the most common mistakes that lose marks, and the specific techniques needed for top marks in calculations, mechanism questions, and graph interpretation.
AQA chemistry calculations are marked using a principle that rewards correct method even when an arithmetic error is made. Here is how it works:
Golden Rule: ALWAYS show your working. A correct answer with no working gets full marks, but a wrong answer with no working gets zero. By showing working, you can pick up method marks even if you make an arithmetic error.
A typical 3-mark calculation might be structured as:
| Mark | Type | What It Rewards |
|---|---|---|
| M1 | Method | Correct formula or approach (e.g. n = m/M) |
| M2 | Method | Correct substitution or intermediate calculation |
| A1 | Answer | Correct final answer with correct units |
A typical 4-mark calculation:
| Mark | Type | What It Rewards |
|---|---|---|
| M1 | Method | Correct setup (e.g. writing the balanced equation) |
| M2 | Method | Correct moles calculation |
| M3 | Method | Correct use of mole ratio |
| A1 | Answer | Correct final answer with units and appropriate significant figures |
AQA mark schemes specify how many significant figures are acceptable. General rules:
Exam Tip: If a question says "Give your answer to an appropriate number of significant figures," aim for 3 s.f. unless the data clearly warrants more or fewer.
The foundation of all chemistry calculations. You must be fluent with:
Titration calculations combine these: use n = c × V for the known solution, apply the mole ratio from the balanced equation, then find the unknown concentration.
| Calculation | Method |
|---|---|
| From calorimetry | q = mcΔT, then ΔH = −q/n |
| From Hess's law (formation data) | ΔrH = Σ ΔfH(products) − Σ ΔfH(reactants) |
| From Hess's law (combustion data) | ΔrH = Σ ΔcH(reactants) − Σ ΔcH(products) |
| From bond enthalpies | ΔH = Σ bonds broken − Σ bonds formed |
| Born-Haber cycle | Sum of enthalpy terms around the cycle = 0 (apply Hess's law) |
| Enthalpy of solution | ΔsolH = −ΔlattH(dissociation) + Σ ΔhydH |
Common Error: Mixing up the signs. When using Hess's law with combustion data, the equation is reactants minus products (opposite to formation data). Draw the Hess's law cycle to avoid confusion.
Steps for a Kc calculation:
Units of Kc depend on the stoichiometry. Work them out from the expression each time — do not guess.
Steps for a Kp calculation:
Common Error: Forgetting that Kp only applies to gaseous equilibria. Solids and pure liquids do not appear in the expression.
Common Error: Getting the sign wrong. Remember: the species with the more positive E° is reduced (gains electrons). The species with the more negative E° is oxidised (loses electrons).
| Scenario | Formula |
|---|---|
| Strong acid | pH = −log₁₀[H⁺], where [H⁺] = concentration of acid × number of H⁺ per molecule |
| Strong base | pOH = −log₁₀[OH⁻]; pH = 14 − pOH (or use Kw = [H⁺][OH⁻] = 1.00 × 10⁻¹⁴) |
| Weak acid | Ka = [H⁺]²/[HA] (assuming [H⁺] is small compared to [HA]); pH = −log₁₀[H⁺] |
| Buffer | Ka = [H⁺][A⁻]/[HA]; rearrange to find [H⁺]; or use pH = pKa + log₁₀([A⁻]/[HA]) |
Important: Always state the assumption you make when calculating pH of a weak acid (that the dissociation is small compared to the initial concentration, so [HA]equilibrium ≈ [HA]initial). If the question asks you to justify this assumption, show that [H⁺] is less than 5% of [HA]initial.
To calculate the pH of a buffer:
Or use the Henderson-Hasselbalch equation: pH = pKa + log₁₀([A⁻] / [HA]).
Mechanism questions are worth 3–5 marks and are among the most frequently examined topics. AQA mark schemes are very specific about what earns marks.
| Feature | Marks? |
|---|---|
| Curly arrow from a lone pair or bond to the correct atom/bond | Yes — essential |
| Curly arrow head pointing to the correct destination (atom or bond) | Yes — essential |
| Correct intermediate(s) shown (e.g. carbocation in electrophilic addition) | Yes |
| Correct product(s) shown with structural formula | Yes |
| Correct charges on intermediates | Yes — often required |
| Dipole shown on the electrophile (e.g. δ+ and δ−) | Sometimes (depends on the question) |
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