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This lesson covers the reactions of aqueous transition metal ions with sodium hydroxide and ammonia, the acidity of hexaaqua ions, and reactions with carbonate ions (AQA 3.2.5). These reactions are frequently tested in practical and written papers.
When transition metal ions dissolve in water, they form hexaaqua complex ions [M(H₂O)₆]^(n+). These ions are acidic because the highly charged metal cation polarises the O–H bonds in the coordinated water molecules, making it easier for a proton to be released.
| Ion | Charge | Ionic radius / pm | Charge density | pH of solution |
|---|---|---|---|---|
| Na⁺ | +1 | 102 | Low | ≈7 (neutral) |
| Mg²⁺ | +2 | 72 | Moderate | ≈6 |
| Al³⁺ | +3 | 53.5 | High | ≈3 |
| Fe³⁺ | +3 | 64.5 | High | ≈2–3 |
| Fe²⁺ | +2 | 78 | Moderate | ≈5 |
Explanation: The metal cation attracts the electron density of the coordinated water molecules towards itself. This weakens the O–H bond and makes it easier for a proton (H⁺) to be lost to a free water molecule:
[M(H₂O)₆]^(n+)(aq) + H₂O(l) ⇌ [M(OH)(H₂O)₅]^((n-1)+)(aq) + H₃O⁺(aq)
The higher the charge and the smaller the ion, the greater the polarisation and the more acidic the solution.
Exam Tip: M³⁺ ions produce more acidic solutions than M²⁺ ions because they have higher charge density and polarise the water ligands more. This is why Fe³⁺ solutions are more acidic than Fe²⁺ solutions.
When sodium hydroxide is added to solutions of transition metal ions, insoluble metal hydroxides precipitate.
| Ion | Formula of aqua ion | Colour of aqua ion | With dilute NaOH | Precipitate colour | With excess NaOH |
|---|---|---|---|---|---|
| Fe²⁺ | [Fe(H₂O)₆]²⁺ | Green | Green precipitate | Green | No change (insoluble) |
| Fe³⁺ | [Fe(H₂O)₆]³⁺ | Yellow/brown | Brown precipitate | Brown (rust-coloured) | No change (insoluble) |
| Cu²⁺ | [Cu(H₂O)₆]²⁺ | Blue | Pale blue precipitate | Pale blue | No change (insoluble) |
| Cr³⁺ | [Cr(H₂O)₆]³⁺ | Green | Green precipitate | Green | Dissolves → dark green solution |
| Al³⁺ | [Al(H₂O)₆]³⁺ | Colourless | White precipitate | White | Dissolves → colourless solution |
| Mn²⁺ | [Mn(H₂O)₆]²⁺ | Very pale pink | Cream/white precipitate | Off-white (darkens in air) | No change (insoluble) |
| Co²⁺ | [Co(H₂O)₆]²⁺ | Pink | Blue-green precipitate | Blue-green | No change (insoluble) |
Iron(II): [Fe(H₂O)₆]²⁺(aq) + 2OH⁻(aq) → Fe(OH)₂(s) + 6H₂O(l) — green precipitate
Fe(OH)₂ is oxidised in air to Fe(OH)₃: 4Fe(OH)₂(s) + O₂(g) + 2H₂O(l) → 4Fe(OH)₃(s) — turns brown
Iron(III): [Fe(H₂O)₆]³⁺(aq) + 3OH⁻(aq) → Fe(OH)₃(s) + 6H₂O(l) — brown precipitate
Copper(II): [Cu(H₂O)₆]²⁺(aq) + 2OH⁻(aq) → Cu(OH)₂(s) + 6H₂O(l) — pale blue precipitate
Chromium(III): [Cr(H₂O)₆]³⁺(aq) + 3OH⁻(aq) → Cr(OH)₃(s) + 6H₂O(l) — green precipitate
With excess NaOH (amphoteric behaviour): Cr(OH)₃(s) + 3OH⁻(aq) → [Cr(OH)₆]³⁻(aq) — dark green solution
Aluminium(III): [Al(H₂O)₆]³⁺(aq) + 3OH⁻(aq) → Al(OH)₃(s) + 6H₂O(l) — white precipitate
With excess NaOH (amphoteric behaviour): Al(OH)₃(s) + OH⁻(aq) → [Al(OH)₄]⁻(aq) — colourless solution
Exam Tip: Only Cr(OH)₃ and Al(OH)₃ dissolve in excess NaOH (amphoteric). Fe(OH)₂, Fe(OH)₃, and Cu(OH)₂ do NOT dissolve in excess NaOH.
When ammonia solution is added, it first acts as a base (forming the hydroxide precipitate), then in excess it may act as a ligand (dissolving the precipitate by forming an ammine complex).
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