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Alcohols are one of the most important homologous series in organic chemistry. They are the gateway to many other functional groups — you can oxidise them to carbonyls and carboxylic acids, dehydrate them to alkenes, substitute them to haloalkanes, and esterify them with carboxylic acids. Understanding their physical properties and classification is therefore essential before we tackle their reactions.
This lesson covers the OCR A-Level Chemistry A (H432) specification point 4.2.1: classification of alcohols as primary, secondary or tertiary, and the effect of hydrogen bonding on their physical properties.
An alcohol is a compound containing a hydroxyl group (–OH) bonded directly to a saturated (sp³) carbon atom. The general formula for a saturated aliphatic alcohol is:
CnH2n+1OH
or equivalently CnH2n+2O.
Key Definition — Alcohol: An organic compound containing the hydroxyl functional group (–OH) bonded to a carbon atom that is itself saturated.
Note that phenol (C₆H₅OH) is not classified as a simple alcohol in OCR A-Level terms — the –OH is attached to an aromatic sp² carbon. This gives phenol markedly different properties and is treated separately at A2.
Alcohols are classified according to the number of carbon atoms bonded to the carbon carrying the –OH group.
| Class | Carbons on C–OH carbon | Structural cue |
|---|---|---|
| Primary (1°) | 0 or 1 | R–CH₂–OH |
| Secondary (2°) | 2 | R₂CH–OH |
| Tertiary (3°) | 3 | R₃C–OH |
graph TD
A[Alcohol R-OH] --> B{How many C atoms bonded to the C-OH carbon?}
B -->|0 or 1| C[Primary 1 degrees<br/>e.g. methanol, ethanol, propan-1-ol]
B -->|2| D[Secondary 2 degrees<br/>e.g. propan-2-ol, butan-2-ol]
B -->|3| E[Tertiary 3 degrees<br/>e.g. 2-methylpropan-2-ol]
| Alcohol | Structure | Class |
|---|---|---|
| Methanol | CH₃–OH | Primary |
| Ethanol | CH₃–CH₂–OH | Primary |
| Propan-1-ol | CH₃–CH₂–CH₂–OH | Primary |
| Propan-2-ol | (CH₃)₂CH–OH | Secondary |
| Butan-2-ol | CH₃–CH(OH)–CH₂–CH₃ | Secondary |
| 2-Methylpropan-2-ol | (CH₃)₃C–OH | Tertiary |
Tip: Methanol is officially counted as primary even though there are zero carbons on the C–OH carbon. Some textbooks call it "special"; OCR mark schemes accept primary.
The class of an alcohol controls how it reacts with oxidising agents. As we shall see in Lesson 2, primary alcohols oxidise to aldehydes then carboxylic acids, secondary alcohols oxidise to ketones, and tertiary alcohols resist oxidation under normal lab conditions. Identifying the class is therefore the first step in predicting the product of an oxidation.
The hydroxyl group is both a hydrogen bond donor (because the O–H hydrogen is highly deshielded) and a hydrogen bond acceptor (because oxygen has two lone pairs). This gives alcohols much stronger intermolecular forces than alkanes of comparable molecular mass.
The boiling point of an alcohol reflects the energy required to break the intermolecular forces holding the molecules together in the liquid. Alcohols have:
Compare the boiling points of some short molecules of similar molecular mass:
| Molecule | Mᵣ | Boiling point (°C) | Strongest IMF |
|---|---|---|---|
| Ethane, C₂H₆ | 30 | –89 | London |
| Methanal, HCHO | 30 | –19 | Permanent dipole |
| Methanol, CH₃OH | 32 | 65 | Hydrogen bonding |
| Propane, C₃H₈ | 44 | –42 | London |
| Ethanal, CH₃CHO | 44 | 20 | Permanent dipole |
| Ethanol, C₂H₅OH | 46 | 78 | Hydrogen bonding |
Ethanol boils ~167 °C higher than propane despite being almost the same size. That difference is entirely down to hydrogen bonding.
graph LR
A[Ethane -89 C<br/>London only] --> B[Methanal -19 C<br/>Dipole-dipole]
B --> C[Methanol +65 C<br/>Hydrogen bonds]
Short-chain alcohols (methanol, ethanol, propan-1-ol, propan-2-ol) are miscible with water in all proportions because their –OH group can hydrogen bond directly with water molecules. As the carbon chain lengthens, the hydrophobic alkyl "tail" dominates and solubility drops sharply.
| Alcohol | Solubility in water at 20 °C |
|---|---|
| Methanol | Miscible |
| Ethanol | Miscible |
| Propan-1-ol | Miscible |
| Butan-1-ol | ~8 g per 100 cm³ |
| Pentan-1-ol | ~2 g per 100 cm³ |
| Hexan-1-ol | ~0.6 g per 100 cm³ |
| Decan-1-ol | Essentially insoluble |
graph TD
A[Small alcohol e.g. ethanol] --> B[-OH group dominates]
B --> C[H-bonds with water easily]
C --> D[Fully miscible]
E[Large alcohol e.g. decan-1-ol] --> F[Alkyl chain dominates]
F --> G[Cannot disrupt water H-bonding<br/>enough to dissolve]
G --> H[Insoluble]
Place the following molecules in order of increasing boiling point, and justify your ranking: propane, propan-1-ol, propan-2-ol, propanal, propane-1,2,3-triol (glycerol).
Answer:
Notice the dramatic jump from propanal to the alcohols (~50 °C per hydrogen bond), and an even bigger jump from propan-1-ol to glycerol because you gain three hydrogen bonds per molecule.
Classify each alcohol as primary, secondary or tertiary:
(a) 2-Methylbutan-2-ol, (CH₃)₂C(OH)–CH₂CH₃ (b) 3-Methylbutan-1-ol, (CH₃)₂CH–CH₂–CH₂OH (c) Cyclohexanol
Answer:
(a) The C–OH carbon is bonded to two methyl groups and one ethyl group — three carbons — so this is tertiary. (b) The C–OH carbon is bonded to a single CH₂ group — one carbon — so this is primary. (c) In cyclohexanol the C–OH carbon is part of the ring and is bonded to two ring carbons — two carbons — so this is secondary.
Reference: OCR A-Level Chemistry A (H432), Module 4 — Core Organic Chemistry, section 4.2.1: alcohols as primary, secondary and tertiary; physical properties of alcohols including the influence of hydrogen bonding on boiling point and water solubility.