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Group 2 oxides (MO) are ionic and react with water to form metal hydroxides:
MO(s) + H2O(l) → M(OH)2(aq or s)
| Oxide | Reaction with water | Solubility of product |
|---|---|---|
| MgO | Slow, partial reaction | Mg(OH)2 is only sparingly soluble |
| CaO | Exothermic - "slaking of lime" | Ca(OH)2 slightly soluble ("limewater") |
| SrO | Vigorous | Sr(OH)2 more soluble |
| BaO | Very vigorous | Ba(OH)2 readily soluble |
The resulting solutions are alkaline because hydroxide ions (OH-) are released. As you go down the group, the oxides react more vigorously and the resulting hydroxides are more soluble → higher OH- concentration → higher pH.
| Hydroxide | Approximate pH of saturated solution |
|---|---|
| Mg(OH)2 | ~10 |
| Ca(OH)2 | ~12 |
| Sr(OH)2 | ~13 |
| Ba(OH)2 | ~13-14 |
graph TD
A[Group 2 Hydroxides] --> B[Mg OH 2: insoluble 'milk of magnesia']
A --> C[Ca OH 2: slightly soluble 'limewater']
A --> D[Sr OH 2: more soluble]
A --> E[Ba OH 2: readily soluble]
F[Going down: solubility INCREASES] --> A
| Hydroxide | Solubility (mol/100g water at 25 degC) |
|---|---|
| Mg(OH)2 | ~0.00002 (insoluble) |
| Ca(OH)2 | ~0.002 (sparingly soluble) |
| Sr(OH)2 | ~0.008 |
| Ba(OH)2 | ~0.05 (soluble) |
OCR does not require you to explain the thermodynamic reason for this trend in detail (that belongs to A-Level energetics/lattice enthalpy in the enthalpy chapter); you need to recall the direction and its chemical consequences.
The trend for sulfates is opposite to that of hydroxides:
graph TD
A[Group 2 Sulfates] --> B[MgSO4: very soluble 'Epsom salts']
A --> C[CaSO4: slightly soluble 'plaster of Paris']
A --> D[SrSO4: almost insoluble]
A --> E[BaSO4: insoluble 'barite']
F[Going down: solubility DECREASES] --> A
| Sulfate | Solubility (mol/100g water) |
|---|---|
| MgSO4 | ~0.3 (very soluble) |
| CaSO4 | ~0.0002 (sparingly soluble) |
| SrSO4 | ~6 x 10-6 |
| BaSO4 | ~1 x 10-8 (insoluble) |
BaSO4's extreme insolubility has two famous applications:
Mg(OH)2 is a weak, insoluble base. Because it is insoluble, it does not raise the pH of the stomach too far - it only reacts with the excess acid present. It neutralises hydrochloric acid in the stomach:
Mg(OH)2(s) + 2HCl(aq) → MgCl2(aq) + 2H2O(l)
Used to treat indigestion and heartburn. Its insolubility is an advantage: it avoids over-alkalinising the stomach.
Agricultural soils become acidic over time (due to acid rain, nitrogen fertiliser, organic matter decay). Ca(OH)2 is spread on fields to neutralise acidity and raise the pH to a level favourable for crops:
Ca(OH)2(s) + 2H+(aq) → Ca2+(aq) + 2H2O(l)
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