You are viewing a free preview of this lesson.
Subscribe to unlock all 10 lessons in this course and every other course on LearningBro.
By the end of this lesson you should be able to:
Disproportionation is a redox reaction in which the same element is simultaneously oxidised and reduced. One species is split into two products with different oxidation numbers - one higher and one lower than the starting number.
2H2O2 → 2H2O + O2 (disproportionation)
Oxygen starts at -1 (in peroxide); ends as -2 in H2O (reduced) and 0 in O2 (oxidised). Same element, same reaction, both oxidised and reduced.
Chlorine dissolves slightly in water and undergoes disproportionation:
Cl2(aq) + H2O(l) → HClO(aq) + HCl(aq)
Or in ionic form:
Cl2(aq) + H2O(l) → HClO(aq) + H+(aq) + Cl-(aq)
Oxidation numbers of chlorine:
Half of the chlorine is oxidised (0 → +1) and half is reduced (0 → -1). This is disproportionation.
HClO (chloric(I) acid) is a powerful oxidising agent that kills bacteria and viruses by oxidising essential cellular components. Adding a tiny amount of chlorine to drinking water and swimming pools provides continuous sterilisation. The equilibrium maintains a small concentration of HClO, which is effective even at ~1 ppm.
| Benefit | Risk |
|---|---|
| Kills waterborne pathogens (cholera, typhoid) | Cl2 is toxic at high concentration |
| Easy to produce and store as a liquid | Can react with organic matter to form chlorinated hydrocarbons (some are carcinogenic) |
| Long-lasting effect in pipes | Taste/smell can be unpleasant |
| Millions of lives saved worldwide | Historical use as a chemical weapon (WWI) |
The consensus is that the benefits massively outweigh the risks for public health.
At room temperature with cold, dilute sodium hydroxide:
Cl2(aq) + 2NaOH(aq) → NaCl(aq) + NaClO(aq) + H2O(l)
Oxidation numbers of chlorine:
Again this is disproportionation. The product mixture is household bleach - a solution of NaClO (the active ingredient) and NaCl. NaClO is used as a disinfectant and bleaching agent.
Conditions matter: with hot concentrated NaOH, chlorine disproportionates further to chlorate(V):
3Cl2 + 6NaOH(hot conc) → 5NaCl + NaClO3 + 3H2O
But this is not required for OCR AS-level - focus on the cold dilute reaction.
graph TD
A[Cl2 gas] --> B[+ H2O]
A --> C[+ cold dilute NaOH]
A --> D[+ Na metal]
B --> B1[HClO + HCl disproportionation, water treatment]
C --> C1[NaCl + NaClO + H2O bleach, disproportionation]
D --> D1[2NaCl simple redox, no disproportionation]
We have seen that oxidising ability decreases down Group 7 (F2 > Cl2 > Br2 > I2). The mirror-image trend is the reducing ability of the halide ions:
Reducing ability of halide ions increases down the group: I- > Br- > Cl- > F-
A reducing agent loses electrons; halide ions lose an electron to become a halogen atom:
2X-(aq) → X2 + 2e- (oxidation)
Subscribe to continue reading
Get full access to this lesson and all 10 lessons in this course.