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When identifying unknown anions, the sequence matters because some tests can interfere with others. The OCR-recommended order is:
graph TD
A[Unknown solution] --> B[1. Test for carbonate dilute HCl]
B --> B1[Gas evolved? -> CO3 2- present]
B --> C[2. Test for sulfate BaCl2 + dilute HCl]
C --> C1[White precipitate -> SO4 2- present]
C --> D[3. Test for halide AgNO3 + dilute HNO3]
D --> D1[Coloured precipitate -> halide present]
D --> E[Confirm with ammonia NH3]
Why this order?
Always acidify with the correct acid: dilute HCl for sulfate (removes carbonate as CO2), dilute HNO3 for halide (removes any residual carbonate or sulfate).
Test: Add dilute hydrochloric acid (or any strong acid) to the solid or solution.
Observation: Effervescence (bubbles of colourless gas). Collect the gas and bubble through limewater. If limewater turns cloudy/milky, the gas is CO2 and the anion is carbonate.
Ionic equation:
CO3^2-(s/aq) + 2H+(aq) → CO2(g) + H2O(l)
Limewater test for CO2:
Ca(OH)2(aq) + CO2(g) → CaCO3(s) + H2O(l) (calcium carbonate is the white insoluble precipitate that makes limewater cloudy)
Example: Na2CO3(s) + 2HCl(aq) → 2NaCl(aq) + CO2(g) + H2O(l)
Test: Add dilute hydrochloric acid first (to eliminate carbonate), then add aqueous barium chloride (or barium nitrate).
Observation: White precipitate of BaSO4.
Ionic equation:
Ba2+(aq) + SO4^2-(aq) → BaSO4(s)
The HCl acidifies and removes any carbonate as CO2. Without this step, BaCO3 (also a white precipitate) would give a false positive. BaSO4 is extremely insoluble - the Ksp is about 10^-10 - and the white precipitate is a clear, unambiguous confirmation of sulfate.
Test: Add dilute nitric acid first (to eliminate carbonate and sulfate), then add aqueous silver nitrate.
Observation (colour of precipitate):
| Halide | Ionic equation | Precipitate colour |
|---|---|---|
| Cl- | Ag+(aq) + Cl-(aq) → AgCl(s) | White |
| Br- | Ag+(aq) + Br-(aq) → AgBr(s) | Cream |
| I- | Ag+(aq) + I-(aq) → AgI(s) | Yellow |
The colours are subtle - white/cream/yellow can be hard to distinguish, especially in dim light. To confirm, perform a second test with aqueous ammonia.
| Precipitate | Dilute NH3 | Concentrated NH3 |
|---|---|---|
| AgCl (white) | Dissolves | Dissolves |
| AgBr (cream) | Insoluble | Dissolves |
| AgI (yellow) | Insoluble | Insoluble |
The silver halide forms a soluble complex ion [Ag(NH3)2]+ when dissolved:
AgCl(s) + 2NH3(aq) → [Ag(NH3)2]+(aq) + Cl-(aq)
The solubility in ammonia mirrors the trend in silver halide solubility: AgI is the most insoluble (because Ag-I is more covalent, larger polarisable ion), so it resists even concentrated ammonia.
graph TD
A[Unknown with AgNO3 + dil HNO3] --> B{Precipitate colour?}
B -->|White| C[AgCl - Cl- present]
B -->|Cream| D[AgBr - Br- present]
B -->|Yellow| E[AgI - I- present]
C --> C1[Add dil NH3]
C1 --> C2[Dissolves: confirms Cl-]
D --> D1[Add dil NH3]
D1 --> D2[No change]
D2 --> D3[Add conc NH3]
D3 --> D4[Dissolves: confirms Br-]
E --> E1[Add dil NH3]
E1 --> E2[No change]
E2 --> E3[Add conc NH3]
E3 --> E4[No change: confirms I-]
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