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Newton's law of restitution introduces the coefficient of restitution e, which measures the "bounciness" of a collision. This is a central concept in AQA Further Mechanics 1.
For a direct (head-on) collision between two particles:
e = speed of separation / speed of approach
where 0 <= e <= 1.
If particle A has velocity u_1 before and v_1 after, and particle B has velocity u_2 before and v_2 after (all measured in the same positive direction):
Speed of approach = u_1 - u_2 (assuming A approaches B, so u_1 > u_2)
Speed of separation = v_2 - v_1 (B moves faster than A after collision)
e = (v_2 - v_1) / (u_1 - u_2)
A ball hits a wall at 10 m s^(-1). The coefficient of restitution is 0.7. Find the rebound speed.
Solution:
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