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When equations cannot be solved algebraically, numerical methods provide approximate solutions. This lesson covers the change-of-sign method, iteration (fixed-point), Newton-Raphson, and the trapezium rule.
If f(x) is continuous on [a, b] and f(a) and f(b) have opposite signs, then there is at least one root in the interval (a, b).
Show that x³ − 3x − 5 = 0 has a root between x = 2 and x = 3.
f(2) = 8 − 6 − 5 = −3 (negative)
f(3) = 27 − 9 − 5 = 13 (positive)
Sign change → root exists in (2, 3). ∎
The method fails if:
Rearrange f(x) = 0 into the form x = g(x), then use the iteration:
xₙ₊₁ = g(xₙ)
starting from an initial estimate x₀.
The iteration converges if |g’(x)| < 1 near the root.
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