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The ideal gas equation combines all three gas laws into a single equation and introduces the important constants R (the molar gas constant) and k (the Boltzmann constant). This lesson also covers the concept of the mole, the Avogadro constant, and the assumptions that define an ideal gas.
The ideal gas equation can be written in two forms:
pV = nRT (using moles)
pV = NkT (using number of molecules)
where:
A mole is the SI unit for amount of substance. One mole of any substance contains exactly 6.022 × 10²³ particles (atoms, molecules, ions, etc.). This number is called the Avogadro constant (Nₐ).
Nₐ = 6.022 × 10²³ mol⁻¹
The relationship between the number of moles (n) and the number of molecules (N) is:
N = nNₐ
The molar mass (M) is the mass of one mole of a substance, measured in kg mol⁻¹ (or g mol⁻¹ in chemistry). For example:
The number of moles is:
n = m/M (mass divided by molar mass)
The mass of a single molecule is:
m_molecule = M/Nₐ
The Boltzmann constant is the gas constant per molecule:
k = R/Nₐ = 8.31 / (6.022 × 10²³) = 1.38 × 10⁻²³ J K⁻¹
This can be verified:
pV = nRT = (N/Nₐ)RT = N(R/Nₐ)T = NkT ✓
An ideal gas is a theoretical model. The assumptions are:
Exam Tip: You must be able to state the assumptions of an ideal gas. Examiners typically award one mark per distinct assumption, up to a maximum of 3–4 marks. The most commonly missed assumptions are the negligible volume of molecules and the negligible collision duration.
Question: Calculate the volume occupied by 2.0 mol of an ideal gas at a temperature of 300 K and a pressure of 1.0 × 10⁵ Pa.
Solution:
V = nRT/p = (2.0 × 8.31 × 300) / (1.0 × 10⁵)
V = 4986 / 100 000 = 0.0499 m³ ≈ 0.050 m³ (50 litres)
Question: A container holds 5.0 × 10²⁴ molecules of nitrogen gas at 400 K and a pressure of 2.0 × 10⁵ Pa. Calculate the volume of the container.
Solution:
V = NkT/p = (5.0 × 10²⁴ × 1.38 × 10⁻²³ × 400) / (2.0 × 10⁵)
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