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Thomas Young's double slit experiment (1801) provided the first conclusive evidence that light behaves as a wave. It remains one of the most important experiments in physics and is a required part of the AQA A-Level specification.
The apparatus consists of:
Light from the single source passes through the double slit. Each slit acts as a separate coherent source (because they originate from the same wavefront). The two sets of diffracted waves overlap and interfere on the screen.
When using a non-laser source, a single slit is placed before the double slit to ensure spatial coherence. The single slit produces a single diffraction pattern, illuminating both slits of the double slit with light from the same wavefront. This guarantees a constant phase relationship between the two slits.
A laser already produces spatially coherent light, so the single slit can be omitted.
On the screen, an alternating pattern of bright fringes (maxima) and dark fringes (minima) is observed:
The fringes are equally spaced (for small angles) and parallel to the slits. The central bright fringe (zeroth order, n = 0) is on the axis of symmetry, where the path difference is zero.
The distance between adjacent bright fringes (or adjacent dark fringes) is called the fringe spacing (or fringe width), w:
w = λD/s
where:
Consider the nth bright fringe at a position y on the screen, measured from the central maximum. For a bright fringe, the path difference from the two slits must equal nλ.
Using geometry, for small angles θ:
The spacing between the nth and (n+1)th maxima is: w = y(n+1) − y(n) = (n+1)λD/s − nλD/s = λD/s
Exam Tip: This derivation requires the small angle approximation (sin θ ≈ tan θ ≈ θ for small θ in radians). This is valid when D >> s, which is always the case in practice.
Worked Example 1 — Red laser light of wavelength 635 nm passes through a double slit with slit separation 0.40 mm. The screen is 2.5 m from the slits. Calculate the fringe spacing.
λ = 635 nm = 635 × 10⁻⁹ m = 6.35 × 10⁻⁷ m s = 0.40 mm = 4.0 × 10⁻⁴ m D = 2.5 m
w = λD/s = (6.35 × 10⁻⁷ × 2.5)/(4.0 × 10⁻⁴)
w = (1.5875 × 10⁻⁶)/(4.0 × 10⁻⁴) = 3.97 × 10⁻³ m
w = 4.0 × 10⁻³ m = 4.0 mm
Worked Example 2 — In a Young's double slit experiment, the fringe spacing is measured as 2.8 mm when the slit-to-screen distance is 1.80 m and the slit separation is 0.35 mm. Calculate the wavelength of the light.
w = 2.8 mm = 2.8 × 10⁻³ m D = 1.80 m s = 0.35 mm = 3.5 × 10⁻⁴ m
Rearranging w = λD/s:
λ = ws/D = (2.8 × 10⁻³ × 3.5 × 10⁻⁴)/1.80
λ = (9.80 × 10⁻⁷)/1.80 = 5.44 × 10⁻⁷ m
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