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This lesson covers two key industrial processes in the AQA GCSE Combined Science Trilogy (8464) specification: fractional distillation of crude oil and cracking of long-chain hydrocarbons. You need to understand how crude oil is separated into useful fractions and why cracking is necessary.
Fractional distillation is the process used to separate crude oil into useful fractions — groups of hydrocarbons with similar boiling points and chain lengths.
graph TB
subgraph "Fractionating Column"
direction TB
TOP["🔝 Cool — ~25°C"]
R["Refinery gases (C1–C4) — gases"]
P["Petrol/Gasoline (C5–C10) — liquid"]
N["Naphtha — liquid"]
K["Kerosene (C11–C15) — liquid"]
DI["Diesel (C15–C20) — liquid"]
FO["Fuel oil (C20–C40) — liquid"]
BIT["Bitumen (C40+) — solid/semi-solid"]
BOT["🔥 Hot — ~400°C"]
end
TOP --- R --- P --- N --- K --- DI --- FO --- BIT --- BOT
| Fraction | Carbon Chain Length | Boiling Range | Uses |
|---|---|---|---|
| Refinery gases | C₁–C₄ | Below 25°C | Bottled gas (LPG), heating |
| Petrol (gasoline) | C₅–C₁₀ | 25–75°C | Fuel for cars |
| Naphtha | C₅–C₁₀ | 75–150°C | Feedstock for chemicals |
| Kerosene | C₁₁–C₁₅ | 150–240°C | Jet fuel |
| Diesel | C₁₅–C₂₀ | 240–350°C | Fuel for lorries, buses, trains |
| Fuel oil | C₂₀–C₄₀ | 350–500°C | Fuel for ships, power stations |
| Bitumen | C₄₀+ | Above 500°C | Road surfaces, roofing |
Exam Tip: You do not need to memorise the exact boiling ranges, but you must know the order of fractions from top to bottom and understand that boiling point increases down the column.
Fractional distillation works because the different hydrocarbons in crude oil have different boiling points due to their different chain lengths. This is a physical process — no chemical bonds are broken. The hydrocarbons are separated based on their intermolecular forces.
| Chain Length | Intermolecular Forces | Boiling Point | Position in Column |
|---|---|---|---|
| Short | Weak | Low | Top |
| Long | Strong | High | Bottom |
The fractions produced by fractional distillation do not always match the demand for each fraction:
This mismatch is solved by cracking.
Cracking is the process of breaking down long-chain hydrocarbons into shorter, more useful molecules. The products include shorter alkanes (for fuels) and alkenes (for making polymers/plastics).
| Type | Conditions | Details |
|---|---|---|
| Catalytic cracking | High temperature (~600°C), catalyst (zeolite or alumina) | Produces mainly alkenes and branched alkanes |
| Steam cracking | Very high temperature (~850°C), steam | Produces mainly alkenes |
A long-chain alkane is broken into a shorter alkane and one or more alkenes.
Example:
C10H22→C8H18+C2H4
(decane → octane + ethene)
Key Point: Cracking always produces at least one alkene. Alkenes contain a carbon-carbon double bond (C=C) and are described as unsaturated.
Alkenes can be distinguished from alkanes using bromine water:
| Test | Alkane | Alkene |
|---|---|---|
| Bromine water | Stays orange | Turns colourless (decolourised) |
Exam Tip: If a question mentions a hydrocarbon that decolourises bromine water, it is an alkene (unsaturated). Alkanes do not react with bromine water under normal conditions.
Exam Tip: Practise balancing cracking equations. Remember: total carbons on left = total carbons on right, and total hydrogens on left = total hydrogens on right.
Question: Decane (C₁₀H₂₂) is cracked to produce octane (C₈H₁₈) and one other product. Identify the other product and write the balanced equation.
Solution: Carbon balance: 10 − 8 = 2 C. Hydrogen balance: 22 − 18 = 4 H. The remaining fragment is C₂H₄, which is ethene — an alkene.
C10H22→C8H18+C2H4
Question: Suggest a possible cracking of dodecane (C₁₂H₂₆) to give one alkane and two molecules of ethene.
Solution: Ethene is C₂H₄; two ethene molecules = C₄H₈. The alkane must contain the remaining atoms: C = 12 − 4 = 8; H = 26 − 8 = 18. That is octane, C₈H₁₈.
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