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This lesson covers the fundamental electrical quantities — current, charge and potential difference — as required by AQA GCSE Combined Science Trilogy (8464, section 6.2.1). These three quantities and the relationships between them form the foundation for every electricity topic at GCSE.
Electric current is the rate of flow of electric charge. In metallic conductors (such as copper wires), the charge carriers are electrons. In electrolytes (solutions that conduct), the charge carriers are ions.
Current is measured in amperes (A) using an ammeter, which is always connected in series with the component being measured.
Q=I×t
Where:
Rearranging: I=tQ and t=IQ
| Quantity | Symbol | Unit | Unit Symbol |
|---|---|---|---|
| Charge | Q | Coulombs | C |
| Current | I | Amperes | A |
| Time | t | Seconds | s |
Exam Tip (AQA 8464): When defining electric current, say "the rate of flow of electric charge." Do not say "the flow of electrons" — current can also be carried by ions in solutions. The AQA mark scheme requires the precise definition involving charge.
flowchart LR
subgraph "Direction of flow"
direction LR
A["(+) Terminal"] -->|"Conventional current ➜"| B["(−) Terminal"]
B -->|"Electron flow ➜"| A
end
Potential difference (p.d.) is the energy transferred per unit of charge that passes between two points in a circuit. It is sometimes called voltage.
Potential difference is measured in volts (V) using a voltmeter, which is always connected in parallel across the component being measured.
E=Q×V
Rearranging: V=QE
Where:
| Quantity | Symbol | Unit | Unit Symbol |
|---|---|---|---|
| Potential difference | V | Volts | V |
| Energy transferred | E | Joules | J |
| Charge | Q | Coulombs | C |
Exam Tip: A common mistake is confusing potential difference with current. Remember: potential difference tells you how much energy each coulomb of charge transfers. Current tells you how much charge flows per second.
A potential difference of 1 V means that 1 joule of energy is transferred for every 1 coulomb of charge that passes through the component.
1 V=1 J/C
A current of 3 A flows through a lamp for 2 minutes. Calculate the charge that flows.
Step 1: Convert time to seconds: t=2×60=120 s
Step 2: Use Q=I×t
Q=3×120=360 C
A charge of 50 C passes through a resistor and transfers 150 J of energy. Calculate the potential difference.
V=QE=50150=3 V
A 12 V battery transfers charge of 200 C. How much energy is transferred?
E=Q×V=200×12=2400 J
A charge of 900 C flows through a heater in 5 minutes. What is the current?
Step 1: Convert time: t=5×60=300 s
Step 2: I=tQ=300900=3 A
| Mistake | Correction |
|---|---|
| Forgetting to convert minutes to seconds | Always convert to seconds before using Q=It |
| Confusing current and voltage | Current = rate of charge flow; voltage = energy per unit charge |
| Saying current is "used up" | Current is not used up — it is the same at all points in a series circuit |
| Using electron flow direction for conventional current | Use positive-to-negative unless asked specifically about electron flow |
A torch is switched on for 5 minutes. The current in the bulb is 0.30 A. Calculate the total charge that flows.
Step 1 — Convert time: 5 minutes × 60 s = 300 s. Step 2 — Use the equation: Q=I×t. Step 3 — Substitute: Q=0.30×300=90 C.
The bulb transfers 90 coulombs of charge in 5 minutes.
A 12 V car battery drives a current of 5.0 A through a starter motor for 3.0 s. Calculate the energy transferred.
Step 1 — Charge moved: Q=I×t=5.0×3.0=15 C. Step 2 — Energy transferred: E=Q×V=15×12=180 J.
Alternatively, using E=I×V×t=5.0×12×3.0=180 J — the same answer.
A heater transfers 9 600 J of energy when 40 C of charge passes through it. Calculate the potential difference.
Using E=QV, V=E/Q=9600÷40=240 V.
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