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This lesson covers Newton's third law as required by AQA GCSE Combined Science Trilogy (8464), section 6.5.3. This law explains why forces always occur in pairs and is frequently tested in the exam, particularly through questions about everyday situations.
Newton's third law: Whenever two objects interact, the forces they exert on each other are equal in magnitude and opposite in direction.
For every action, there is an equal and opposite reaction.
A Newton's third law pair must satisfy all of the following conditions:
| Feature | Detail |
|---|---|
| Equal in magnitude | Both forces have the same size |
| Opposite in direction | The forces act in opposite directions |
| Same type | Both forces are the same kind (both gravitational, both contact, both electrostatic, etc.) |
| Act on different objects | One force acts on object A, the other on object B |
| Act simultaneously | Both forces exist at the same time |
Exam Tip (AQA 8464): The most common mistake is identifying two forces acting on the same object as a Newton's third law pair. For example, the weight of a book and the normal contact force from the table act on the same object (the book), so they are NOT a third-law pair — they are simply balanced forces.
These forces are equal in magnitude, opposite in direction, the same type (contact), and act on different objects (person and ground).
Both forces are gravitational, equal in magnitude, opposite in direction, and act on different objects.
This is why the swimmer moves forward.
flowchart LR
subgraph "Newton’s Third Law — Rocket"
R["Rocket pushes gases DOWN"] <-->|"Equal and opposite"| G["Gases push rocket UP"]
end
style R fill:#e74c3c,color:#fff
style G fill:#27ae60,color:#fff
This is the single most tested misconception in AQA exams on Newton's third law.
| Feature | Newton's Third Law Pair | Balanced Forces |
|---|---|---|
| Number of objects | Two different objects | One object |
| Type of force | Same type | Can be different types |
| Example | Book pushes table down; table pushes book up | Weight of book (gravity) and normal force on book (contact) |
| Result | Neither force is "cancelled" — they act on different objects | Forces cancel out; resultant = 0 |
A book rests on a table. The weight of the book is 10 N downwards.
(a) What is the normal contact force on the book?
The normal contact force = 10 N upwards (balanced forces on the book).
(b) Identify the Newton's third law pair for the weight of the book.
The weight of the book is the gravitational pull of the Earth on the book (10 N downwards). The third-law pair is the gravitational pull of the book on the Earth (10 N upwards). These are equal, opposite, the same type (gravitational), and act on different objects (book and Earth).
(c) Why is the weight of the book and the normal contact force NOT a Newton's third law pair?
They act on the same object (the book) and are different types of force (gravitational vs contact). A true third-law pair must act on different objects and be the same type.
| Scenario | Force A (on object 1) | Force B (on object 2) |
|---|---|---|
| Walking | Foot pushes ground backwards | Ground pushes foot forwards |
| Sitting on a chair | Body pushes chair down | Chair pushes body up |
| Hitting a tennis ball | Racket pushes ball forwards | Ball pushes racket backwards |
| Car tyre on road | Tyre pushes road backwards | Road pushes tyre forwards |
Exam Tip: When describing a third-law pair, always name BOTH objects and BOTH directions. For example: "The foot pushes the ground backwards, and the ground pushes the foot forwards. These forces are equal in magnitude and opposite in direction."
A common question: "If the forces are equal and opposite, why does anything move?"
The answer: the two forces act on different objects. Each object only experiences one of the forces. The motion of each object depends on the forces acting on that object and its mass (F=ma).
For example, when you push a shopping trolley:
flowchart TD
P["Person pushes trolley with 50 N"]
T["Trolley pushes person with 50 N"]
P -->|"50 N forward on trolley (20 kg)"| TA["Trolley accelerates: a = 50/20 = 2.5 m/s²"]
T -->|"50 N backward on person (70 kg)"| PA["Person decelerates slightly: a = 50/70 = 0.7 m/s²"]
style P fill:#2980b9,color:#fff
style T fill:#e74c3c,color:#fff
style TA fill:#27ae60,color:#fff
style PA fill:#f39c12,color:#fff
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