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This lesson covers the Required Practical to investigate the effect of varying force and mass on the acceleration of an object, as specified by AQA GCSE Combined Science Trilogy (8464), section 6.5.3 (Required Practical Activity 19). This practical directly tests Newton's second law (F=ma) and is a common source of exam questions.
To investigate the relationship between:
| Item | Purpose |
|---|---|
| Dynamics trolley | The object being accelerated |
| Runway (ramp/track) | Smooth surface for the trolley to travel along |
| Light gates and data logger (or ticker tape and timer) | To measure speed and calculate acceleration |
| Pulley and string | To connect hanging masses to the trolley |
| Masses and mass hanger | To provide the accelerating force (weight of hanging masses) |
| Balance | To measure the mass of the trolley and added masses |
flowchart LR
A["Trolley on runway"] --> B["String over pulley"]
B --> C["Hanging masses provide force (F = mg)"]
C --> D["Light gates measure speed"]
D --> E["Data logger calculates acceleration"]
style A fill:#2c3e50,color:#fff
style B fill:#2980b9,color:#fff
style C fill:#e74c3c,color:#fff
style D fill:#f39c12,color:#fff
style E fill:#27ae60,color:#fff
| Variable type | When investigating force | When investigating mass |
|---|---|---|
| Independent (changed) | Force (weight of hanging masses) | Mass (of trolley + added masses) |
| Dependent (measured) | Acceleration | Acceleration |
| Control (kept same) | Total system mass | Applied force |
As force increases, acceleration increases proportionally (straight-line graph through the origin).
a=mF
This confirms Newton's second law: F=ma.
As mass increases, acceleration decreases. The relationship is inversely proportional: a∝m1.
A graph of acceleration against 1/m should be a straight line through the origin.
graph LR
subgraph "Force vs Acceleration"
FA["Straight line through origin"]
FA2["Gradient = 1/m"]
end
subgraph "Acceleration vs 1/Mass"
MA["Straight line through origin"]
MA2["Gradient = F"]
end
style FA fill:#2980b9,color:#fff
style MA fill:#27ae60,color:#fff
A trolley of mass 0.8 kg is accelerated by a force of 2.4 N. Calculate the expected acceleration.
Solution:
a=mF=0.82.4=3.0 m/s²
| Source of error | How to reduce it |
|---|---|
| Friction on the runway | Tilt the runway slightly to compensate |
| Inaccurate timing | Use light gates and a data logger instead of manual timing |
| Masses not transferred correctly | Ensure total system mass remains constant by transferring masses between trolley and hanger |
| Parallax error when reading scales | Read the balance at eye level |
| Air resistance on the trolley | Difficult to eliminate; keep speeds low to minimise the effect |
Tilting the runway compensates for friction. The component of gravity acting down the slope provides a small force that exactly balances the friction force. This means any acceleration measured is due only to the applied force from the hanging masses.
To check: give the trolley a gentle push with no hanging mass. If it travels at constant speed (no acceleration or deceleration), friction has been correctly compensated.
The accelerating force equals the weight of the hanging masses:
F=mhanger×g
Using g=9.8 N/kg (or 10 N/kg if stated):
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