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This lesson covers resultant forces and their effect on objects, as required by AQA GCSE Combined Science Trilogy (8464), section 6.5.1. The resultant force is one of the most important concepts in the entire Forces topic — it determines whether an object accelerates, decelerates, or remains at constant velocity.
A resultant force is the single force that has the same effect as all the individual forces acting on an object combined. It is the overall (net) force.
Two forces of 6 N and 4 N both act to the right:
Resultant = 6 + 4 = 10 N to the right
A force of 12 N acts to the right and 5 N acts to the left:
Resultant = 12 − 5 = 7 N to the right
graph LR
subgraph "Forces in Same Direction"
S1["6 N -->"] --- S2["4 N -->"]
S3["Resultant = 10 N -->"]
end
subgraph "Forces in Opposite Directions"
O1["12 N -->"] --- O2["<-- 5 N"]
O3["Resultant = 7 N -->"]
end
style S3 fill:#27ae60,color:#fff
style O3 fill:#27ae60,color:#fff
A boat has a driving force of 3000 N forwards and water resistance of 1200 N backwards. Calculate the resultant force.
Solution:
Resultant force = 3000 − 1200 = 1800 N forwards
Because there is a resultant force acting forwards, the boat will accelerate in the forward direction.
When all forces cancel out, the resultant force is zero. The object is said to be in equilibrium.
An object with a resultant force of zero will:
| Situation | Forces | Result |
|---|---|---|
| Book on a table | Weight (down) = Normal force (up) | Stationary — balanced |
| Car at constant speed | Driving force = Friction + drag | Constant velocity — balanced |
When the forces do not cancel out, there is a non-zero resultant force. The object will accelerate in the direction of the resultant force.
| Situation | Forces | Result |
|---|---|---|
| Rocket launching | Thrust > Weight | Accelerates upwards |
| Car braking | Braking force > Driving force | Decelerates (slows down) |
flowchart TD
R["Is the resultant force zero?"]
R -->|Yes| B["Forces are BALANCED"]
R -->|No| U["Forces are UNBALANCED"]
B --> BS["Object is stationary OR moving at constant velocity"]
U --> US["Object ACCELERATES in the direction of the resultant force"]
style R fill:#f39c12,color:#fff
style B fill:#27ae60,color:#fff
style U fill:#e74c3c,color:#fff
style BS fill:#2ecc71,color:#fff
style US fill:#c0392b,color:#fff
Exam Tip (AQA 8464): A very common misconception is that "if an object is moving, there must be a force acting on it." This is WRONG. An object moving at constant velocity has a resultant force of zero. Only a change in velocity requires a resultant force.
When an object falls through a fluid (air or water), the sequence of events is:
graph TD
subgraph "Falling Object — Three Stages"
A["Stage 1: Weight > Air resistance"] --> B["Resultant force downwards — ACCELERATES"]
C["Stage 2: Weight still > Air resistance, but gap closing"] --> D["Resultant force decreasing — acceleration decreasing"]
E["Stage 3: Weight = Air resistance"] --> F["Resultant force = 0 — TERMINAL VELOCITY"]
end
style B fill:#e74c3c,color:#fff
style D fill:#f39c12,color:#fff
style F fill:#27ae60,color:#fff
A skydiver of weight 800 N jumps from a plane.
(a) At the moment they jump, what is the air resistance? What is the resultant force?
Solution: Air resistance = 0 N (they have just started falling). Resultant force = 800 − 0 = 800 N downwards.
(b) After some time, the air resistance has increased to 500 N. What is the resultant force?
Solution: Resultant force = 800 − 500 = 300 N downwards. The skydiver is still accelerating, but at a lower rate.
(c) The skydiver reaches terminal velocity. What is the air resistance now?
Solution: At terminal velocity, air resistance = weight = 800 N. Resultant force = 0 N.
In the exam, you may be given a free body diagram and asked to find the resultant force. Follow these steps:
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