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While mitosis produces genetically identical cells, meiosis is the type of cell division that produces genetically unique cells with half the chromosome number. Meiosis is essential for sexual reproduction and is a major source of genetic variation. The Edexcel A-Level Biology specification (9BI0) requires you to understand the process of meiosis and how it generates genetic diversity.
In sexually reproducing organisms, body cells are diploid (2n) — they contain two complete sets of chromosomes (one from each parent). The human diploid number is 46 chromosomes (23 pairs).
If gametes (sex cells) were produced by mitosis, they would also be diploid. When two diploid gametes fused at fertilisation, the offspring would have 4n chromosomes, and this number would double with every generation. This would be unsustainable.
Meiosis solves this problem by producing haploid (n) gametes, each containing half the number of chromosomes of the parent cell. In humans, this means each gamete contains 23 chromosomes. When two haploid gametes fuse at fertilisation, the diploid number is restored.
Diploid cell (2n)meiosisFour haploid cells (n)
Homologous chromosomes (homologues) are pairs of chromosomes that:
For example, in humans, chromosome 9 from the mother and chromosome 9 from the father are homologous — they both carry the gene for ABO blood group at the same locus, but one might carry the allele for blood group A while the other carries the allele for blood group B.
Exam Tip: Do not confuse homologous chromosomes with sister chromatids. Homologous chromosomes are two separate chromosomes (one maternal, one paternal) that carry genes for the same traits. Sister chromatids are two identical copies of a single chromosome, joined at the centromere, produced during DNA replication.
Meiosis consists of two successive divisions:
The result is four genetically unique haploid cells from a single diploid parent cell.
The following diagram provides an overview of the two divisions in meiosis:
flowchart TD
A["Diploid Cell (2n)"] --> B["Meiosis I<br/>Homologous pairs separate"]
B --> C["Two Haploid Cells"]
C --> D["Meiosis II<br/>Sister chromatids separate"]
D --> E["Four Haploid Cells (n)<br/>Genetically unique"]
Meiosis II is essentially the same as mitosis, but it starts with a haploid cell.
| Stage | Key event | Result |
|---|---|---|
| Meiosis I | Homologous chromosomes separated | Two haploid cells |
| Meiosis II | Sister chromatids separated | Four haploid cells |
Meiosis generates genetic variation through three main mechanisms:
During metaphase I, each bivalent can align in one of two orientations at the metaphase plate. The orientation of one bivalent is independent of all others.
For an organism with n pairs of homologous chromosomes, the number of possible combinations of chromosomes in the gametes is:
2n
For humans (n = 23): 223=8,388,608 possible combinations
This means that, through independent assortment alone, a single individual can produce over 8 million genetically different gametes.
During prophase I, non-sister chromatids within a bivalent exchange corresponding segments of DNA at chiasmata. This results in new combinations of alleles on each chromatid — called recombinant chromosomes.
Although not part of meiosis itself, random fertilisation greatly increases genetic variation. Any one of the millions of genetically unique sperm can fuse with any one of the genetically unique eggs:
8,388,608×8,388,608=over 70 trillion possible combinations
And this doesn't even account for crossing over!
Exam Tip: When answering questions about how meiosis generates genetic variation, always describe all three mechanisms: (1) independent assortment during metaphase I, (2) crossing over during prophase I, and (3) random fertilisation. State clearly how each one works and the effect it has. This is a very common 6-mark question.
| Feature | Mitosis | Meiosis |
|---|---|---|
| Number of divisions | One | Two (meiosis I and II) |
| Number of daughter cells | Two | Four |
| Chromosome number of daughters | Diploid (2n) — same as parent | Haploid (n) — half of parent |
| Genetic variation | No — daughters are identical to parent | Yes — daughters are genetically unique |
| Crossing over | No | Yes (during prophase I) |
| Independent assortment | No | Yes (during metaphase I) |
| Homologous pairing (bivalents) | No | Yes (during prophase I) |
| Where it occurs | Somatic (body) cells | Reproductive organs (gonads) |
| Purpose | Growth, repair, asexual reproduction | Production of gametes, genetic variation |
Non-disjunction is the failure of homologous chromosomes (in meiosis I) or sister chromatids (in meiosis II) to separate properly during cell division. This results in gametes with an abnormal number of chromosomes (aneuploidy).
| Condition | Chromosome affected | Karyotype | Effect |
|---|---|---|---|
| Down syndrome | Chromosome 21 (trisomy 21) | 47 chromosomes | Characteristic facial features, learning difficulties, increased health risks |
| Turner syndrome | X chromosome (monosomy X) | 45, X | Female; short stature, infertility |
| Klinefelter syndrome | X chromosome (extra X in males) | 47, XXY | Male; tall, may have reduced fertility |
The risk of non-disjunction increases with maternal age, which is why Down syndrome is more common in babies born to older mothers.
Exam Tip: Non-disjunction can occur in either meiosis I or meiosis II. In meiosis I, homologous pairs fail to separate — both homologues go to the same pole. In meiosis II, sister chromatids fail to separate. Both lead to aneuploidy.
The Edexcel 9BI0 specification places meiosis within Topic 2 (Cells, Viruses and Reproduction) with strong overlap into Topic 3 (Voice of the Genome). Candidates must: describe meiosis as a reduction division producing four genetically variable haploid daughter cells from one diploid parent cell; sequence the eight stages across Meiosis I (prophase I, metaphase I, anaphase I, telophase I) and Meiosis II (prophase II, metaphase II, anaphase II, telophase II); identify three sources of genetic variation — independent assortment of homologues at metaphase I, crossing-over between non-sister chromatids of homologues paired as bivalents in prophase I, and random fertilisation of haploid gametes; quantify variation as 2n gamete types from independent assortment alone (n = haploid number; for humans 223 ≈ 8.4 × 106); and explain the consequences of non-disjunction for aneuploidy. Synoptic links: lesson 6 (mitosis — for direct contrast), lesson 8 (cell differentiation — what fertilised diploid zygotes go on to do), lesson 9 (gamete formation specifics — spermatogenesis and oogenesis), Topic 8 (genetic disorders arising from non-disjunction — trisomy 21 Down syndrome, monosomy X Turner syndrome) and Topic 5 (natural selection acting on heritable variation that meiosis generates) — refer to the official Pearson Edexcel 9BI0 specification document for exact wording.
Question (8 marks):
A diploid mammalian cell with a haploid number n = 4 enters meiosis.
(a) Construct a labelled comparison table contrasting the outputs of mitosis and meiosis from this cell, covering: number of daughter cells, ploidy, genetic identity, chromosome number relative to parent, and number of nuclear divisions involved. (3)
(b) Calculate the maximum number of genetically distinct gamete types this cell could produce from independent assortment alone, and state the equivalent figure for a human cell. Show your working. (3)
(c) Explain why the actual number of genetically distinct gametes produced is far greater than the figure calculated in (b). (2)
Solution with mark scheme:
(a) Step 1 — construct the table.
| Feature | Mitosis output | Meiosis output |
|---|---|---|
| Daughter cells | 2 | 4 |
| Ploidy | Diploid (2n) | Haploid (n) |
| Genetic identity | Genetically identical to parent | Genetically variable, all unique |
| Chromosome number | Same as parent | Halved relative to parent |
| Nuclear divisions | 1 | 2 (Meiosis I + Meiosis II) |
M1 (AO1.1) — correct daughter-cell number and ploidy stated for both (2 diploid vs 4 haploid).
A1 (AO1.2) — genetic-identity contrast credited (identical clones from mitosis vs unique gametes from meiosis).
A1 (AO2.1) — division-count contrast credited (one nuclear division in mitosis; two in meiosis, with chromosome-number reduction occurring across both divisions taken together — Meiosis I separates homologues, Meiosis II separates sister chromatids).
(b) M1 (AO1.2) — quote the formula: maximum gamete types from independent assortment =2n, where n is the haploid chromosome number.
M1 (AO2.1) — substitute n = 4 for this cell: 24=16 genetically distinct gamete types.
A1 (AO3.2a) — for a human cell, n = 23, so 223≈8.4×106 genetically distinct gamete types from independent assortment alone. A common pitfall is to use n = 46 (diploid) — wrong, because independent assortment operates on homologous pairs, so the exponent is the haploid count.
(c) M1 (AO3.1a) — crossing-over in prophase I shuffles alleles between non-sister chromatids of homologous chromosomes paired as bivalents at chiasmata, generating recombinant chromatids. Multiple chiasmata typically form per bivalent.
A1 (AO3.2a) — random fertilisation then pairs any of ∼8.4×106 female gametes with any of ∼8.4×106 male gametes, giving ∼7×1013 possible zygotes per couple — before crossing-over is added. Many candidates forget random fertilisation as the third source of variation.
Total: 8 marks.
Question (6 marks): Explain how meiosis generates genetic variation in haploid gametes, and discuss the evolutionary significance of that variation.
Mark scheme decomposition by AO:
| Marking point | AO | Credit-worthy content |
|---|---|---|
| 1 | AO1.1 | Names the three sources of variation: independent assortment of homologues at metaphase I; crossing-over between non-sister chromatids of homologous pairs in prophase I; random fertilisation of gametes. |
| 2 | AO1.2 | Locates each correctly in the meiotic timeline — crossing-over occurs in prophase I (chiasma formation between bivalents); independent assortment occurs at metaphase I (random orientation of bivalents on the equator); random fertilisation occurs after meiosis is complete. |
| 3 | AO2.1 | Quantifies independent assortment as 2n combinations (n = haploid number; for humans 223 ≈ 8.4 million) and notes that crossing-over multiplies this further by reshuffling alleles within each chromosome. |
| 4 | AO2.1 | Distinguishes precisely: independent assortment shuffles whole chromosomes; crossing-over shuffles alleles within chromosomes. The two mechanisms are complementary, not interchangeable. |
| 5 | AO3.1a | Links variation to natural selection — heritable phenotypic variation is the raw material on which selection acts; meiosis is the generator of that variation in sexual species, while mitosis (asexual) cannot produce it. |
| 6 | AO3.2a | Concludes by linking variation to adaptive evolution — populations with greater allelic variation respond faster to environmental change (climate shifts, novel pathogens, antibiotic/herbicide pressure). Conversely, asexually reproducing populations face evolutionary "dead ends" when conditions change. |
Total: 6 marks split AO1 = 2, AO2 = 2, AO3 = 2. This is a typical Section A item — Edexcel rewards candidates who integrate the cell-biology mechanism with the evolutionary consequence (AO3) rather than restating the three sources without context (AO1 only).
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