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The Edexcel A-Level Biology specification (9BI0) requires a thorough understanding of prokaryotic cell structure and how it differs from eukaryotic cells. You must also understand the structure of viruses and the debate surrounding whether they can be classified as living organisms. This lesson covers all the key content for Topic 2.
Prokaryotic cells are cells that lack a true nucleus — their genetic material is not enclosed within a nuclear envelope. The term "prokaryote" comes from the Greek pro (before) and karyon (kernel/nucleus). Prokaryotes include the domains Bacteria and Archaea.
Prokaryotic cells are typically much smaller than eukaryotic cells, usually in the range of 0.2–5.0 μm in diameter, compared to 10–100 μm for most eukaryotic cells.
Exam Tip: The specification requires you to understand the structural features of prokaryotic cells and be able to compare them with eukaryotic cells. A comparison table is almost always the best way to present this in an exam answer.
| Feature | Gram-positive bacteria | Gram-negative bacteria |
|---|---|---|
| Cell wall thickness | Thick peptidoglycan layer (20–80 nm) | Thin peptidoglycan layer (5–10 nm) |
| Outer membrane | Absent | Present (contains lipopolysaccharides) |
| Gram stain result | Purple/violet | Pink/red |
| Examples | Staphylococcus aureus | Escherichia coli |
Plasmids are small, circular DNA molecules that replicate independently of the main chromosome. They typically carry genes that confer a selective advantage, such as:
Plasmids can be transferred between bacteria via conjugation (horizontal gene transfer), which is a major factor in the spread of antibiotic resistance.
Exam Tip: Plasmids are also essential tools in genetic engineering and biotechnology. You may be asked to explain how plasmids are used as vectors to introduce foreign genes into bacterial cells.
Not all bacteria possess the following structures, but they are commonly found:
| Feature | Prokaryotic Cell | Eukaryotic Cell |
|---|---|---|
| Size | 0.2–5.0 μm | 10–100 μm |
| Nucleus | No true nucleus (nucleoid region) | True nucleus with nuclear envelope |
| DNA | Circular, naked (no histones) | Linear, associated with histones |
| Chromosomes | Single chromosome + plasmids | Multiple chromosomes |
| Ribosomes | 70S | 80S |
| Membrane-bound organelles | Absent | Present (e.g. mitochondria, ER, Golgi) |
| Cell wall | Peptidoglycan | Cellulose (plants), chitin (fungi), absent (animals) |
| Reproduction | Binary fission | Mitosis / meiosis |
| Flagella | Simple (flagellin) | Complex (9+2 microtubule arrangement) |
Viruses are non-cellular, obligate intracellular parasites. They are much smaller than bacteria, typically 20–300 nm in diameter, and can only be seen using an electron microscope.
All viruses share certain structural features:
| Component | Description |
|---|---|
| Nucleic acid (genome) | Either DNA or RNA (never both); can be single-stranded (ss) or double-stranded (ds) |
| Capsid | A protein coat surrounding the nucleic acid, made up of repeating protein subunits called capsomeres |
| Envelope (some viruses) | A lipid bilayer derived from the host cell membrane; contains viral glycoproteins |
| Attachment proteins | Surface proteins that enable the virus to bind to specific receptors on the host cell |
| Virus | Nucleic acid | Envelope | Shape | Host |
|---|---|---|---|---|
| HIV (Human Immunodeficiency Virus) | ssRNA (retrovirus) | Yes | Spherical | Human T-helper cells |
| Influenza | ssRNA | Yes | Spherical | Respiratory epithelial cells |
| Tobacco Mosaic Virus (TMV) | ssRNA | No | Rod-shaped / helical | Tobacco plant cells |
| Bacteriophage (T4 phage) | dsDNA | No | Complex (head + tail) | E. coli bacteria |
| SARS-CoV-2 | ssRNA | Yes | Spherical with spike proteins | Human respiratory cells |
The Edexcel specification specifically requires knowledge of HIV structure:
Exam Tip: HIV is a retrovirus because it carries the enzyme reverse transcriptase, which catalyses the synthesis of DNA from an RNA template. This is the reverse of the normal flow of genetic information (DNA → RNA → protein), hence the name.
This is a classic discussion point in biology. Viruses display some characteristics of living organisms but lack others:
| Characteristic of life | Viruses |
|---|---|
| Contain genetic material | Yes (DNA or RNA) |
| Reproduce | Only inside a host cell (cannot reproduce independently) |
| Evolve / mutate | Yes (through mutation and natural selection) |
| Metabolism | No — viruses have no enzymes for metabolic reactions (except a few specific enzymes like reverse transcriptase) |
| Homeostasis | No |
| Growth | No — viruses do not grow |
| Response to stimuli | No |
| Cellular structure | No — viruses are acellular |
The general scientific consensus is that viruses are not considered living organisms because they cannot carry out metabolic processes independently and must hijack host cell machinery to replicate.
The basic steps of viral replication (using a bacteriophage as an example):
Some viruses (e.g. HIV) can also follow the lysogenic cycle, where the viral DNA integrates into the host genome and is replicated along with the host DNA during cell division, remaining dormant until triggered to enter the lytic cycle.
The following diagram summarises the stages of the lytic cycle:
graph TD
A["Attachment<br/>Virus binds to host"] --> B["Penetration<br/>Nucleic acid injected"]
B --> C["Replication<br/>Viral DNA/RNA copied"]
C --> D["Assembly<br/>New virions formed"]
D --> E["Lysis<br/>Cell bursts, viruses released"]
E -->|"Infect new cells"| A
Binary fission is the method of asexual reproduction used by prokaryotic cells. It is simpler and faster than mitosis:
Under optimal conditions, some bacteria (e.g. E. coli) can divide every 20 minutes, leading to exponential population growth.
Exam Tip: Binary fission is not mitosis. Prokaryotes do not undergo mitosis because they lack a nucleus and the complex chromosome organisation of eukaryotes. Make sure you use the correct terminology.
The Edexcel 9BI0 specification places prokaryotic ultrastructure and viral biology within Topic 2: Membranes, Proteins, DNA and Gene Expression and the wider Cells, Viruses & Reproduction strand. The relevant statements require candidates to: describe the ultrastructure of a prokaryotic cell (cell wall of peptidoglycan, plasma membrane, cytoplasm, 70S ribosomes, circular DNA in a nucleoid, plasmids, capsule, flagella, pili and mesosomes); compare prokaryotic with eukaryotic ultrastructure quantitatively in μm and nm; describe the structure of viruses with reference to a non-enveloped example (e.g. tobacco mosaic virus, λ-phage) and an enveloped example (e.g. HIV); and evaluate whether viruses should be classified as living. Synoptic threads run into Topic 4 (Microbiology, Disease and the Immune System) — selective antibiotic toxicity exploits the 70S/80S ribosome distinction — and Topic 6 (Modern Genetics) — bacterial plasmids serve as vectors for recombinant DNA technology and as the molecular substrate for horizontal gene transfer (refer to the official Pearson Edexcel 9BI0 specification document for exact wording).
Question (8 marks):
A student examines a transmission electron micrograph of an unknown microorganism. The cell is approximately 2μm long, has no visible membrane-bound organelles, and shows ribosomes that sediment at 70S in centrifugation. A separate image shows a distinct particle 80nm across with a protein capsid, an inner core of single-stranded RNA and a phospholipid envelope studded with glycoprotein spikes.
(a) Identify each of the two structures, justifying your conclusions with reference to the features given. (4)
(b) The scale bar on the bacterial image reads 1μm and prints as 25mm. Calculate the magnification of the printed image, expressing your answer in standard form. (2)
(c) Explain one reason why the second structure cannot reproduce on its own. (2)
Solution with mark scheme:
(a) Step 1 — interpret the bacterial clues. Cell size ≈2μm, absence of membrane-bound organelles and 70S ribosomes together identify a prokaryotic (bacterial) cell.
M1 (AO2.1) — correct identification of the prokaryotic cell from the size range and lack of membrane-bound organelles. A common pitfall is to write "small eukaryote" because the candidate has missed that 70S ribosomes are diagnostic.
A1 (AO1.2) — explicit justification that 70S ribosomes (smaller than the eukaryotic 80S) and the lack of a true nucleus are diagnostic features.
Step 2 — interpret the viral clues. A particle 80nm across with a capsid, ssRNA genome and phospholipid envelope bearing glycoprotein spikes identifies an enveloped RNA virus (e.g. an influenza-like or HIV-like particle).
M1 (AO2.1) — correct identification as a virus (acellular, sub-100 nm, capsid + nucleic acid).
A1 (AO1.2) — justification linking the envelope and glycoprotein spikes to host-derived membrane and receptor-binding function. A bare "virus" with no justification scores M1 only.
(b) Step 1 — convert units consistently. 1μm=1×10−3mm. Printed length =25mm.
M1 (AO2.1) — correct conversion of μm to mm before dividing.
Step 2 — apply magnification=actual sizeimage size.
M=1×10−3mm25mm=2.5×104
A1 (AO1.1b) — magnification =2.5×104 (or ×25000). Many candidates lose marks here by dividing the raw numbers (25÷1) and reporting ×25, three orders of magnitude wrong.
(c) M1 (AO1.2) — viruses lack ribosomes / metabolic enzymes / a plasma membrane bounding cytoplasm, so they cannot synthesise proteins, generate ATP or replicate their genome unaided.
A1 (AO2.1) — therefore the virus is an obligate intracellular parasite that must hijack a living host cell's ribosomes (70S in bacteria, 80S in eukaryotes) and nucleotide pools to replicate.
Total: 8 marks.
Question (6 marks): Bacteria, viruses and animal cells differ in their structure and in their capacity for independent reproduction. Using examples, evaluate the claim that viruses should be classified as living organisms.
Mark scheme decomposition by AO:
| Marking point | AO | Credit-worthy content |
|---|---|---|
| 1 | AO1.1 | States that the conventional criteria for life include cellular organisation, metabolism, response to stimuli, growth, reproduction, homeostasis and heredity (MRS GREN or equivalent). |
| 2 | AO1.2 | States that viruses are acellular, lack ribosomes and a plasma membrane bounding cytoplasm, and have no independent metabolism. |
| 3 | AO2.1 | Applies the criteria: viruses do possess heritable nucleic acid (DNA or RNA), undergo evolution, and can self-assemble within a host. |
| 4 | AO2.1 | Applies the criteria: viruses cannot reproduce, generate ATP or maintain homeostasis outside a host — they are obligate intracellular parasites. |
| 5 | AO3.1a | Evaluates: by strict criteria viruses fail the test for life; by an inclusive evolutionary criterion they are biological entities subject to selection. |
| 6 | AO3.2a | Reaches a justified conclusion (either side accepted if reasoned), e.g. "viruses are best classified as biological replicators rather than living organisms, because their dependence on host machinery means the cell, not the virion, is the unit of metabolism". |
Total: 6 marks split AO1 = 2, AO2 = 2, AO3 = 2. This is a classic Section B "evaluate" question — Edexcel rewards candidates who weigh evidence on both sides and reach a defensible conclusion, not those who merely list features.
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