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One of the most fundamental functions of the cell membrane is to control the movement of substances into and out of the cell. The Edexcel A-Level Biology specification (9BI0) requires a thorough understanding of passive transport mechanisms — diffusion, facilitated diffusion and osmosis — including the factors that affect their rates and how to investigate them experimentally.
Diffusion is the net movement of molecules or ions from a region of higher concentration to a region of lower concentration, down a concentration gradient. It is a passive process, meaning it does not require metabolic energy (ATP).
Diffusion occurs because all molecules in a liquid or gas are in constant random motion due to their kinetic energy. Although individual molecules move randomly, the overall net movement is from high to low concentration until dynamic equilibrium is reached (where molecules continue to move, but there is no net movement in either direction).
Simple diffusion refers to the direct movement of small, non-polar molecules through the phospholipid bilayer. No membrane proteins are required.
Molecules that can diffuse directly through the bilayer include:
Molecules that cannot easily diffuse through the bilayer:
Exam Tip: When explaining why a substance can or cannot cross the membrane by simple diffusion, always refer to the hydrophobic core of the phospholipid bilayer. Polar and charged molecules are repelled by this hydrophobic region.
Facilitated diffusion is the passive movement of molecules or ions across the membrane through specific transport proteins. Like simple diffusion, it moves substances down their concentration gradient and requires no ATP.
There are two types of transport protein involved:
| Feature | Channel proteins | Carrier proteins |
|---|---|---|
| Mechanism | Form a pore/channel | Bind, change shape, release |
| Speed | Faster (up to millions of ions per second) | Slower (hundreds to thousands per second) |
| Specificity | Selective (based on size and charge of the channel) | Highly specific (complementary binding site) |
| Shape change | No | Yes |
| Substances transported | Ions, small polar molecules | Glucose, amino acids, larger polar molecules |
Exam Tip: Facilitated diffusion is still passive (no ATP required) and still moves substances down their concentration gradient. The only difference from simple diffusion is that it requires specific membrane proteins. Make this distinction clear in your answers.
Several factors influence how quickly substances diffuse across a membrane or through a medium. These can be remembered using Fick's Law of Diffusion:
Rate of diffusion∝thickness of membrane (diffusion distance)surface area×concentration difference
| Factor | Effect on rate of diffusion |
|---|---|
| Concentration gradient | The steeper (larger) the gradient, the faster the rate of diffusion. Cells maintain steep gradients by rapidly using up or converting substances that enter the cell |
| Surface area | The greater the surface area, the faster the rate. Exchange surfaces (e.g. alveoli, villi) are adapted to have large surface areas |
| Diffusion distance (membrane thickness) | The shorter the distance, the faster the rate. Exchange surfaces are adapted to be thin (e.g. alveolar epithelium is only one cell thick) |
| Temperature | Higher temperature = more kinetic energy = faster molecular movement = faster diffusion |
| Size of molecule | Smaller molecules diffuse faster than larger molecules |
| Polarity of molecule | Non-polar molecules diffuse through the phospholipid bilayer more easily than polar molecules |
| Number of transport proteins | For facilitated diffusion, more channel/carrier proteins = faster rate (until all proteins are saturated) |
An important difference between simple diffusion and facilitated diffusion is the concept of saturation:
This is a key graph you should be able to draw and explain.
Osmosis is the net movement of water molecules from a region of higher water potential to a region of lower (more negative) water potential, across a partially permeable membrane.
Water potential (symbol: ψ, the Greek letter psi) is a measure of the tendency of water molecules to move from one region to another. It is measured in kilopascals (kPa).
The water potential of a cell is determined by two components:
ψcell=ψs+ψp
Where:
Exam Tip: Always use the term water potential rather than "concentration" when describing osmosis. Describing osmosis as movement from "dilute to concentrated" may not receive full marks at A-Level. The correct terminology is "from higher water potential to lower (more negative) water potential".
Animal cells have no cell wall, so they are very sensitive to changes in the water potential of their surroundings:
| Solution type | Water potential relative to cell | Effect on animal cell | Term |
|---|---|---|---|
| Hypotonic (dilute) | Higher than the cell | Water enters by osmosis; cell swells and may burst (lysis) | Cytolysis |
| Isotonic | Equal to the cell | No net movement of water; cell maintains normal shape | — |
| Hypertonic (concentrated) | Lower than the cell | Water leaves by osmosis; cell shrinks | Crenation |
Red blood cells (erythrocytes) are commonly used to demonstrate osmosis because:
Plant cells have a rigid cell wall outside the cell membrane, which prevents the cell from bursting. This means they respond differently to changes in water potential:
| Solution type | Water potential relative to cell | Effect on plant cell | Term |
|---|---|---|---|
| Hypotonic (dilute, e.g. pure water) | Higher than the cell | Water enters by osmosis; cell swells; the cell membrane pushes against the cell wall; the cell becomes turgid | Turgor / Turgid |
| Isotonic | Equal to the cell | No net movement of water; cell is flaccid | Incipient plasmolysis |
| Hypertonic (concentrated) | Lower than the cell | Water leaves by osmosis; the cell membrane pulls away from the cell wall | Plasmolysis |
Turgor pressure is the pressure exerted by the cell contents against the cell wall. It is essential for plant support — when cells lose turgor, the plant wilts.
Plasmolysis occurs when so much water is lost that the cell membrane detaches from the cell wall. The point at which the membrane just begins to pull away is called incipient plasmolysis.
Exam Tip: In calculations involving water potential, remember that ψp is usually zero for animal cells and for plasmolysed plant cells. A fully turgid plant cell has ψcell=0 because ψp has become large enough to balance ψs.
The Edexcel specification includes a practical on investigating the water potential of plant tissue using osmosis (the potato or beetroot method).
Percentage change in mass=initial massfinal mass−initial mass×100
Plot a graph of percentage change in mass (y-axis) against sucrose concentration (x-axis). The point where the line crosses the x-axis gives the sucrose concentration equivalent to the water potential of the potato cells.
| Variable | Details |
|---|---|
| Independent | Concentration of sucrose solution |
| Dependent | Percentage change in mass of potato cylinders |
| Control variables | Size/dimensions of potato cylinders, volume of solution, temperature, time, same potato source |
The Edexcel 9BI0 specification places passive transport within Topic 2: Membranes, Proteins, DNA and Gene Expression, building directly on the fluid mosaic model of the previous lesson. Candidates must: define simple diffusion as the net movement of molecules or ions down a concentration gradient through the phospholipid bilayer; define facilitated diffusion as the passive movement of polar solutes through channel or carrier proteins; define osmosis as the net movement of water from a region of higher (less negative) water potential to a region of lower (more negative) water potential across a partially permeable membrane; apply Fick's law qualitatively (rate ∝ surface area × concentration difference / diffusion distance); and use the relation ψ=ψs+ψp to predict water movement between cells and surroundings. The same content is examined for both core practical literacy (the potato-cylinder serial-dilution practical) and synoptic application: forward to active and bulk transport (the next lesson), to Topic 5/7 (electron-transport metabolite movement across mitochondrial and chloroplast membranes), to Topic 7 (gas exchange and Fick's law applied to alveoli, gills and leaves) and to Topic 8 (kidney osmoregulation and plant root water uptake) — refer to the official Pearson Edexcel 9BI0 specification document for exact wording.
Question (8 marks):
A plant cell has a solute potential (ψs) of −800kPa and a pressure potential (ψp) of +300kPa. It is placed in a sucrose solution of water potential −400kPa.
(a) Calculate the water potential (ψ) of the cell. (2)
(b) State and explain the direction of net water movement. (3)
(c) Predict, with reasoning, what would happen to the cell if the bathing solution were replaced with one of water potential −700kPa. (3)
Solution with mark scheme:
(a) Step 1 — recall the relation. ψ=ψs+ψp.
M1 (AO1.2) — correct equation written and solute and pressure potentials correctly identified.
Step 2 — substitute and evaluate. ψ=(−800)+(+300)=−500kPa.
A1 (AO2.1) — correct numerical answer with sign and unit. Many candidates lose A1 by dropping the negative sign or by giving the answer as +500. The credited language is "the water potential is −500kPa, which is more negative than the bathing solution".
(b) M1 (AO2.1) — correct comparison: the bathing solution has ψ=−400kPa; the cell has ψ=−500kPa; the cell is more negative.
M1 (AO2.1) — correct direction: water moves by osmosis from the bathing solution (higher / less negative ψ) into the cell (lower / more negative ψ), through the partially permeable membrane.
A1 (AO3.2a) — explicit framing as net movement of water down a water-potential gradient, not of solute, and via aquaporins as well as the bilayer. A common pitfall is to write "water moves into the cell because the cell is more concentrated" — examiners credit the water-potential framing, not solute-concentration framing.
(c) Step 1 — compare the new bathing solution to the cell. Bathing ψ=−700kPa; cell ψ=−500kPa; the cell is now less negative.
M1 (AO3.1a) — correct prediction: water moves out of the cell by osmosis.
M1 (AO3.2a) — correct mechanism: the protoplast loses water and shrinks; the pressure potential falls towards zero; if water loss continues, the protoplast pulls away from the cell wall — incipient plasmolysis when ψp→0, then plasmolysis when the protoplast has detached.
A1 (AO3.2a) — full reasoning: as ψp falls, the cell's ψ becomes more negative, narrowing the gradient until equilibrium (ψcell=ψbath). A common pitfall is to state "the cell bursts" — animal cells lyse, plant cells plasmolyse because the cellulose wall prevents bursting.
Total: 8 marks.
Question (6 marks): Compare and contrast simple diffusion, facilitated diffusion and osmosis as mechanisms of passive transport across the cell-surface membrane.
Mark scheme decomposition by AO:
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