You are viewing a free preview of this lesson.
Subscribe to unlock all 10 lessons in this course and every other course on LearningBro.
Measuring biodiversity accurately is essential for monitoring ecosystems, assessing the impact of human activities, and making informed conservation decisions. In this lesson, we examine the practical techniques used to sample organisms and the mathematical index used to quantify species diversity.
Quantifying biodiversity allows scientists and conservationists to:
It is usually impossible to count every individual of every species in an area (a complete census). Instead, biologists take samples — collecting data from representative portions of the habitat and using these to estimate the overall biodiversity.
| Method | Description | Best For | Limitations |
|---|---|---|---|
| Quadrat | A square frame (typically 0.25 m² or 1 m²) placed on the ground; organisms within are identified and counted | Sessile (non-moving) organisms: plants, lichens, barnacles | Not suitable for mobile animals; size of quadrat must be appropriate for organism size |
| Point quadrat | A frame with pins that are lowered vertically; each species touched by a pin is recorded | Estimating percentage cover of plant species in grassland | Time-consuming; requires skill in species identification |
| Transect (belt) | Quadrats are placed at regular intervals along a line (tape measure) across a habitat | Studying how species distribution changes along an environmental gradient (e.g., from shore to inland) | Labour-intensive; may miss patchy distributions |
| Transect (line) | A tape measure is laid across the habitat; species touching the line are recorded at regular intervals | Quick survey of species distribution across a gradient | Less detailed than belt transect |
| Sweep net | A strong net swept through vegetation to catch invertebrates | Flying or vegetation-dwelling invertebrates | Catch depends on sweeping technique and speed; not quantitative |
| Pitfall trap | A container sunk into the ground with its rim level with the surface; organisms fall in and are trapped | Ground-dwelling invertebrates (beetles, spiders) | Catches depend on activity of organisms, not abundance; predation within trap |
| Kick sampling | The riverbed is disturbed by kicking while a net is held downstream to catch dislodged organisms | Freshwater invertebrates in streams and rivers | Semi-quantitative; depends on effort and technique |
| Light trap | A bright light source attracts nocturnal flying insects into a collecting chamber | Nocturnal flying insects (moths) | Biased towards species attracted to light; weather affects catches |
| Pooter | A small suction device used to collect individual small invertebrates by mouth | Small, individual invertebrates that need careful collection | Very time-consuming; only suitable for small numbers |
| Tullgren funnel | A sample of soil or leaf litter is placed on a mesh above a funnel, with a heat/light source above; organisms move away from heat and fall into a collecting jar | Soil and leaf-litter invertebrates | Only catches organisms that respond to heat/light gradient |
Exam Tip: You must be able to describe and evaluate specific sampling methods. Always discuss advantages and limitations, and explain why random sampling is essential to avoid bias.
This is a required practical for Edexcel A-Level Biology. You must be able to describe and explain this procedure in detail.
Random sampling is essential to ensure the data is unbiased. If the investigator chooses where to place quadrats, they might (consciously or unconsciously) select areas that are particularly species-rich or poor, giving a misleading picture of the habitat.
To estimate the total population of a species in an area using quadrat data:
Estimated population=mean number per quadrat×quadrat areatotal area
For example, if the mean number of daisy plants per 0.25 m² quadrat is 6, and the total field area is 500 m²:
Estimated population=6×0.25500=6×2000=12,000 daisies
For mobile animals, quadrats are impractical. The mark-release-recapture (Lincoln Index) method is used instead.
N=mM×n
Where:
A biologist captures 40 woodlice from a garden, marks them with a dot of paint, and releases them. The next day, 50 woodlice are captured, of which 8 are marked.
N=840×50=82000=250
The estimated population is 250 woodlice.
The method is only valid if several assumptions are met:
| Assumption | Explanation | If Violated |
|---|---|---|
| No births, deaths, immigration or emigration between sampling events | The population size must remain constant | Estimate will be inaccurate |
| Marked individuals mix randomly with the rest of the population | Ensures the recapture sample is representative | If marked individuals cluster together, the method is unreliable |
| Marks do not affect survival | Marking must not make individuals more visible to predators or cause harm | Marked individuals may die at higher rates, inflating the population estimate |
| Marks do not rub off or fade | All marked individuals must still be identifiable at recapture | Lost marks reduce m, inflating the estimate |
| Equal catchability | Marked and unmarked individuals must have an equal probability of being caught | If marked individuals become "trap-shy" or "trap-happy," the estimate is biased |
Exam Tip: Mark-release-recapture questions are very common. Always state the formula AND list the assumptions. If asked to evaluate the method, explain what happens if each assumption is violated.
Species richness alone does not fully capture biodiversity because it ignores relative abundance (evenness). A diversity index combines both richness and evenness into a single numerical value.
The Simpson's Index of Diversity is calculated as:
D=1−N(N−1)∑n(n−1)
Where:
A pond contains three species of invertebrate:
| Species | Number of Individuals (n) | n(n-1) |
|---|---|---|
| Mayfly larva | 15 | 15 × 14 = 210 |
| Freshwater shrimp | 10 | 10 × 9 = 90 |
| Caddisfly larva | 5 | 5 × 4 = 20 |
| Totals | N = 30 | Σn(n-1) = 320 |
D=1−30×29320=1−870320=1−0.368=0.632
The Simpson's Index of Diversity is 0.632, indicating moderate diversity.
By calculating D for different habitats, we can objectively compare their biodiversity. For example:
This comparison provides quantitative evidence that pollution reduces biodiversity.
Exam Tip: You MUST be able to calculate Simpson's Index of Diversity from raw data. Practise the calculation with different datasets. Show all your working in the exam — even if your final answer is wrong, you can earn method marks.
Biodiversity measurements can indicate habitat quality:
| Indicator | High Biodiversity | Low Biodiversity |
|---|---|---|
| Water quality | Clean, unpolluted water supports many species of invertebrate (mayfly, stonefly, caddisfly larvae) | Polluted water is dominated by few tolerant species (bloodworm, tubifex, rat-tailed maggot) |
| Air quality | Clean air supports many lichen species | Polluted air supports only a few tolerant lichens (or none) |
| Soil health | Healthy soil with high organic matter supports diverse invertebrate communities | Degraded soil with heavy metal contamination supports few species |
Indicator species are organisms that are particularly sensitive to environmental changes and whose presence or absence indicates specific conditions. For example:
| Source of Error | Solution |
|---|---|
| Non-random sampling | Use random number generator for coordinates |
| Too few samples | Increase the number of quadrats or recaptures |
| Identification errors | Use identification keys; train investigators |
| Seasonal variation | Sample at the same time of year for comparisons |
| Observer bias | Use standardised protocols; multiple observers |
| Disturbing the habitat | Use minimally invasive techniques |
| Key Concept | Detail |
|---|---|
| Sampling | Taking representative portions of a habitat to estimate biodiversity |
| Quadrats | For sessile organisms; placed randomly |
| Mark-release-recapture | For mobile animals; Lincoln Index: N = Mn/m |
| Simpson's Index (D) | D = 1 − Σn(n−1) / N(N−1); ranges 0 to 1; higher = more diverse |
| Species richness | Number of species only |
| Species diversity | Richness + evenness |
| Indicator species | Organisms whose presence indicates environmental conditions |
| Required practical | Random sampling with quadrats to investigate distribution and abundance |
Exam Tip: This lesson contains one of the most important required practicals. Be prepared to describe the full method, explain why random sampling is essential, calculate Simpson's Index, and evaluate the limitations of each technique.
The Edexcel 9BI0 specification places measurement of biodiversity within Topic 4: Biodiversity and Natural Resources, with synoptic overlap into the previous lesson on biodiversity and species richness (which defined biodiversity — this lesson operationalises the species level), the next lesson on natural selection and evolution (selection changes the abundance distribution Simpson's index summarises), Topic 5: On the Wild Side (succession and the biodiversity–stability relationship use the same quadrat / transect / Simpson tooling), Topic 7: Run for your Life (representative sampling reappears in the cardiac-output and respirometer practicals), and Paper 3: General and Practical Principles in Biology (sampling, statistical analysis and methodology evaluation are tested across topics). The relevant statements concern: random and systematic sampling using quadrats, point quadrats and transects; mark–release–recapture (Lincoln Index) for mobile organisms; calculating Simpson's D=1−∑(n/N)2; comparing biodiversity between habitats; and evaluating sources of error (refer to the official Pearson Edexcel 9BI0 specification document for exact wording).
Question (8 marks):
A field biologist surveys a 400m2 grassland for invertebrates using 0.25m2 random quadrats. The aggregated counts are:
| Species | Number of individuals (n) |
|---|---|
| Common ground beetle | 20 |
| Yellow meadow ant (workers) | 15 |
| Garden snail | 5 |
| Total | N = 40 |
(a) Calculate Simpson's index of diversity using the proportional form D=1−∑(n/N)2, showing working to three significant figures. (3)
(b) The same area is resurveyed five years later after intensive grazing. Richness drops to two species and Simpson's D falls to 0.18. Interpret these results and explain why D has fallen further than the richness loss alone would suggest. (3)
(c) Evaluate one design weakness of the original survey and one specific improvement. (2)
Solution with mark scheme:
(a) ∑(n/N)2=(20/40)2+(15/40)2+(5/40)2=0.250+0.141+0.0156=0.407, so D=1−0.407=0.593.
M1 (AO2.1) — proportions correct (0.500, 0.375, 0.125).
M1 (AO2.1) — squares and sums to 0.407.
A1 (AO2.1) — final answer D=0.593 to three significant figures.
(b) M1 (AO3.1a) — richness has fallen from three species to two, and Simpson's D from 0.593 to 0.18.
M1 (AO3.1a) — a fall in D of ∼0.41 is much larger than the loss of one species from three would suggest; it signals a combined loss of richness and evenness. D=0.18 implies ∑p2≈0.82, consistent with one species at roughly 90%.
A1 (AO3.2a) — Simpson's D is dominated by the most abundant species because its term in ∑p2 is squared. Grazing has not merely removed a species — it has re-engineered the dominance structure, and the index is sensitive to both effects.
(c) M1 (AO3.1a) — design weakness: a sample of forty individuals is small enough that rare-species detection is unreliable. The species–area relationship S=cAz predicts observed richness scales sublinearly with sampled area, so rare species are under-recorded at low effort.
M1 (AO3.2a) — matched improvement: increase quadrat number until a species–area accumulation curve plateaus (e.g., < 1 new species per 5 additional quadrats), and report a bootstrap confidence interval on D.
Total: 8 marks.
Question (6 marks): Describe how a researcher would use random quadrat sampling to estimate Simpson's index of diversity for plants in a 50×50m meadow, and evaluate the validity of conclusions drawn from a fixed sample size of ten quadrats.
Mark scheme decomposition by AO:
| Marking point | AO | Credit-worthy content |
|---|---|---|
| 1 | AO1.1 | States quadrats must be placed at coordinates from a random number generator — not "thrown over the shoulder" — to remove observer bias. |
| 2 | AO1.2 | Describes the protocol — place quadrat, identify every plant species inside, count individuals (or estimate percentage cover for mat-forming species), tally, repeat. |
| 3 | AO2.1 | Applies the calculation: aggregate counts across quadrats, compute n/N, square and sum to obtain ∑(n/N)2, then D=1−∑(n/N)2. |
| 4 | AO2.1 | Sample-size reasoning: ten quadrats is likely too few — plot running D against quadrat number and continue until the species–area accumulation curve plateaus. |
| 5 | AO3.1a | Evaluates: with ten quadrats, rare species are under-detected, observed D is biased low, and the CI on D is wide. Fixed-effort comparisons between meadows can be unreliable if richness is high. |
| 6 | AO3.2a | Concludes that valid inference requires standardised effort, a plateaued accumulation curve and a reported CI on D — not a single point estimate. |
Total: 6 marks split AO1 = 2, AO2 = 2, AO3 = 2. This is a typical Section B "describe and evaluate" question — Edexcel rewards candidates who describe the protocol (AO1) and justify the sample-size and confidence-interval moves (AO3) rather than merely listing equipment.
Subscribe to continue reading
Get full access to this lesson and all 10 lessons in this course.