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This lesson covers differentiation of parametric equations as required by the Edexcel A-Level Mathematics specification (9MA0). You need to be able to find dy/dx for curves defined parametrically and use it to find tangents and normals.
In parametric form, both x and y are expressed in terms of a third variable (the parameter), usually denoted t or θ.
x = f(t), y = g(t)
Each value of t gives a point (x, y) on the curve.
The parametric equations x = t², y = 2t describe a parabola (equivalent to x = y²/4 or y² = 4x).
| t | -2 | -1 | 0 | 1 | 2 |
|---|---|---|---|---|---|
| x = t² | 4 | 1 | 0 | 1 | 4 |
| y = 2t | -4 | -2 | 0 | 2 | 4 |
To find dy/dx for parametric equations, use:
dy/dx = (dy/dt) / (dx/dt)
provided dx/dt ≠ 0.
This follows from the chain rule: dy/dt = (dy/dx) × (dx/dt), so dy/dx = (dy/dt) / (dx/dt).
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