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Radians are the standard unit of angle measurement in A-Level Mathematics (9MA0). One radian is the angle subtended at the centre of a circle by an arc equal in length to the radius. Working in radians simplifies many formulae and is essential for calculus.
| Term | Meaning |
|---|---|
| Radian | The angle at the centre of a circle when arc length equals radius |
| Full turn | 2pi radians = 360 degrees |
| Half turn | pi radians = 180 degrees |
| Quarter turn | pi/2 radians = 90 degrees |
Degrees to radians: multiply by pi/180
Radians to degrees: multiply by 180/pi
| Degrees | Radians |
|---|---|
| 0 | 0 |
| 30 | pi/6 |
| 45 | pi/4 |
| 60 | pi/3 |
| 90 | pi/2 |
| 120 | 2pi/3 |
| 135 | 3pi/4 |
| 150 | 5pi/6 |
| 180 | pi |
| 270 | 3pi/2 |
| 360 | 2pi |
You should memorise these common values.
Convert 72 degrees to radians.
72 x pi/180 = 72pi/180 = 2pi/5 radians
Convert 5pi/12 radians to degrees.
5pi/12 x 180/pi = 5 x 180/12 = 900/12 = 75 degrees
For a sector with radius r and angle theta (in radians):
Arc length: s = r x theta
A sector has radius 8 cm and angle 1.2 radians. Find the arc length.
s = 8 x 1.2 = 9.6 cm
An arc of length 15 cm is part of a circle of radius 6 cm. Find the angle in radians.
theta = s/r = 15/6 = 2.5 radians
Area of sector: A = (1/2) x r² x theta
where theta is in radians.
Find the area of a sector with radius 10 cm and angle pi/3 radians.
A = (1/2) x 100 x pi/3 = 50pi/3 = 52.36 cm² (to 2 d.p.)
A sector has area 24 cm² and radius 6 cm. Find the angle in radians.
24 = (1/2) x 36 x theta
24 = 18 x theta
theta = 24/18 = 4/3 radians
A segment is the region between a chord and the arc.
Area of segment = Area of sector - Area of triangle
= (1/2)r²theta - (1/2)r²sin(theta)
= (1/2)r²(theta - sin(theta))
Find the area of a segment of a circle with radius 5 cm and central angle 1.4 radians.
Area = (1/2)(25)(1.4 - sin(1.4))
sin(1.4) = 0.9854...
Area = 12.5 x (1.4 - 0.9854) = 12.5 x 0.4146 = 5.18 cm² (to 2 d.p.)
You must know these exact values (they appear frequently without a calculator):
| Angle | sin | cos | tan |
|---|---|---|---|
| 0 | 0 | 1 | 0 |
| pi/6 (30) | 1/2 | sqrt(3)/2 | 1/sqrt(3) = sqrt(3)/3 |
| pi/4 (45) | sqrt(2)/2 | sqrt(2)/2 | 1 |
| pi/3 (60) | sqrt(3)/2 | 1/2 | sqrt(3) |
| pi/2 (90) | 1 | 0 | undefined |
45-45-90 triangle: sides 1, 1, sqrt(2)
30-60-90 triangle: sides 1, sqrt(3), 2
Find the exact perimeter of a sector with radius 4 cm and angle pi/3.
Arc length = 4 x pi/3 = 4pi/3
Perimeter = 2 x radius + arc = 8 + 4pi/3
Perimeter = 8 + 4pi/3 cm (exact)
| Tip | Detail |
|---|---|
| Radian mode | Make sure your calculator is in radian mode for all trig work at A-Level |
| Leave in exact form | Unless told otherwise, give answers involving pi as exact (e.g. 5pi/6, not 2.618) |
| Formula links | s = r x theta and A = (1/2)r²theta only work in radians |
| Segment formula | Remember: segment = sector minus triangle |
| Memorise exact values | These are tested frequently, especially on Paper 1 (no calculator) |