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This lesson covers cracking — the process of breaking long-chain hydrocarbons into shorter, more useful molecules — as required by the Edexcel GCSE Chemistry specification (1CH0). You need to know why cracking is necessary, the two main methods (thermal and catalytic), and how to write balanced equations for cracking reactions.
As you learned in previous lessons, fractional distillation of crude oil produces a mismatch between supply and demand:
Cracking solves this problem by converting long-chain hydrocarbons (for which there is low demand) into shorter-chain hydrocarbons (for which there is high demand), along with useful alkenes.
Cracking always produces a mixture of:
Exam Tip: Cracking always produces at least one alkene as well as shorter alkanes. If the question asks why cracking is useful, mention both fuels and feedstock for the petrochemical industry (making polymers).
Cracking is a thermal decomposition reaction — a large molecule is broken down into smaller molecules by heating. Covalent bonds within the long-chain hydrocarbon are broken.
long-chain alkane → shorter alkane + alkene(s)
There are two main methods of cracking:
| Feature | Detail |
|---|---|
| Temperature | Very high: 600–700 °C |
| Pressure | High pressure |
| Catalyst | None (heat alone provides the energy) |
| Products | Tends to produce a high proportion of alkenes |
Thermal cracking is used when the primary goal is to produce alkenes for making polymers and other chemicals.
| Feature | Detail |
|---|---|
| Temperature | High but slightly lower than thermal: approximately 500 °C |
| Pressure | Slight pressure (lower than thermal cracking) |
| Catalyst | Zeolite catalyst (an aluminosilicate with a honeycomb-like porous structure) |
| Products | Produces a mixture of alkanes and alkenes; more useful for making motor fuels |
The zeolite catalyst provides an alternative reaction pathway with a lower activation energy, allowing the reaction to occur at a lower temperature than thermal cracking.
Exam Tip: Know the key difference: thermal cracking uses high temperature and high pressure with no catalyst; catalytic cracking uses a zeolite catalyst at a slightly lower temperature. Both break long chains into shorter ones.
You need to be able to write and balance equations for cracking reactions.
Decane (C₁₀H₂₂) can be cracked into octane (C₈H₁₈) and ethene (C₂H₄):
C₁₀H₂₂ → C₈H₁₈ + C₂H₄
Word equation: decane → octane + ethene
Check: Left side: C = 10, H = 22. Right side: C = 8 + 2 = 10, H = 18 + 4 = 22. ✓ Balanced.
Decane can also be cracked in a different way:
C₁₀H₂₂ → C₃H₆ + C₂H₄ + C₅H₁₂
Word equation: decane → propene + ethene + pentane
Check: C = 3 + 2 + 5 = 10 ✓, H = 6 + 4 + 12 = 22 ✓
C₆H₁₄ → C₄H₁₀ + C₂H₄
Word equation: hexane → butane + ethene
C₁₂H₂₆ → C₂H₄ + C₁₀H₂₂
Word equation: dodecane → ethene + decane
Exam Tip: When balancing a cracking equation, count all the carbon atoms and hydrogen atoms on both sides. The total must be the same. Remember: cracking is not combustion — there is no oxygen involved.
The alkenes produced by cracking are extremely valuable to the chemical industry because they are reactive (due to their C=C double bond). They are used as the starting materials (monomers) for making:
Without cracking, the chemical industry would not have a sufficient supply of alkenes.
| Factor | Detail |
|---|---|
| Improves fuel supply | Converts surplus heavy fractions into petrol-range molecules |
| Provides feedstock | Produces alkenes for the polymer and chemical industries |
| Reduces waste | Less unwanted heavy oil is left over |
| Economic value | Short-chain fuels and alkenes are worth more than heavy oil |
Question: A hydrocarbon with the formula C₈H₁₈ is cracked. One product is ethene (C₂H₄). Write a balanced equation for this reaction and name the other product. [3 marks]
Step 1: Write what you know:
C₈H₁₈ → C₂H₄ + ?
Step 2: Work out the unknown product by subtracting:
Step 3: Identify the product — C₆H₁₄ is hexane (an alkane, since it fits CₙH₂ₙ₊₂ with n = 6).
Balanced equation: C₈H₁₈ → C₂H₄ + C₆H₁₄
Exam Tip: When a cracking equation gives you one product and asks for the other, just subtract the atoms. Then check whether the unknown product is an alkane (CₙH₂ₙ₊₂) or an alkene (CₙH₂ₙ) by applying the general formulae.
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