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This lesson explains the difference between scalar and vector quantities, including how to add vectors and find the resultant force, as required by the Edexcel GCSE Combined Science specification (1SC0). Understanding scalars and vectors is fundamental to describing motion and forces correctly.
A scalar quantity has magnitude (size) only. It does not have a direction.
| Scalar Quantity | SI Unit |
|---|---|
| Distance | m |
| Speed | m/s |
| Mass | kg |
| Time | s |
| Energy | J |
| Temperature | K or °C |
| Power | W |
A vector quantity has both magnitude and direction.
| Vector Quantity | SI Unit |
|---|---|
| Displacement | m |
| Velocity | m/s |
| Acceleration | m/s² |
| Force | N |
| Momentum | kg m/s |
| Weight | N |
Exam Tip: A common exam question asks you to classify quantities as scalar or vector. Remember: if direction matters, it is a vector. Key pairs to know are distance/displacement and speed/velocity.
A runner completes one full lap of a 400 m track, returning to the starting point.
A walker goes 3 km north then 4 km east.
Vectors are represented by arrows in diagrams:
graph LR
A["Start"] -- "8 N" --> B["End"]
A longer arrow means a larger force or velocity.
When two vectors act along the same line, you add or subtract them depending on direction.
If two forces act in the same direction, add them:
Fresultant=F1+F2
Example: 5 N right + 3 N right = 8 N right
If two forces act in opposite directions, subtract the smaller from the larger:
Fresultant=F1−F2
Example: 8 N right + 3 N left = 5 N right
A toy car has a driving force of 6 N forward and friction of 2 N backward. What is the resultant force?
Fresultant=6−2=4 N forward
Exam Tip: Always state both the magnitude and the direction when giving a resultant vector. Writing just "5 N" without a direction will cost you a mark.
When two vectors act at right angles, use Pythagoras' theorem to find the magnitude of the resultant:
R=F12+F22
A boat travels 30 m east then 40 m north. What is the magnitude of the resultant displacement?
R=302+402=900+1600=2500=50 m
graph TB
A["Start"] -- "30 m east" --> B["Turn"]
B -- "40 m north" --> C["End"]
A -. "R = 50 m" .-> C
You can also find the angle using trigonometry:
tanθ=3040=1.333... θ=tan−1(1.333)=53.1°
The resultant is 50 m at 53.1° north of east.
The resultant force is the single force that has the same effect as all the individual forces acting on an object combined.
Three forces act on an object: 10 N right, 4 N left, and 2 N left. Find the resultant.
Fresultant=10−4−2=4 N right
Exam Tip: When adding vectors at right angles, always draw a diagram first. Label the sides, then apply Pythagoras. This helps avoid sign errors and makes your working clear.
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