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This lesson explains what specific heat capacity means, introduces the equation linking energy, mass and temperature change, and works through several exam-style calculations. Specific heat capacity is a required equation for the Edexcel GCSE Combined Science specification (1SC0).
Different materials heat up at different rates. The property that quantifies this is specific heat capacity (SHC).
Specific heat capacity is the amount of energy required to raise the temperature of 1 kg of a substance by 1 °C (or 1 K).
E=mcΔθ
| Symbol | Quantity | Unit |
|---|---|---|
| E | Energy transferred | joules (J) |
| m | Mass | kilograms (kg) |
| c | Specific heat capacity | joules per kilogram per degree Celsius (J/kg °C) |
| Δθ | Temperature change | degrees Celsius (°C) or kelvin (K) |
Exam Tip: The symbol Δθ (delta-theta) means "change in temperature". You calculate it as: Δθ=final temperature−initial temperature.
| To find | Rearrangement |
|---|---|
| Energy | E=mcΔθ |
| Mass | m=cΔθE |
| Specific heat capacity | c=mΔθE |
| Temperature change | Δθ=mcE |
| Material | Specific Heat Capacity (J/kg °C) |
|---|---|
| Water | 4200 |
| Aluminium | 900 |
| Copper | 390 |
| Iron | 450 |
| Lead | 130 |
| Oil | 2100 |
| Concrete | 800 |
graph LR
A["Same energy input"] --> B["Water: small temp rise<br/>(high SHC)"]
A --> C["Copper: large temp rise<br/>(low SHC)"]
Exam Tip: If an exam question asks you to explain why water is used in heating systems or as a coolant, always state that water has a high specific heat capacity and then explain what this means (it can absorb or release a large amount of energy for a relatively small temperature change).
How much energy is needed to heat 2.0 kg of water from 20 °C to 100 °C? (SHC of water = 4200 J/kg °C)
Step 1 — Identify the values:
Step 2 — Substitute into the equation:
E=mcΔθ=2.0×4200×80=672000 J=672 kJ
A 0.5 kg block of copper is supplied with 15 600 J of energy. By how much does the temperature rise? (SHC of copper = 390 J/kg °C)
Δθ=mcE=0.5×39015600=19515600=80 °C
A student heats 0.3 kg of oil from 25 °C to 85 °C using an immersion heater that supplies 37 800 J. Calculate the specific heat capacity of the oil.
c=mΔθE=0.3×(85−25)37800=0.3×6037800=1837800=2100 J/kg °C
In this practical you measure the SHC of a metal block.
| Source of error | How to reduce it |
|---|---|
| Energy lost to the surroundings | Insulate the block with a lagging jacket |
| Poor thermal contact | Add a few drops of oil into the thermometer hole |
| Reading the thermometer at the wrong time | Stir (liquids) or wait for equilibrium; use a data logger for continuous readings |
Exam Tip: In the practical, the measured SHC is usually higher than the accepted value because some energy is lost to the surroundings. You should be able to explain this.
When an object is heated, energy is transferred from the thermal energy store of the heater (or flame) to the thermal energy store of the substance. The temperature rise depends on:
| Misconception | Correction |
|---|---|
| Temperature and energy are the same thing | Temperature measures the average kinetic energy of particles; energy is the total amount transferred |
| All materials heat up at the same rate for the same energy input | Materials with different SHC values heat up at different rates |
| A higher temperature means more energy stored | Not necessarily — a large mass of water at 30 °C stores more energy than a small mass of iron at 100 °C |
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