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This lesson covers Newton's three laws of motion — as required by the Edexcel GCSE Physics specification (1PH0), Topic 1: Key Concepts of Physics. You need to be able to state, explain, and apply each of the three laws to a variety of situations.
Newton's First Law: An object will remain stationary or continue to move at a constant velocity unless acted upon by a resultant force.
Inertia is the tendency of an object to resist a change in its state of motion. It is directly related to mass — the greater the mass, the greater the inertia, and the harder it is to change the object's motion.
Example 1: A book on a desk. The book is stationary. The weight (downward) and normal contact force (upward) are balanced. The resultant force is zero, so the book remains stationary.
Example 2: A hockey puck on ice. Once hit, the puck slides across the ice. If the ice were perfectly smooth (no friction), the puck would continue at constant velocity forever. In practice, a small friction force gradually slows it down.
Example 3: Passengers in a braking car. When a car brakes suddenly, the passengers continue to move forward (due to inertia) until a force (seatbelt) acts to decelerate them.
Exam Tip: Newton's First Law does NOT say "an object at rest stays at rest." It says an object remains at rest or at constant velocity. Many students forget the "constant velocity" part. An object moving at constant velocity has zero resultant force — this is a key concept.
Newton's Second Law: The acceleration of an object is directly proportional to the resultant force acting on it and inversely proportional to its mass.
This is expressed as the equation:
force = mass × acceleration
F=ma
Where:
Example 1: A resultant force of 600 N acts on a car of mass 1200 kg. Calculate the acceleration.
a = F ÷ m = 600 ÷ 1200 = 0.5 m/s²
Example 2: A 0.15 kg ball accelerates at 20 m/s². What is the resultant force?
F = ma = 0.15 × 20 = 3.0 N
Example 3: A force of 50 N accelerates an object at 2 m/s². What is the object's mass?
m = F ÷ a = 50 ÷ 2 = 25 kg
Example 4: A car of mass 1500 kg has a driving force of 4500 N and friction of 1500 N. Calculate the acceleration.
Step 1: Find the resultant force. Resultant = 4500 − 1500 = 3000 N
Step 2: Apply F = ma. a = F ÷ m = 3000 ÷ 1500 = 2.0 m/s²
Exam Tip: Always use the resultant force in F = ma, not just any single force. If there are multiple forces, calculate the resultant first. This is the most common error on exam questions about Newton's Second Law.
Newton's Third Law: When two objects interact, they exert equal and opposite forces on each other.
The two forces in a Newton's Third Law pair:
Example 1: A person standing on the floor.
Example 2: Earth and Moon.
Example 3: A swimmer pushing off a wall.
graph LR
A["Swimmer"] -- "Swimmer pushes wall →" --> B["Wall"]
B -- "← Wall pushes swimmer" --> A
style A fill:#2980b9,color:#fff
style B fill:#2c3e50,color:#fff
"If the forces are equal and opposite, don't they cancel out?"
No. Newton's Third Law pairs act on different objects, so they cannot cancel. Forces only cancel (balance) when they act on the same object.
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