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This lesson covers converging (convex) lenses as required by the Edexcel GCSE Physics specification (1PH0), Topic 5: Light and the Electromagnetic Spectrum. You need to understand focal point, focal length, how to draw ray diagrams, and how the position of the object determines the type of image formed.
A converging lens (also called a convex lens) is thicker in the middle than at the edges. It causes parallel rays of light to converge (come together) to a single point called the focal point (or principal focus).
| Term | Definition |
|---|---|
| Converging lens | A lens that is thicker in the middle; it brings parallel rays of light to a focus |
| Principal axis | The horizontal line passing through the centre of the lens |
| Focal point (F) | The point where parallel rays of light converge after passing through the lens |
| Focal length (f) | The distance from the centre of the lens to the focal point |
| 2F | A point at twice the focal length from the centre of the lens |
| Optical centre | The centre of the lens — rays passing through here are not deviated |
Exam Tip: There is a focal point on each side of the lens, both at the same distance from the centre. When drawing ray diagrams, you need to mark F and 2F on both sides of the lens.
When drawing ray diagrams for a converging lens, you should use at least two of these three standard rays:
The point where two (or more) of these rays meet on the far side of the lens is where the image is formed.
The type of image formed depends on where the object is placed relative to the focal point (F) and 2F.
| Property | Description |
|---|---|
| Image position | Between F and 2F on the other side |
| Image type | Real |
| Orientation | Inverted (upside down) |
| Size | Diminished (smaller than the object) |
| Application | Camera, the eye |
| Property | Description |
|---|---|
| Image position | At 2F on the other side |
| Image type | Real |
| Orientation | Inverted |
| Size | Same size as the object |
| Property | Description |
|---|---|
| Image position | Beyond 2F on the other side |
| Image type | Real |
| Orientation | Inverted |
| Size | Magnified (larger than the object) |
| Application | Projector |
| Property | Description |
|---|---|
| Image position | At infinity (rays are parallel after the lens) |
| Image type | No image formed |
| Use | Searchlight, spotlight beam |
| Property | Description |
|---|---|
| Image position | On the same side as the object (behind it) |
| Image type | Virtual |
| Orientation | Upright |
| Size | Magnified |
| Application | Magnifying glass |
flowchart TD
A["Object beyond 2F"] --> B["Image: between F and 2F<br/>Real, inverted, diminished"]
C["Object at 2F"] --> D["Image: at 2F<br/>Real, inverted, same size"]
E["Object between F and 2F"] --> F["Image: beyond 2F<br/>Real, inverted, magnified"]
G["Object at F"] --> H["No image formed<br/>Rays emerge parallel"]
I["Object between F and lens"] --> J["Image: same side as object<br/>Virtual, upright, magnified"]
style A fill:#2c3e50,color:#fff
style C fill:#2c3e50,color:#fff
style E fill:#2c3e50,color:#fff
style G fill:#2c3e50,color:#fff
style I fill:#2c3e50,color:#fff
style B fill:#3498db,color:#fff
style D fill:#3498db,color:#fff
style F fill:#3498db,color:#fff
style H fill:#e74c3c,color:#fff
style J fill:#27ae60,color:#fff
Exam Tip: Learn the mnemonic "Beyond 2F → diminished; Between F and 2F → magnified; Beyond F → virtual". When describing an image, always state three things: (1) real or virtual, (2) upright or inverted, (3) magnified, diminished, or same size.
Magnification tells you how much larger (or smaller) the image is compared to the object.
Magnification=object heightimage height
Magnification can also be calculated using distances:
Magnification=uv
Where:
An object is 3.0 cm tall and the image formed by a converging lens is 9.0 cm tall. Calculate the magnification.
Magnification=object heightimage height=3.09.0=3.0
The magnification is 3.0 — the image is 3 times larger than the object.
The power of a lens measures how strongly it converges (or diverges) light. It is related to the focal length.
Power=f1
Where:
A converging lens has a focal length of 20 cm. Calculate its power.
Step 1: Convert focal length to metres: f = 20 cm = 0.20 m
Step 2: Calculate power:
P=f1=0.201=+5.0 D
The power of the lens is +5.0 D.
Exam Tip: Remember to convert the focal length to metres before calculating power. A focal length of 25 cm = 0.25 m, not 25. Also, include the positive sign for converging lenses and the negative sign for diverging lenses.
| Application | Object Position | Image Type |
|---|---|---|
| Magnifying glass | Between F and the lens | Virtual, upright, magnified |
| Camera | Beyond 2F | Real, inverted, diminished |
| Projector | Between F and 2F | Real, inverted, magnified (projected onto screen) |
| The human eye | Beyond 2F | Real, inverted, diminished (on retina) |
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