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This lesson covers the turning effect of forces — known as moments — and how levers and gears act as force multipliers. This is part of the Edexcel GCSE Physics specification (1PH0), Topic 2: Motion and Forces. You need to be able to calculate moments, apply the principle of moments, and explain how levers and gears work.
A moment is the turning effect of a force about a pivot (also called a fulcrum). When you push a door handle, turn a spanner, or use a see-saw, you are applying a moment.
The moment of a force is calculated using:
Moment = Force × Perpendicular Distance from the Pivot
M = F × d
| Quantity | Symbol | Unit |
|---|---|---|
| Moment | M | Newton-metres (Nm) |
| Force | F | Newtons (N) |
| Perpendicular distance from pivot | d | Metres (m) |
Exam Tip: A very common mistake is using a distance that is not perpendicular to the force. Always check that the distance is measured at 90° to the line of action of the force. If the force is applied at an angle, you must use the perpendicular component.
A force of 20 N is applied at a perpendicular distance of 0.3 m from a pivot. Calculate the moment.
M = F × d = 20 × 0.3 = 6 Nm
A spanner is 0.25 m long. A mechanic applies a force of 40 N at the end. What moment is produced?
M = F × d = 40 × 0.25 = 10 Nm
A moment of 15 Nm is required to turn a bolt. If the spanner is 0.5 m long, what force must be applied?
F = M ÷ d = 15 ÷ 0.5 = 30 N
A moment of 12 Nm is produced by a 60 N force. At what distance from the pivot is the force applied?
d = M ÷ F = 12 ÷ 60 = 0.2 m
When an object is in rotational equilibrium (balanced and not rotating), the following rule applies:
The sum of the clockwise moments about any point = the sum of the anticlockwise moments about the same point.
This is known as the principle of moments.
flowchart LR
A["Anticlockwise<br/>Moments"] -- "=" --- B["Clockwise<br/>Moments"]
A --> C["F₁ × d₁"]
B --> D["F₂ × d₂"]
style A fill:#2980b9,color:#fff
style B fill:#c0392b,color:#fff
style C fill:#3498db,color:#fff
style D fill:#e74c3c,color:#fff
A child of weight 400 N sits 2 m from the pivot of a see-saw. Where must a child of weight 500 N sit on the other side for the see-saw to balance?
Anticlockwise moment = Clockwise moment
400 × 2 = 500 × d
800 = 500 × d
d = 800 ÷ 500 = 1.6 m from the pivot
A uniform beam is pivoted at its centre. On the left side, a 30 N weight hangs 0.4 m from the pivot. On the right side, a 10 N weight hangs 0.6 m from the pivot and an unknown weight W hangs 0.2 m from the pivot.
Anticlockwise moment = 30 × 0.4 = 12 Nm
Clockwise moments = (10 × 0.6) + (W × 0.2) = 6 + 0.2W
For balance: 12 = 6 + 0.2W
0.2W = 6
W = 6 ÷ 0.2 = 30 N
Exam Tip: The principle of moments can be applied about any point, not just the obvious pivot. Choosing a clever pivot point (where an unknown force acts) can simplify your calculation because that force creates zero moment about that point.
A lever is a simple machine that uses a rigid bar (or beam) and a pivot to multiply force.
| Class | Arrangement | Example |
|---|---|---|
| Class 1 | Pivot between effort and load | See-saw, crowbar, scissors |
| Class 2 | Load between pivot and effort | Wheelbarrow, nutcracker, bottle opener |
| Class 3 | Effort between pivot and load | Tweezers, fishing rod, tongs |
A crowbar is used to lift a rock. The pivot is 0.1 m from the rock (load) and 1.0 m from where you push (effort). If the rock weighs 500 N, what effort is needed?
Effort × 1.0 = 500 × 0.1
Effort = 50 ÷ 1.0 = 50 N
The crowbar multiplies the force by a factor of 10.
Gears are toothed wheels that interlock to transmit rotational forces (turning effects).
| Driving Gear | Driven Gear | Effect |
|---|---|---|
| Small gear (fewer teeth) | Large gear (more teeth) | Speed decreases, force (moment) increases |
| Large gear (more teeth) | Small gear (fewer teeth) | Speed increases, force (moment) decreases |
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