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This lesson covers flame emission spectroscopy in detail, as required by the AQA GCSE Chemistry specification (8.1.2). This is Higher Tier only content, indicated by [H]. Flame emission spectroscopy is an instrumental method used to identify metal ions and measure their concentrations. It is more accurate and sensitive than simple flame tests and is widely used in laboratories and industry.
Flame emission spectroscopy (FES) is an instrumental technique that analyses the light emitted by a sample when it is heated in a flame. Each element emits light at characteristic wavelengths, producing a unique line spectrum that acts like a "fingerprint" for that element.
| Feature | Simple Flame Test | Flame Emission Spectroscopy |
|---|---|---|
| What it measures | Flame colour observed by eye | Wavelengths of light measured by instrument |
| Accuracy | Low — relies on human colour judgement | High — precise wavelength measurements |
| Sensitivity | Can only detect high concentrations | Can detect very low concentrations (trace amounts) |
| Quantitative? | No — only qualitative (colour observed) | Yes — can measure concentration |
| Can identify mixtures? | Difficult — colours may overlap | Yes — each element has a unique line spectrum |
| Equipment needed | Bunsen burner, wire loop | Flame emission spectrometer (expensive) |
Exam Tip: A common exam question asks you to explain why flame emission spectroscopy is better than a simple flame test. The key points are: (1) it is more accurate because it measures specific wavelengths rather than relying on human colour judgement, (2) it can identify elements in mixtures because each element has a unique line spectrum, and (3) it can measure the concentration of an element, not just identify it.
graph TD
subgraph Energy_Levels["Electron Energy Levels"]
A["Higher Energy Level (excited state)"] -->|"Electron falls back, emits light at specific wavelength"| B["Lower Energy Level (ground state)"]
end
C["Heat energy from flame"] -->|"Electron absorbs energy and is promoted"| A
subgraph Outcome["Detection"]
D["Emitted light"] --> E["Spectrometer separates wavelengths"]
E --> F["Detector measures intensity"]
F --> G["Line spectrum produced"]
end
B --> D
style A fill:#e74c3c,color:#fff
style B fill:#3498db,color:#fff
style G fill:#27ae60,color:#fff
Each element has a different arrangement of electrons in different energy levels. Because the gaps between energy levels are unique to each element, the wavelengths of light emitted are also unique. This means:
Exam Tip: If asked why each element produces a unique line spectrum, explain that each element has a unique arrangement of electrons and energy levels, so the energy gaps between levels are different. Different energy gaps mean different wavelengths of light are emitted. This is a 3-mark answer that requires you to link electrons, energy levels, and wavelengths.
A line spectrum shows the specific wavelengths of light emitted by an element. Each line corresponds to a specific electron transition (from a higher to a lower energy level).
If the line spectrum of an unknown sample matches the known line spectrum of sodium, the sample contains sodium.
If the line spectrum shows lines matching two or more known elements, the sample is a mixture containing those elements.
You may be given a table of reference wavelengths:
| Element | Wavelength of Strongest Line (nm) |
|---|---|
| Lithium | 670.8 |
| Sodium | 589.0 |
| Potassium | 766.5 |
| Calcium | 422.7 |
| Barium | 553.6 |
| Strontium | 460.7 |
Example question: A sample produces lines at 589.0 nm and 422.7 nm. What elements are present?
Answer: The line at 589.0 nm matches sodium and the line at 422.7 nm matches calcium. Therefore, the sample contains sodium and calcium.
One of the most important advantages of flame emission spectroscopy over simple flame tests is that it can measure the concentration of a metal ion in solution. This is done using a calibration curve.
| Standard Solution Concentration (mg/L) | Light Intensity (arbitrary units) |
|---|---|
| 0 | 0 |
| 2 | 15 |
| 4 | 32 |
| 6 | 47 |
| 8 | 63 |
| 10 | 78 |
If the unknown sample gives a light intensity of 40, reading from the calibration curve gives a concentration of approximately 5.1 mg/L.
Exam Tip: Calibration curve questions are common on Higher Tier papers. You may be asked to plot the graph, draw a line of best fit, and read off a value for an unknown sample. Always use a ruler for the line of best fit, and show your working by drawing lines on the graph from the unknown's intensity to the x-axis. Remember to include units in your answer.
| Advantage | Explanation |
|---|---|
| More accurate than flame tests | Measures specific wavelengths, not subjective colours |
| Can identify mixtures | Each element has a unique line spectrum; multiple elements can be detected simultaneously |
| Quantitative | Can measure the concentration of an element using calibration curves |
| Sensitive | Can detect very low concentrations (parts per million or billion) |
| Fast | Results obtained in seconds |
| Reproducible | Machine measurements are consistent and repeatable |
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