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This lesson brings together all the Number topics from the AQA GCSE Mathematics specification. It provides exam-style practice questions with detailed solutions, highlights common mistakes, and offers strategies for tackling Number questions in the exam. Use this lesson as a revision tool to consolidate your understanding.
Number topics appear across both Paper 1 (non-calculator) and Papers 2 and 3 (calculator). They can appear as standalone questions or as parts of larger problems.
| Topic | Typical Marks | Papers |
|---|---|---|
| Place value and rounding | 1-3 | All |
| HCF and LCM | 3-4 | All |
| Fractions | 2-5 | Paper 1 especially |
| Percentages | 3-5 | All |
| Converting between forms | 2-4 | All |
| Indices | 2-4 | All |
| Surds [H] | 3-5 | All |
| Standard form | 2-4 | All |
| Bounds [H] | 3-5 | Papers 2, 3 |
Exam Tip: Number skills underpin many other topics. For example, you need fractions for probability, percentages for statistics, and indices for algebra. Mastering Number makes the whole exam easier.
Estimate the value of (19.7 x 4.13) / 0.489
Step 1: Round each number to 1 significant figure.
Step 2: Calculate.
Common mistake: Forgetting to show the rounded values. Even if your final answer is correct, you may lose marks if the examiner cannot see your rounding.
Using prime factorisation, find the HCF and LCM of 84 and 120.
Step 1: Prime factorise each number.
Step 2: Venn diagram.
| 84 only | Overlap | 120 only |
|---|---|---|
| 7 | 2, 2, 3 | 2, 5 |
Step 3: Calculate.
Check: 12 x 840 = 10,080. Also 84 x 120 = 10,080. Correct.
Calculate 2 and 3/4 divided by 1 and 1/6. Give your answer as a mixed number in its simplest form.
Step 1: Convert to improper fractions.
Step 2: Flip and multiply.
Step 3: Simplify.
Step 4: Convert to mixed number.
Answer: 2 and 5/14
Exam Tip: Always convert mixed numbers to improper fractions before dividing or multiplying. And always check whether your final fraction can be simplified.
A bicycle was bought for 340 pounds and sold for 289 pounds. Calculate the percentage loss.
Common mistake: Dividing by 289 (the selling price) instead of 340 (the original price). Always divide by the original.
After a 12% decrease in price, a television costs 440 pounds. What was the original price?
Step 1: The current price represents 88% of the original (100% - 12% = 88%).
Step 2: Original price = 440 / 0.88
Step 3: = 500 pounds
Check: 12% of 500 = 60. 500 - 60 = 440. Correct.
Show that 0.363636... = 4/11.
Let x = 0.363636...
100x = 36.363636...
100x - x = 36.363636... - 0.363636...
99x = 36
x = 36/99
Simplify: 36/99 = 4/11 (divide numerator and denominator by 9)
Evaluate 64 to the power (-2/3).
Step 1: Deal with the negative — take the reciprocal.
Step 2: Root first — cube root of 64 = 4.
Step 3: Then power — 4 squared = 16.
Step 4: Apply reciprocal — 1/16.
Answer: 1/16
Simplify (3 + root 5)(3 - root 5) + 2 root 20.
Step 1: Expand the brackets (difference of two squares).
Step 2: Simplify root 20.
Step 3: Calculate 2 root 20.
Step 4: Add results.
Answer: 4 + 4 root 5
Exam Tip: Look for the difference of two squares pattern in surd questions. It always eliminates the surd, leaving a rational number.
Calculate (4.2 x 10 to the power 5) x (3 x 10 to the power (-2)). Give your answer in standard form.
Step 1: Multiply the "a" values: 4.2 x 3 = 12.6
Step 2: Add the powers: 5 + (-2) = 3
Step 3: 12.6 x 10 cubed
Step 4: Adjust to standard form: 12.6 = 1.26 x 10
So: 1.26 x 10 x 10 cubed = 1.26 x 10 to the power 4
A runner completes a 100 m track (measured to the nearest metre) in 12.3 seconds (measured to the nearest 0.1 seconds). Calculate the upper and lower bounds of the runner's speed. State whether the runner could have been travelling faster than 8.2 m/s.
Step 1: Find bounds.
| Measurement | Lower Bound | Upper Bound |
|---|---|---|
| Distance | 99.5 m | 100.5 m |
| Time | 12.25 s | 12.35 s |
Step 2: Calculate speed bounds. (Speed = Distance / Time)
Step 3: Could the speed be more than 8.2 m/s?
The maximum possible speed is approximately 8.20 m/s. Since the upper bound exceeds 8.2, yes, the runner could have been travelling faster than 8.2 m/s.
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