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This lesson covers the use of Venn diagrams in probability, including set notation, as required by the AQA GCSE Mathematics specification. Venn diagrams are a powerful visual tool for organising data and calculating probabilities, especially when events overlap.
A Venn diagram uses overlapping circles inside a rectangle to represent sets (groups) and their relationships. The rectangle represents the universal set (all items being considered).
graph TD
subgraph Universal Set
subgraph Set A
A1[A only]
AB[A and B]
end
subgraph Set B
AB
B1[B only]
end
N[Neither A nor B]
end
Each region of the Venn diagram represents a different group:
| Region | Meaning |
|---|---|
| A only (not in B) | Items in set A but not in set B |
| B only (not in A) | Items in set B but not in set A |
| A and B (overlap) | Items in both set A and set B |
| Outside both circles | Items in neither set A nor set B |
The AQA specification requires you to understand and use set notation.
| Notation | Name | Meaning |
|---|---|---|
| A | Set A | The set of elements in A |
| A' | Complement of A | Everything not in A |
| A ∩ B | Intersection | Elements in both A and B |
| A ∪ B | Union | Elements in A or B or both |
| n(A) | Number in A | The number of elements in set A |
Exam Tip: Remember the symbols — the ∩ (intersection) looks like an "n" for "and" (both), and the ∪ (union) looks like a "u" for "united" (together). These symbols appear frequently in AQA exam questions.
In a class of 30 students:
Draw a Venn diagram and find how many study neither subject.
Step 1: Start with the overlap: both History and Geography = 7
Step 2: History only = 18 - 7 = 11
Step 3: Geography only = 15 - 7 = 8
Step 4: Neither = 30 - 11 - 7 - 8 = 4
| Region | Number |
|---|---|
| History only | 11 |
| Both | 7 |
| Geography only | 8 |
| Neither | 4 |
| Total | 30 |
Exam Tip: Always start filling in a Venn diagram from the intersection (the overlap in the middle). This prevents errors because the overlap is part of both sets. Then work outwards.
Once you have completed the Venn diagram, you can calculate probabilities by dividing the relevant count by the total.
Using the data from Worked Example 1 (30 students total):
(a) P(History) = n(History) / total = 18/30 = 3/5
(b) P(History and Geography) = P(H ∩ G) = 7/30
(c) P(History or Geography) = P(H ∪ G) = (11 + 7 + 8)/30 = 26/30 = 13/15
(d) P(neither) = 4/30 = 2/15
(e) P(not History) = P(H') = (8 + 4)/30 = 12/30 = 2/5
(f) P(Geography but not History) = 8/30 = 4/15
When events overlap, the addition rule needs adjusting:
P(A ∪ B) = P(A) + P(B) - P(A ∩ B)
We subtract the intersection to avoid counting it twice (once in A and once in B).
In a bag of 40 sweets, 22 are chocolate, 18 are toffee, and 6 are both chocolate and toffee.
P(chocolate or toffee) = P(C) + P(T) - P(C ∩ T) = 22/40 + 18/40 - 6/40 = 34/40 = 17/20
Exam Tip: If events are mutually exclusive (no overlap), then P(A ∩ B) = 0, and the formula simplifies to P(A ∪ B) = P(A) + P(B). This matches the addition rule from the earlier lesson.
Some questions involve three overlapping sets. The same principles apply, but there are more regions to fill in.
60 students were asked about the sports they play. The results were:
Fill in the Venn diagram step by step:
Step 1: All three = 3
Step 2: F and T only (not C) = 10 - 3 = 7
Step 3: F and C only (not T) = 8 - 3 = 5
Step 4: T and C only (not F) = 5 - 3 = 2
Step 5: F only = 30 - 7 - 3 - 5 = 15
Step 6: T only = 25 - 7 - 3 - 2 = 13
Step 7: C only = 20 - 5 - 3 - 2 = 10
Step 8: Neither = 60 - 15 - 7 - 5 - 3 - 13 - 2 - 10 = 5
| Region | Count |
|---|---|
| F only | 15 |
| T only | 13 |
| C only | 10 |
| F ∩ T only | 7 |
| F ∩ C only | 5 |
| T ∩ C only | 2 |
| F ∩ T ∩ C | 3 |
| Neither | 5 |
| Total | 60 |
P(plays exactly one sport) = (15 + 13 + 10)/60 = 38/60 = 19/30
P(plays at least two sports) = (7 + 5 + 2 + 3)/60 = 17/60
Sometimes the diagram is labelled with probabilities rather than counts.
Events A and B are such that P(A) = 0.4, P(B) = 0.5, and P(A ∩ B) = 0.15.
| Region | Probability |
|---|---|
| A only | 0.4 - 0.15 = 0.25 |
| A ∩ B | 0.15 |
| B only | 0.5 - 0.15 = 0.35 |
| Neither | 1 - 0.25 - 0.15 - 0.35 = 0.25 |
P(A ∪ B) = 0.25 + 0.15 + 0.35 = 0.75
P(A') = 1 - 0.4 = 0.6
P(A' ∩ B) = 0.35 (B only region)
Exam Tip: Whether a Venn diagram uses counts or probabilities, the method is the same. With probabilities, the regions should add up to 1. With counts, they add up to the total number.
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