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This is a Higher-tier only topic in the AQA GCSE Mathematics specification. Growth and decay extends the compound interest and depreciation work into more general contexts, including population growth, radioactive decay, and exponential change. You need to be able to use and interpret exponential formulae and solve problems in context.
Exponential growth occurs when a quantity increases by a fixed percentage in each time period. This is the same principle as compound interest, applied more broadly.
Final Value = Initial Value x (Multiplier) to the power of n
Where:
| Feature | Description |
|---|---|
| Shape of graph | Starts slowly, then curves steeply upward |
| Rate of increase | Gets faster and faster over time |
| Multiplier | Greater than 1 |
| Real-world examples | Population growth, bacterial growth, investment returns |
Worked Example 1: A colony of bacteria doubles every hour. Starting with 500 bacteria, how many will there be after 8 hours?
Worked Example 2: A town has a population of 25,000. The population grows at 3% per year. What will the population be after 10 years?
graph TD
A[Exponential Growth] --> B[Identify initial value]
B --> C[Determine the percentage increase]
C --> D[Calculate multiplier = 1 + rate/100]
D --> E[Apply: Value = Initial x multiplier to the power of n]
E --> F[Round appropriately for context]
Exam Tip: When a question says "the population grows by 3% each year", the multiplier is 1.03. When it says "the population doubles", the multiplier is 2. Read carefully to identify the correct multiplier.
Exponential decay occurs when a quantity decreases by a fixed percentage in each time period. This is the same principle as depreciation, applied to contexts like radioactive decay and cooling.
Final Value = Initial Value x (Multiplier) to the power of n
Where:
| Feature | Description |
|---|---|
| Shape of graph | Starts high, then curves downward, approaching zero but never reaching it |
| Rate of decrease | Gets slower and slower over time |
| Multiplier | Between 0 and 1 |
| Real-world examples | Radioactive decay, depreciation, cooling |
Worked Example 3: A radioactive substance has a mass of 400 g. It decays at a rate of 12% per hour. What mass remains after 6 hours?
Worked Example 4: The value of a painting decreases by 5% each year. It is currently worth 8,000 pounds. What will it be worth in 12 years?
The half-life is the time it takes for a quantity to reduce to half its original value. This concept is commonly used in radioactive decay problems.
Worked Example 5: A substance has a half-life of 3 hours. If you start with 1,200 g, how much remains after 12 hours?
Alternatively: 1,200 x (0.5) to the power of 4 = 1,200 x 0.0625 = 75 g
| Half-lives passed | Fraction remaining | Amount (starting with 1,200 g) |
|---|---|---|
| 0 | 1 | 1,200 |
| 1 | 1/2 | 600 |
| 2 | 1/4 | 300 |
| 3 | 1/8 | 150 |
| 4 | 1/16 | 75 |
| 5 | 1/32 | 37.5 |
Exam Tip: Half-life problems can be solved by repeatedly halving OR by using the formula with multiplier 0.5 raised to the power of (total time / half-life). The formula method is faster for large numbers of half-lives.
An exponential growth graph:
An exponential decay graph:
graph LR
A[Exponential Functions] --> B[Growth: multiplier > 1]
A --> C["Decay: 0 < multiplier < 1"]
B --> D[Curve goes up steeply]
C --> E[Curve approaches zero]
B --> F[Examples: population, bacteria]
C --> G[Examples: radioactive decay, cooling]
Worked Example 6: A population of 10,000 fish decreases by 8% per year due to pollution. After how many years will the population first fall below 6,000?
Use trial and improvement with multiplier = 0.92:
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