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This lesson covers histograms — a Higher tier topic on the AQA GCSE Mathematics specification. Unlike bar charts, histograms use frequency density on the vertical axis and can have bars of unequal width. Understanding how to draw, read, and interpret histograms is essential for the Higher paper.
| Feature | Bar Chart | Histogram |
|---|---|---|
| Vertical axis | Frequency | Frequency density |
| Bar width | All the same | Can vary (based on class width) |
| Gaps between bars | Yes (for discrete/categorical data) | No gaps |
| What represents the frequency | Height of the bar | Area of the bar |
| Data type | Discrete or categorical | Continuous |
The crucial difference is that in a histogram, the area of each bar represents the frequency, not the height.
Frequency density = frequency / class width
Or equivalently:
Frequency = frequency density x class width
The class width is the difference between the upper and lower boundaries of the class interval.
The table shows the ages of 50 people at a concert.
| Age (a years) | Class Width | Frequency | Frequency Density |
|---|---|---|---|
| 10 < a ≤ 20 | 10 | 8 | 8 / 10 = 0.8 |
| 20 < a ≤ 25 | 5 | 12 | 12 / 5 = 2.4 |
| 25 < a ≤ 30 | 5 | 15 | 15 / 5 = 3.0 |
| 30 < a ≤ 40 | 10 | 10 | 10 / 10 = 1.0 |
| 40 < a ≤ 60 | 20 | 5 | 5 / 20 = 0.25 |
Notice how the class widths are not all the same — this is why we must use frequency density rather than frequency on the vertical axis.
Exam Tip: Always calculate the class width first. For the class 20 < a ≤ 25, the class width is 25 - 20 = 5 (not 6 — do not count the endpoints, just subtract). A common mistake is getting the class width wrong, which leads to incorrect frequency densities.
To draw a histogram:
graph LR
A[Grouped Frequency Table] --> B[Calculate Class Widths]
B --> C[Calculate Frequency Density]
C --> D[Draw Bars]
D --> E[Width = Class Width]
D --> F[Height = Frequency Density]
D --> G[Area = Frequency]
Exam Tip: When drawing a histogram in the exam, use a ruler and be precise with widths and heights. The bars must start and end at the correct class boundaries. A bar from 20 to 25 must be exactly 5 units wide on the horizontal scale.
When given a histogram, you may need to find frequencies. Remember:
Frequency = frequency density x class width
This is the area of the bar.
A histogram shows the weights of parcels. One bar covers the interval 2 < w ≤ 5 and has a height (frequency density) of 4.
Class width = 5 - 2 = 3
Frequency = 4 x 3 = 12 parcels
A histogram shows the following:
| Weight (w kg) | Class Width | Frequency Density | Frequency |
|---|---|---|---|
| 0 < w ≤ 2 | 2 | 3 | 3 x 2 = 6 |
| 2 < w ≤ 5 | 3 | 4 | 4 x 3 = 12 |
| 5 < w ≤ 10 | 5 | 2.4 | 2.4 x 5 = 12 |
| 10 < w ≤ 20 | 10 | 1.2 | 1.2 x 10 = 12 |
| 20 < w ≤ 25 | 5 | 0.8 | 0.8 x 5 = 4 |
Total frequency = 6 + 12 + 12 + 12 + 4 = 46 parcels
Sometimes you are given a histogram with a missing bar and told the frequency for that class. You need to calculate the frequency density and draw the bar.
A histogram shows the times (t seconds) taken to run 100m. All bars are drawn except for the class 13 < t ≤ 14, which has a frequency of 9.
Class width = 14 - 13 = 1
Frequency density = 9 / 1 = 9
Draw a bar from 13 to 14 on the horizontal axis with a height of 9 on the frequency density axis.
Exam Tip: If a question gives you one frequency and asks you to complete a histogram, first use that frequency to work out the scale on the frequency density axis. Divide the frequency by the class width to get the frequency density, then check it matches the height of the corresponding bar. This lets you read the frequency densities of the other bars and calculate their frequencies.
Sometimes you need to estimate how many values fall within a range that does not match the class boundaries.
Using the weights table above, estimate the number of parcels weighing between 3 and 7 kg.
This range spans two classes:
From the class 2 < w ≤ 5 (frequency density = 4): The portion from 3 to 5 has width 2. Frequency = 4 x 2 = 8
From the class 5 < w ≤ 10 (frequency density = 2.4): The portion from 5 to 7 has width 2. Frequency = 2.4 x 2 = 4.8
Total estimate = 8 + 4.8 = 12.8 (approximately 13 parcels)
This is only an estimate because we assume the data is evenly spread within each class.
If given a histogram, you can reconstruct the frequency table:
A histogram has the following bars:
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