You are viewing a free preview of this lesson.
Subscribe to unlock all 10 lessons in this course and every other course on LearningBro.
This lesson covers power — the rate of energy transfer — and efficiency — the proportion of energy that is usefully transferred. Both are fundamental concepts in the AQA GCSE Physics specification (Section 4.1) and are tested with both calculation and explanation questions.
Power is the rate at which energy is transferred or the rate at which work is done. It tells you how quickly a device converts energy from one form to another.
An appliance with a high power rating transfers energy quickly. An appliance with a low power rating transfers energy slowly.
There are two key equations for power:
P = E / t
Where:
P = W / t
Where:
| Quantity | Symbol | Unit |
|---|---|---|
| Power | P | watts (W) |
| Energy transferred | E | joules (J) |
| Work done | W | joules (J) |
| Time | t | seconds (s) |
1 watt = 1 joule per second (1 W = 1 J/s)
For larger values:
Exam Tip: Power is energy transferred per second. If a question asks "how much energy is transferred in 5 minutes," remember to convert to seconds first (5 minutes = 300 seconds). This is a very common source of lost marks.
Example 1: A kettle transfers 460 000 J of energy in 200 seconds. Calculate its power.
P = E / t P = 460 000 / 200 P = 2300 W (or 2.3 kW)
Example 2: A 60 W light bulb is left on for 2 hours. How much energy does it transfer?
First convert time: 2 hours = 2 x 3600 = 7200 seconds
E = P x t E = 60 x 7200 E = 432 000 J (or 432 kJ)
Example 3: An electric motor has a power of 500 W. It does 15 000 J of useful work lifting a load. How long does this take?
t = E / P t = 15 000 / 500 t = 30 seconds
Exam Tip: You should be able to rearrange the power equation for E or t. Use the formula triangle if it helps: E is on top, P and t are on the bottom.
| Appliance | Typical Power Rating | Energy Transfer |
|---|---|---|
| LED light bulb | 10 W | Electrical to light and some internal energy |
| Filament light bulb | 60 W | Electrical to light and a lot of internal energy |
| Laptop | 50 W | Electrical to light, sound, and internal energy |
| Kettle | 2000-3000 W | Electrical to internal (thermal) energy of water |
| Electric shower | 7000-10 000 W | Electrical to internal (thermal) energy of water |
| Washing machine | 500-2000 W | Electrical to kinetic and internal energy |
A higher power rating means the appliance uses energy faster. This does not necessarily mean it wastes more energy — that depends on its efficiency.
Efficiency is a measure of how much of the input energy is usefully transferred. No device is 100% efficient because some energy is always dissipated (wasted).
Efficiency = useful output energy transfer / total input energy transfer
Efficiency = useful output power / total input power
Efficiency can be expressed as a decimal (e.g., 0.75) or as a percentage (e.g., 75%).
To convert from decimal to percentage: multiply by 100. To convert from percentage to decimal: divide by 100.
| Expression | Decimal | Percentage |
|---|---|---|
| 3/4 of energy is useful | 0.75 | 75% |
| 1/2 of energy is useful | 0.50 | 50% |
| 9/10 of energy is useful | 0.90 | 90% |
Exam Tip: Efficiency can NEVER be greater than 1 (or 100%). If your calculated efficiency is greater than 1, you have made an error — check that you used useful OUTPUT in the numerator and total INPUT in the denominator.
Example 1: A motor uses 500 J of electrical energy and does 400 J of useful work. Calculate its efficiency.
Efficiency = useful output / total input Efficiency = 400 / 500 Efficiency = 0.80 (or 80%)
Example 2: An LED bulb has an input power of 10 W and a useful light output of 8.5 W. Calculate its efficiency.
Efficiency = useful output power / total input power Efficiency = 8.5 / 10 Efficiency = 0.85 (or 85%)
Example 3: A car engine is 30% efficient. If it receives 50 000 J of chemical energy from fuel, how much useful kinetic energy is produced?
Useful output = efficiency x total input Useful output = 0.30 x 50 000 Useful output = 15 000 J
How much energy is wasted? Wasted = total input - useful output = 50 000 - 15 000 = 35 000 J
graph LR
A["Total input energy: 50 000 J (Chemical)"] --> B["Useful output: 15 000 J (Kinetic)"]
A --> C["Wasted: 35 000 J (Internal energy of engine, exhaust, friction)"]
style B fill:#aaffaa,stroke:#006600
style C fill:#ffcccc,stroke:#cc0000
A Sankey diagram is a visual representation of energy transfers. The width of each arrow is proportional to the amount of energy it represents.
| Feature | Meaning |
|---|---|
| Total width of input arrow | Total energy input |
| Width of useful output arrow | Useful energy transferred |
| Width of wasted arrow(s) | Wasted (dissipated) energy |
| Arrows drawn to scale | Widths are proportional to energy values |
For a light bulb with 100 J input, 10 J useful light, and 90 J wasted heat:
graph LR
A["100 J Electrical energy input"] --> B["10 J Light output (useful)"]
A --> C["90 J Internal energy (wasted)"]
style B fill:#aaffaa,stroke:#006600
style C fill:#ffcccc,stroke:#cc0000
From a Sankey diagram, you can calculate efficiency: Efficiency = useful output / total input = 10 / 100 = 0.10 (or 10%)
Exam Tip: When drawing Sankey diagrams, the arrows MUST be drawn to scale. If the total input is 200 J, the useful output is 150 J, and waste is 50 J, then the useful arrow should be three times wider than the waste arrow. Use a ruler and label all values.
Devices can be made more efficient by reducing wasted energy transfers.
Subscribe to continue reading
Get full access to this lesson and all 10 lessons in this course.