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This lesson covers the required practical investigation into the relationship between force and extension for a spring, as required by the AQA GCSE Physics specification (4.5.4). This practical demonstrates Hooke's law and is one of the most frequently tested required practicals in the GCSE Physics exam. You must know the method, equipment, variables, results analysis, and safety precautions in detail.
Hooke's law states that the extension of an elastic object (such as a spring) is directly proportional to the force applied to it, provided the limit of proportionality is not exceeded.
The equation for Hooke's law is:
F = k x e
Where:
The spring constant (k) tells you how stiff the spring is. A larger spring constant means the spring is stiffer and harder to stretch.
| Spring | Spring Constant (N/m) | Meaning |
|---|---|---|
| Soft spring | 10 | Easy to stretch |
| Medium spring | 50 | Moderate stiffness |
| Stiff spring | 200 | Hard to stretch |
Exam Tip: The equation F = k x e is on the AQA equation sheet, but you MUST be able to rearrange it. To find extension: e = F / k. To find the spring constant: k = F / e. Practise rearranging this equation until it is automatic.
| Term | Definition |
|---|---|
| Extension | The increase in length of the spring from its natural (unstretched) length |
| Natural length | The original length of the spring when no force is applied |
| Elastic deformation | The spring returns to its original shape when the force is removed |
| Inelastic (plastic) deformation | The spring is permanently stretched and does not return to its original length |
| Limit of proportionality | The point beyond which the extension is no longer proportional to the force |
| Elastic limit | The point beyond which the spring will not return to its original shape |
You will need the following equipment for this practical:
Follow these steps carefully:
Set up the equipment. Clamp the spring securely at the top using the clamp stand, boss, and clamp. Attach a pointer to the bottom of the spring. Place a ruler vertically beside the spring.
Measure the natural length. Record the position of the pointer on the ruler with no masses attached. This is the natural (unstretched) length of the spring.
Add the first mass. Hang a 100 g mass (weight = 1.0 N, using g = 10 N/kg) from the bottom of the spring. Allow the spring to come to rest (stop oscillating).
Record the new length. Read the position of the pointer on the ruler. Calculate the extension by subtracting the natural length from the new length.
Repeat with additional masses. Add masses one at a time (100 g increments), recording the new length and calculating the extension each time. Continue up to at least 6 or 7 different masses.
Record results in a table.
Repeat the entire experiment at least 3 times and calculate a mean extension for each force value.
Plot a graph of force (y-axis) against extension (x-axis).
graph TD
A["Clamp stand"] --> B["Clamp and boss"]
B --> C["Spring (attached at top)"]
C --> D["Pointer"]
D --> E["Hanging masses"]
F["Ruler (alongside spring)"] -.-> D
style A fill:#2c3e50,color:#fff
style C fill:#2980b9,color:#fff
style E fill:#e74c3c,color:#fff
style F fill:#27ae60,color:#fff
Exam Tip: In the exam, you may be asked to describe how to improve the accuracy of this experiment. Key answers include: use a pointer attached to the spring to reduce parallax error; take the reading at eye level; allow the spring to stop oscillating before reading; and repeat measurements to calculate a mean.
| Variable Type | Variable | Details |
|---|---|---|
| Independent variable | Force applied (weight of masses) | Changed by adding masses in equal increments |
| Dependent variable | Extension of the spring | Measured using a ruler |
| Control variables | Same spring, same starting position, same ruler, temperature | Must remain constant throughout the experiment |
Your results table should look like this:
| Mass (g) | Weight / Force (N) | Length (mm) | Extension (mm) | Extension Trial 1 (mm) | Extension Trial 2 (mm) | Extension Trial 3 (mm) | Mean Extension (mm) |
|---|---|---|---|---|---|---|---|
| 0 | 0.0 | 250 | 0 | 0 | 0 | 0 | 0 |
| 100 | 1.0 | 270 | 20 | 20 | 21 | 19 | 20 |
| 200 | 2.0 | 290 | 40 | 40 | 39 | 41 | 40 |
| 300 | 3.0 | 310 | 60 | 60 | 61 | 59 | 60 |
| 400 | 4.0 | 330 | 80 | 81 | 79 | 80 | 80 |
| 500 | 5.0 | 350 | 100 | 99 | 101 | 100 | 100 |
| 600 | 6.0 | 375 | 125 | 124 | 126 | 125 | 125 |
Exam Tip: Notice that the extension at 600 g (125 mm) is greater than expected if proportionality continued (it should be 120 mm). This suggests the spring may have passed the limit of proportionality. In the exam, you may be asked to identify this point from a graph or data table.
When you plot force (y-axis) against extension (x-axis):
graph LR
subgraph "Force vs Extension Graph"
A["Origin (0,0)"] -->|"Straight line: Hooke’s law obeyed"| B["Limit of proportionality"]
B -->|"Curve: Hooke’s law no longer obeyed"| C["Spring permanently deformed"]
end
style A fill:#27ae60,color:#fff
style B fill:#e67e22,color:#fff
style C fill:#e74c3c,color:#fff
The spring constant is the gradient of the straight-line section:
k = F / e
For example, if a force of 4.0 N produces an extension of 0.08 m:
k = 4.0 / 0.08 = 50 N/m
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