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This lesson covers solving quadratic and simultaneous equations, including the case of one linear and one quadratic, and representing inequality solutions on graphs.
Set equal to zero, factorise, then solve each factor.
x² − 7x + 10 = 0 → (x − 2)(x − 5) = 0 → x = 2 or x = 5
x = (−b ± √(b² − 4ac)) / 2a (see previous lesson).
Convert to (x + p)² = q form, then square root both sides (see previous lesson).
Look for a substitution. For x⁴ − 5x² + 4 = 0, let u = x²: u² − 5u + 4 = 0 → (u − 1)(u − 4) = 0 → u = 1 or u = 4 → x = ±1 or x = ±2
Example: 3x + 2y = 12 and 5x − 2y = 4 Add the equations: 8x = 16 → x = 2 → y = 3
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