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One of the most elegant applications of polar coordinates is computing the area enclosed by a polar curve. The formula differs from the Cartesian one and is a key part of the AQA Further Mathematics specification.
Consider a polar curve r = f(theta). A thin "sector" from angle theta to theta + delta theta has:
The area of this sector is approximately (1/2) r^2 delta theta (using the sector area formula).
Summing all such sectors and taking the limit:
A = (1/2) integral from alpha to beta of r^2 d theta
where alpha and beta are the angular limits.
Key Point: This gives the area swept by the radius vector from theta = alpha to theta = beta. It is the area between the curve and the pole.
Find the area enclosed by r = a.
Solution:
A = (1/2) integral from 0 to 2pi of a^2 d theta = (1/2) a^2 [theta] from 0 to 2pi = (1/2) a^2 (2pi) = pi a^2
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