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Success in A-Level Physics exams comes not only from understanding the physics but from knowing how marks are awarded. This lesson covers the structured approach to calculations, the equations you must know versus those provided, unit analysis, uncertainty and error propagation, graph skills, common mistakes, and the patterns examiners use in mark schemes.
Every calculation in A-Level Physics should follow this disciplined seven-step process:
flowchart TD
A["1. IDENTIFY the physics<br/>What principle or law applies?"] --> B["2. SELECT the equation<br/>From memory or data sheet"]
B --> C["3. LIST known values<br/>with correct units"]
C --> D["4. CONVERT units if needed<br/>(mm to m, mA to A, etc.)"]
D --> E["5. SUBSTITUTE and REARRANGE<br/>Show all working"]
E --> F["6. SOLVE and state the answer<br/>with correct units"]
F --> G["7. CHECK sig figs and<br/>reasonableness of answer"]
Question: A wire of length 1.80 m and diameter 0.56 mm has a resistance of 3.2 ohm. Calculate the resistivity of the wire.
Exam Tip: Examiners award marks at each stage. Even if your final answer is wrong, you can still earn marks for selecting the correct equation, converting units, and substituting correctly. ALWAYS show your working.
One of the most important revision tasks is knowing which equations are provided and which must be memorised. Here is the comprehensive breakdown:
Mechanics:
| Equation | Description |
|---|---|
| v = u + at | First SUVAT equation |
| s = ½(u + v)t | Second SUVAT equation |
| W = Fs cos theta | Work done by a force at angle theta |
| Ek = ½mv² | Kinetic energy |
| Ep = mgh | Gravitational potential energy (near surface) |
| P = W/t | Power |
| P = Fv | Power (force x velocity) |
| p = mv | Momentum |
| F = delta p / delta t | Force as rate of change of momentum |
| F = kx | Hooke's law |
| E_elastic = ½Fx = ½kx² | Elastic strain energy |
Electricity:
| Equation | Description |
|---|---|
| Q = It | Charge = current x time |
| V = IR | Ohm's law |
| P = IV = I²R = V²/R | Electrical power |
| V = W/Q | Potential difference |
| epsilon = I(R + r) | EMF equation |
| V_out = R_2/(R_1 + R_2) x V_in | Potential divider |
| R_series = R_1 + R_2 + ... | Resistors in series |
| 1/R_parallel = 1/R_1 + 1/R_2 + ... | Resistors in parallel |
Waves:
| Equation | Description |
|---|---|
| v = f lambda | Wave speed equation |
| n = c/v | Refractive index |
| n_1 sin theta_1 = n_2 sin theta_2 | Snell's law |
| lambda = ws/D | Double slit equation |
Particles and Radiation:
| Equation | Description |
|---|---|
| E = hf | Photon energy |
| hf = phi + Ek_max | Photoelectric equation |
| lambda = h/p = h/(mv) | de Broglie wavelength |
| E = mc² | Mass-energy equivalence |
Further Physics:
| Equation | Description |
|---|---|
| v = omega r | Linear speed from angular velocity |
| omega = 2pi/T = 2pi f | Angular frequency |
| a = -omega² x | SHM defining equation |
| E_total = ½m omega² A² | Total energy in SHM |
| C = Q/V | Capacitance |
| E = ½QV = ½CV² = ½Q²/C | Energy stored in a capacitor |
| pV = nRT | Ideal gas equation (amount in moles) |
These are given — but you must still know when and how to use them:
Exam Tip: Even though equations are given on the data sheet, you must practise using them. In the exam, you do not have time to figure out how to apply an unfamiliar equation. Know what every symbol means and how to rearrange.
Unit analysis is a powerful tool for checking answers and is explicitly tested in the AQA specification.
| Quantity | Unit | Symbol |
|---|---|---|
| Length | metre | m |
| Mass | kilogram | kg |
| Time | second | s |
| Electric current | ampere | A |
| Temperature | kelvin | K |
| Amount of substance | mole | mol |
| Luminous intensity | candela | cd |
To find the units of a quantity, substitute the units of the quantities on the right-hand side of its defining equation.
Example 1: Units of resistance
R = V/I. The volt is defined as J/C = kg m² s⁻³ A⁻¹. The ampere is A.
So R has units: (kg m² s⁻³ A⁻¹)/A = kg m² s⁻³ A⁻² = ohm
Example 2: Units of the spring constant k
F = kx, so k = F/x. Units: N/m = kg m s⁻² / m = kg s⁻²
Example 3: Show that the units of epsilon_0 are C² N⁻¹ m⁻² (or equivalently F m⁻¹)
From Coulomb's law: F = Q_1 Q_2 / (4pi epsilon_0 r²)
Rearranging: epsilon_0 = Q_1 Q_2 / (4pi F r²)
Units: C² / (N m²) = C² N⁻¹ m⁻²
Exam Tip: In unit analysis questions, always start from a defining equation and substitute units systematically. Show every step clearly.
Percentage uncertainty = (absolute uncertainty / measured value) x 100%
| Operation | Rule | Example |
|---|---|---|
| Addition or subtraction (a + b or a - b) | Add absolute uncertainties | If delta_a = 0.1 and delta_b = 0.2, then delta_(a+b) = 0.3 |
| Multiplication or division (a x b or a/b) | Add percentage uncertainties | If %a = 2% and %b = 3%, then %(a x b) = 5% |
| Power (a^n) | Multiply percentage uncertainty by n | If %a = 2% and you calculate a², then %uncertainty = 2 x 2% = 4% |
Given: R = 3.2 ± 0.1 ohm, L = 1.80 ± 0.01 m, d = 0.56 ± 0.02 mm
% uncertainty in R = (0.1/3.2) x 100 = 3.1% % uncertainty in L = (0.01/1.80) x 100 = 0.56% % uncertainty in d = (0.02/0.56) x 100 = 3.6%
Since A = pi(d/2)², and we use d²: % uncertainty in A = 2 x 3.6% = 7.1%
rho = RA/L, so: % uncertainty in rho = 3.1% + 7.1% + 0.56% = 10.8%
The absolute uncertainty in rho = 10.8% x 4.4 x 10⁻⁷ = 4.8 x 10⁻⁸ ohm m
So rho = (4.4 ± 0.5) x 10⁻⁷ ohm m
Exam Tip: The diameter is often the largest source of uncertainty in resistivity experiments because it is small and squared in the area calculation. This is a very common exam question.
| Skill | What to do |
|---|---|
| Plotting | Use more than half the grid, label axes with units, plot points accurately |
| Line of best fit | Draw a straight line or smooth curve that best represents the data trend |
| Gradient | Choose two points far apart on the line (not data points); calculate rise/run |
| Y-intercept | Read from the graph or calculate using y = mx + c |
| Error bars | Draw horizontal and/or vertical bars showing the uncertainty at each point |
| Worst line | Draw the steepest and shallowest lines that pass through the error bars; the range of gradients gives the uncertainty in the gradient |
Many A-Level physics relationships are not linear. To produce a straight-line graph (y = mx + c), you must manipulate the equation:
| Relationship | Equation | What to plot | Gradient | Y-intercept |
|---|---|---|---|---|
| y = kx² | y vs x² | y against x² | k | 0 |
| y = k/x | y vs 1/x | y against 1/x | k | 0 |
| y = k/x² | y vs 1/x² | y against 1/x² | k | 0 |
| y = ax^n | ln y = n ln x + ln a | ln y against ln x | n | ln a |
| y = ae^(bx) | ln y = bx + ln a | ln y against x | b | ln a |
| y = ae^(-bx) | ln y = -bx + ln a | ln y against x | -b | ln a |
When the relationship is exponential (e.g. radioactive decay, capacitor discharge), taking natural logs linearises the equation:
Example: V = V_0 e^(-t/RC)
Taking ln of both sides: ln V = ln V_0 - t/RC
This is in the form y = mx + c where:
Example: Finding n in I = k r^n (inverse square law test)
Taking ln: ln I = n ln r + ln k
Plot ln I against ln r — if n = -2, the relationship is an inverse square law.
Exam Tip: When drawing log plots, always label the axes as "ln V" not "V", and include the units in brackets if appropriate (e.g. ln(V/V) to make the argument dimensionless). Take care with significant figures when calculating ln values.
The y = mx + c form allows you to determine physical constants:
| Physical situation | Equation | Plot | What gradient gives |
|---|---|---|---|
| EMF/internal resistance | V = epsilon - Ir | V vs I | -r (negative gradient) |
| Resistivity | R = (rho/A)L | R vs L | rho/A |
| Free fall | h = ½gt² | h vs t² | ½g |
| SHM (spring) | T² = (4pi²/k)m | T² vs m | 4pi²/k |
| SHM (pendulum) | T² = (4pi²/g)L | T² vs L | 4pi²/g |
| Capacitor discharge | ln V = -(1/RC)t + ln V_0 | ln V vs t | -1/RC |
| Radioactive decay | ln N = -lambda t + ln N_0 | ln N vs t | -lambda |
| Common mistake | Correct conversion |
|---|---|
| Using mm instead of m | 1 mm = 1 x 10⁻³ m |
| Using cm instead of m | 1 cm = 1 x 10⁻² m |
| Using mA instead of A | 1 mA = 1 x 10⁻³ A |
| Using kOhm instead of Ohm | 1 kOhm = 1 x 10³ Ohm |
| Using MOhm instead of Ohm | 1 MOhm = 1 x 10⁶ Ohm |
| Using km instead of m | 1 km = 1 x 10³ m |
| Using degrees instead of radians | 180° = pi radians |
| Using °C instead of K | T(K) = T(°C) + 273.15 |
| Using cm² instead of m² | 1 cm² = 1 x 10⁻⁴ m² |
| Using eV instead of J | 1 eV = 1.60 x 10⁻¹⁹ J |
Exam Tip: ALWAYS convert to SI base units before substituting into equations. The most common unit error is forgetting to convert mm to m when calculating cross-sectional area — this is squared, so the error is magnified.
Rules for significant figures in A-Level Physics:
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