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The AQA A-Level Physics specification includes several required practicals related to waves. You must understand the experimental methods, be able to describe the apparatus, explain sources of uncertainty, and perform calculations from experimental data. These practicals are assessed in Paper 3 and the Practical Endorsement.
Spec mapping: This lesson consolidates AQA 7408 Required Practicals 3 (investigation into the variation of the frequency of stationary waves on a string with length, tension and mass per unit length, and resonance in standing waves in air columns) and 4 (interference effects using Young's double slit and a diffraction grating). It also covers the practical-skills strand: planning, hazard identification, uncertainty estimation, graphical analysis, and improvements to reduce systematic and random error. (Refer to the official AQA specification document for exact wording.)
Synoptic links:
- Section 3.3.1 (stationary waves): Required Practical 3 is the experimental partner of the stationary-waves theory lesson; the harmonic-frequency formula fₙ = nv/(2L) is the prediction tested.
- Section 3.3.2 (Young's double slits, gratings): Required Practical 4 is the experimental partner of the double-slit and grating lessons; the relations w = λD/s and d sin θ = nλ are the predictions tested.
- Section 3.1 (measurements and their errors): percentage uncertainty, combining uncertainties, identifying random vs systematic error, and constructing a graph with error bars are foundational skills examined here on Paper 3.
To measure the wavelength of laser light using a double slit interference pattern.
Worked Example 1 — A student measures across 12 bright fringes and obtains a distance of 42.0 mm. The slit separation is 0.40 mm and the screen distance is 2.80 m. Calculate the wavelength.
Number of fringe spacings = 12 − 1 = 11
w = 42.0/11 = 3.818 mm = 3.818 × 10⁻³ m
λ = ws/D = (3.818 × 10⁻³ × 4.0 × 10⁻⁴)/2.80
λ = (1.527 × 10⁻⁶)/2.80 = 5.45 × 10⁻⁷ m = 545 nm
This is consistent with green laser light.
To measure the wavelength of light using a diffraction grating of known line spacing.
Worked Example 2 — A grating with 300 lines per mm is used. The first-order maximum is observed at 10.2° from the central maximum. Calculate the wavelength.
d = 1/(300 × 10³) = 1/(3.00 × 10⁵) = 3.33 × 10⁻⁶ m
λ = d sin θ/n = (3.33 × 10⁻⁶ × sin 10.2°)/1
sin 10.2° = 0.1771
λ = 3.33 × 10⁻⁶ × 0.1771 = 5.90 × 10⁻⁷ m = 590 nm
This is consistent with the sodium yellow doublet.
Worked Example 3 — The same grating gives a second-order maximum at 21.0°. Calculate the wavelength and compare with the first-order result.
λ = d sin θ/n = (3.33 × 10⁻⁶ × sin 21.0°)/2
sin 21.0° = 0.3584
λ = (3.33 × 10⁻⁶ × 0.3584)/2 = (1.193 × 10⁻⁶)/2 = 5.97 × 10⁻⁷ m = 597 nm
Average of both measurements: (590 + 597)/2 = 594 nm
Using two orders improves the reliability of the result.
To determine the speed of sound in air using stationary waves.
Apparatus: Glass tube partially submerged in water, tuning fork of known frequency f.
λ/2 = L₂ − L₁, so λ = 2(L₂ − L₁)
Worked Example 4 — A tuning fork of frequency 512 Hz produces resonance in a tube at air column lengths of 16.0 cm and 49.2 cm. Calculate the speed of sound.
λ/2 = L₂ − L₁ = 49.2 − 16.0 = 33.2 cm = 0.332 m
λ = 2 × 0.332 = 0.664 m
v = fλ = 512 × 0.664 = 340 m s⁻¹
The first resonance occurs at approximately λ/4, but there is an "end correction" e at the open end (the antinode is slightly beyond the open end). By using the difference L₂ − L₁, the end correction cancels out:
L₁ = λ/4 + e L₂ = 3λ/4 + e L₂ − L₁ = 3λ/4 − λ/4 = λ/2 (the end correction e cancels)
Apparatus: Signal generator, loudspeaker, two microphones connected to a dual-trace oscilloscope.
This method avoids the end correction problem entirely.
To investigate the factors affecting the frequency of stationary waves on a string.
Keep tension T and mass per unit length μ constant. Vary L by changing the position of the bridge or pulley.
f₁ = v/(2L) → f₁ ∝ 1/L
A graph of f₁ vs 1/L should be a straight line through the origin with gradient v/2.
Keep L and μ constant. Vary T by changing the hanging mass.
f₁ = (1/2L)√(T/μ) → f₁ ∝ √T
A graph of f₁ vs √T should be a straight line through the origin.
Worked Example 5 — A string of length 0.80 m and mass per unit length 2.0 × 10⁻³ kg m⁻¹ is under a tension of 5.0 N. The string vibrates in its fundamental mode. Calculate the expected frequency.
v = √(T/μ) = √(5.0/(2.0 × 10⁻³)) = √(2500) = 50.0 m s⁻¹
f₁ = v/(2L) = 50.0/(2 × 0.80) = 50.0/1.60 = 31.3 Hz
Worked Example 6 — The same string is observed vibrating with 4 antinodes at a frequency of 125 Hz. Calculate the wave speed and verify consistency with the tension.
4 antinodes → 4th harmonic → λ₄ = 2L/4 = 2 × 0.80/4 = 0.40 m
v = fλ = 125 × 0.40 = 50.0 m s⁻¹ ✓
This matches the expected wave speed from v = √(T/μ), confirming the result.
Worked Example 7 — A student measures across 10 fringes as 35 ± 1 mm. Calculate the fringe spacing and its absolute uncertainty.
Number of spacings = 10 − 1 = 9
w = 35/9 = 3.89 mm
% uncertainty in total distance = (1/35) × 100% = 2.86%
Absolute uncertainty in w = 2.86% × 3.89 = 0.11 mm
w = 3.9 ± 0.1 mm
Exam Tip: In Paper 3 questions about required practicals, you must be able to describe the method clearly, identify key sources of uncertainty, and suggest improvements. Always link your improvements to specific sources of error.
For calculations involving multiple measured quantities, percentage uncertainties combine according to standard rules:
| Operation | Rule for combining uncertainties |
|---|---|
| Addition: z = a + b | Δz = Δa + Δb (absolute uncertainties add) |
| Subtraction: z = a − b | Δz = Δa + Δb (absolute uncertainties still add — worst case) |
| Multiplication: z = a × b | Δz/z = Δa/a + Δb/b (% uncertainties add) |
| Division: z = a/b | Δz/z = Δa/a + Δb/b (% uncertainties add) |
| Power: z = aⁿ | Δz/z = |
| Product/Quotient: z = aᵐ × bⁿ / cᵖ | Δz/z = |
g = 4π² × 0.800 / (1.795)² = (4π² × 0.800) / 3.222 = 31.58 / 3.222 = 9.80 m s⁻²
Percentage uncertainty in L: ΔL/L = 0.005/0.800 = 0.625%
Percentage uncertainty in T²: 2 × ΔT/T = 2 × (0.015/1.795) = 2 × 0.836% = 1.67%
Total percentage uncertainty in g: 0.625% + 1.67% = 2.30%
Absolute uncertainty in g: 0.023 × 9.80 = 0.23 m s⁻². So g = (9.80 ± 0.23) m s⁻², consistent with the accepted value of 9.81 m s⁻² to within the experimental uncertainty.
(a) λ = ws/D = (3.50 × 10⁻³)(0.30 × 10⁻³)/(1.50) = 7.00 × 10⁻⁷ m = 700 nm
% uncertainty in w: 0.05/3.50 = 1.43% % uncertainty in s: 0.02/0.30 = 6.67% ← dominant % uncertainty in D: 0.005/1.50 = 0.33%
Total: 8.43% → absolute uncertainty = 0.0843 × 700 = 59 nm
Final: λ = (700 ± 59) nm
(b) The slit separation s dominates at 6.67%. The single most effective improvement is to measure s directly using a calibrated travelling microscope (reducing Δs from ±0.02 mm to ±0.002 mm), which would drop the dominant percentage uncertainty from 6.67% to 0.67% — a tenfold improvement.
In practical-skills questions, the underlying physics often requires linearising a non-linear relation before plotting. A linear graph allows you to read the gradient as a known physical combination of measured quantities and verify the relation.
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