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The periodic table is divided into blocks based on the subshell being filled by the outermost (highest-energy) electrons. This classification explains many patterns in properties and behaviour. Understanding the blocks helps you predict an element's chemistry from its position in the table.
The block of an element is determined by the subshell that contains its highest-energy electron:
graph TD
A[Periodic Table Blocks] --> B[s-block: Groups 1-2]
A --> C[p-block: Groups 13-18]
A --> D[d-block: Groups 3-12]
A --> E[f-block: Lanthanides and Actinides]
B --> B1[Filling s subshell]
C --> C1[Filling p subshell]
D --> D1[Filling d subshell]
E --> E1[Filling f subshell]
| Block | Subshell Being Filled | Groups | Examples |
|---|---|---|---|
| s-block | s subshell | 1 and 2 (plus He) | Li, Be, Na, Mg, K, Ca |
| p-block | p subshell | 13-18 | B, C, N, O, F, Ne, Al, Si |
| d-block | d subshell | 3-12 | Sc, Ti, V, Cr, Mn, Fe, Co, Ni, Cu, Zn |
| f-block | f subshell | Lanthanides, Actinides | La, Ce, Pr... / Ac, Th, Pa... |
Note: Helium (1s2) is placed in Group 18 with the noble gases due to its chemical properties, but it is technically an s-block element by electron configuration.
The s-block elements have their outermost electron(s) in an s subshell.
Configuration pattern: [noble gas] ns1
Key properties:
Physical data for Group 1:
| Property | Li | Na | K | Rb | Cs |
|---|---|---|---|---|---|
| 1st IE (kJ/mol) | 520 | 496 | 419 | 403 | 376 |
| Melting point (degrees C) | 181 | 98 | 63 | 39 | 29 |
| Density (g/cm3) | 0.53 | 0.97 | 0.86 | 1.53 | 1.87 |
| Atomic radius (pm) | 152 | 186 | 227 | 248 | 265 |
Trend down the group: Reactivity increases because:
Configuration pattern: [noble gas] ns2
Key properties:
Trend down the group: Reactivity increases for the same reasons as Group 1.
| Element | Reaction with Cold Water |
|---|---|
| Beryllium | No reaction |
| Magnesium | Very slow (practically no reaction) |
| Calcium | Steady reaction, fizzes gently |
| Strontium | Vigorous reaction |
| Barium | Very vigorous reaction |
The p-block elements have their highest-energy electron in a p subshell (except helium).
This block contains a huge diversity of properties because it spans from metals (aluminium, tin, lead) through metalloids (silicon, germanium) to non-metals (carbon, nitrogen, oxygen, fluorine) and noble gases (neon, argon).
Configuration pattern: [noble gas] ns2 np5
Key properties:
| Property | F2 | Cl2 | Br2 | I2 |
|---|---|---|---|---|
| State at 25 degrees C | Pale yellow gas | Green-yellow gas | Brown liquid | Grey-black solid |
| Electronegativity | 4.0 | 3.2 | 3.0 | 2.7 |
| 1st EA (kJ/mol) | -328 | -349 | -325 | -295 |
| Bond energy (kJ/mol) | 158 | 242 | 193 | 151 |
The decrease in reactivity occurs because:
Note on fluorine: F2 has a surprisingly low bond energy (158 kJ/mol) compared to Cl2 (242 kJ/mol). This is because fluorine atoms are so small that the lone pairs on adjacent F atoms strongly repel each other in the F-F bond, weakening it. Despite this, fluorine is the most reactive halogen because its high electronegativity and small size make it extremely effective at attracting electrons from other atoms.
Configuration pattern: [noble gas] ns2 np6 (full outer shell)
Key properties:
| Noble Gas | He | Ne | Ar | Kr | Xe |
|---|---|---|---|---|---|
| Electrons | 2 | 10 | 18 | 36 | 54 |
| BP (degrees C) | -269 | -246 | -186 | -152 | -108 |
The d-block elements (transition metals) have their highest-energy electrons entering the 3d, 4d, or 5d subshells.
A transition metal is a d-block element that forms at least one ion with a partially filled d subshell.
This distinction is important:
| Element | Config | Common Ion | Ion Config | Transition Metal? |
|---|---|---|---|---|
| Scandium | [Ar] 4s2 3d1 | Sc3+ | [Ar] 3d0 | No (empty d) |
| Titanium | [Ar] 4s2 3d2 | Ti2+, Ti3+, Ti4+ | [Ar] 3d2, 3d1, 3d0 | Yes (Ti2+ and Ti3+ have partial d) |
| Iron | [Ar] 4s2 3d6 | Fe2+, Fe3+ | [Ar] 3d6, 3d5 | Yes (both have partial d) |
| Copper | [Ar] 4s1 3d10 | Cu+, Cu2+ | [Ar] 3d10, 3d9 | Yes (Cu2+ has partial d) |
| Zinc | [Ar] 4s2 3d10 | Zn2+ | [Ar] 3d10 | No (full d) |
So scandium and zinc are d-block elements but NOT transition metals by the strict definition.
| Element | Common Oxidation States | Example Compounds |
|---|---|---|
| Ti | +2, +3, +4 | TiCl4, TiO2 |
| V | +2, +3, +4, +5 | VO2+, V2O5 |
| Cr | +2, +3, +6 | CrCl3, K2Cr2O7 |
| Mn | +2, +4, +6, +7 | MnO2, KMnO4 |
| Fe | +2, +3 | FeSO4, FeCl3 |
| Cu | +1, +2 | Cu2O, CuSO4 |
| Ion | Colour | d-electrons |
|---|---|---|
| Ti3+ | Purple | 1 |
| V3+ | Green | 2 |
| Cr3+ | Green/violet | 3 |
| Mn2+ | Very pale pink | 5 |
| Fe2+ | Pale green | 6 |
| Fe3+ | Yellow/brown | 5 |
| Cu2+ | Blue | 9 |
Catalytic activity: both as elements (Fe in Haber process, Ni in hydrogenation) and as compounds (V2O5 in Contact process, MnO2 decomposing H2O2). Variable oxidation states allow transition metals to provide alternative reaction pathways with lower activation energies.
Complex ion formation: transition metal ions form coordination compounds with ligands (molecules or ions that donate lone pairs to the metal ion)
Relatively high melting points and densities (compared to s-block metals) due to strong metallic bonding involving d electrons
Elements that are diagonally adjacent in the periodic table sometimes show surprising chemical similarities. The two most important are:
graph TD
subgraph "Diagonal Relationships"
Li["Li"] --- Mg["Mg"]
Be["Be"] --- Al["Al"]
end
subgraph "Why?"
A["Moving RIGHT increases<br/>nuclear charge and<br/>polarising power"]
B["Moving DOWN increases<br/>atomic radius"]
C["Effects partially cancel,<br/>giving similar charge density"]
end
Why do diagonal relationships occur? Moving one element right increases nuclear charge (tending to decrease size and increase polarising power). Moving one element down increases atomic radius. These effects partially cancel, giving diagonal neighbours similar charge density and polarising power.
Misconception: "All d-block elements are transition metals."
Correction: Scandium and zinc are d-block elements but are NOT transition metals. A transition metal must form at least one stable ion with a partially filled d subshell. Sc3+ has an empty d subshell (3d0), and Zn2+ has a full d subshell (3d10), so neither qualifies.
Edexcel 9CH0 specification Topic 1, sub-topic 1.6 covers the classification of elements into s-, p-, d- and f-blocks based on the subshell of the highest-energy electron; the characteristic chemistry of each block (s-block: ionic compounds, +1/+2 ions, reactive metals; p-block: ranges from metallic to non-metallic, multiple oxidation states, covalent and ionic bonding; d-block: variable oxidation states, coloured compounds, catalytic activity; f-block: lanthanides and actinides, trivalent ions); and the use of block classification to predict element properties (refer to the official Pearson Edexcel specification document for exact wording). Examined principally in Paper 1 (Advanced Inorganic and Physical Chemistry) and re-examined in Topic 15 (Transition metals) and Topic 4 (Inorganic chemistry of group 1, 2, 7), where block classification underpins the structural framework.
Question (8 marks):
(a) Classify each of the following elements into s-, p-, d- or f-block, justifying your answer with the electron configuration of the highest-energy subshell: K (Z = 19), Br (Z = 35), Fe (Z = 26), Ce (Z = 58). (4) (b) Explain why d-block elements typically show variable oxidation states whereas s-block elements show only one or two characteristic oxidation states. (2) (c) Predict, with reasoning, whether the +3 oxidation state would be more accessible for Fe (a d-block element) or for Ca (an s-block element). (2)
Solution with mark scheme:
(a) B1 — K, Z = 19, [Ar] 4s¹ — highest-energy subshell is 4s → s-block.
B1 — Br, Z = 35, [Ar] 3d¹⁰ 4s² 4p⁵ — highest-energy subshell is 4p → p-block.
B1 — Fe, Z = 26, [Ar] 3d⁶ 4s² — highest-energy subshell is 3d (lower in energy than 4s in the cation, but the characterising subshell is 3d, since 4s² is also present in s-block elements). d-block.
B1 — Ce, Z = 58, [Xe] 4f¹ 5d¹ 6s² — highest-energy subshell includes 4f → f-block (lanthanide). Cerium is sometimes classed as d-block due to the 5d¹, but Edexcel and most periodic tables place it in f-block as the first lanthanide.
Common error: candidates classify Fe as s-block because of the 4s² in its configuration. The defining subshell for d-block is the 3d (or 4d, 5d depending on row), not the s. The presence of 4s² is shared with the alkali metals.
(b) B1 — d-block elements have similar energies for 3d and 4s subshells, and the differences between successive ionisation energies are small once the 4s electrons are removed. So removing 1, 2, 3 or more electrons from a d-block element produces stable cations of multiple oxidation states (e.g. Fe²⁺, Fe³⁺ both exist in aqueous solution).
B1 — s-block elements have a much larger gap between successive IEs once the valence shell is empty: removing the 1 (Group 1) or 2 (Group 2) outer electrons gives the noble gas configuration; further removal would require accessing the next shell at very high energy cost. Hence Group 1 shows only +1; Group 2 shows only +2.
(c) B1 — Fe³⁺ is readily accessible: Fe loses 4s² then one 3d electron to form [Ar] 3d⁵ — half-filled, stable. The third IE of Fe is moderate (~2957 kJ mol⁻¹).
B1 — Ca³⁺ is not accessible: Ca³⁺ would require breaking into the inner [Ar] core (3p⁶ → 3p⁵), at very high energy cost (>4910 kJ mol⁻¹ for IE3 of Ca). So Ca only forms Ca²⁺. The block determines the oxidation states accessible; the 3d subshell provides Fe with extra "stretching room" not available to Ca.
Total: 8 marks (B4 + B2 + B2).
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