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The transition metals occupy the central block of the periodic table, spanning Groups 3 to 12 in Period 4 (and further periods below). For Edexcel A-Level, the focus is on the first-row transition metals from scandium (Sc) to zinc (Zn), with particular attention to the elements titanium through copper.
The A-Level definition of a transition metal is precise and frequently tested:
A transition metal is a d-block element that forms at least one stable ion with an incomplete d sub-shell.
This definition is important because it excludes two d-block elements from the transition metal category:
All other first-row d-block elements (Ti, V, Cr, Mn, Fe, Co, Ni, Cu) form ions with partially filled d sub-shells and are therefore transition metals.
Common exam mistake: Writing "d-block element" when asked to define a transition metal. Not all d-block elements are transition metals. You must include the phrase "incomplete d sub-shell" in your definition.
The 3d and 4s sub-shells are very close in energy. In atoms, the 4s sub-shell fills before the 3d. The expected filling pattern is:
| Element | Symbol | Z | Electron Configuration | Notes |
|---|---|---|---|---|
| Scandium | Sc | 21 | [Ar] 3d¹ 4s² | |
| Titanium | Ti | 22 | [Ar] 3d² 4s² | |
| Vanadium | V | 23 | [Ar] 3d³ 4s² | |
| Chromium | Cr | 24 | [Ar] 3d⁵ 4s¹ | Anomalous |
| Manganese | Mn | 25 | [Ar] 3d⁵ 4s² | |
| Iron | Fe | 26 | [Ar] 3d⁶ 4s² | |
| Cobalt | Co | 27 | [Ar] 3d⁷ 4s² | |
| Nickel | Ni | 28 | [Ar] 3d⁸ 4s² | |
| Copper | Cu | 29 | [Ar] 3d¹⁰ 4s¹ | Anomalous |
| Zinc | Zn | 30 | [Ar] 3d¹⁰ 4s² |
Chromium has the configuration [Ar] 3d⁵ 4s¹ rather than the expected [Ar] 3d⁴ 4s². This is because a half-filled 3d sub-shell (3d⁵) is particularly stable due to the symmetrical distribution of electrons and exchange energy stabilisation.
Copper has the configuration [Ar] 3d¹⁰ 4s¹ rather than [Ar] 3d⁹ 4s². A completely filled 3d sub-shell (3d¹⁰) is also especially stable.
When transition metal atoms form positive ions, the 4s electrons are removed before the 3d electrons. This is because in the presence of d electrons, the 4s sub-shell is at slightly higher energy due to inter-electron repulsion effects.
For example:
Common exam mistake: Writing Fe²⁺ as [Ar] 3d⁴ 4s² instead of [Ar] 3d⁶. Students forget that 4s electrons are lost first, not 3d. This is one of the most common errors in transition metal questions.
One of the defining properties of transition metals is their ability to form ions with multiple stable oxidation states. This occurs because the 3d and 4s sub-shells are close in energy, so varying numbers of electrons can be removed without a prohibitive increase in ionisation energy.
| Element | Common Oxidation States | Example Compounds |
|---|---|---|
| Ti | +2, +3, +4 | TiO₂ (+4), TiCl₃ (+3) |
| V | +2, +3, +4, +5 | V₂O₅ (+5), VO²⁺ (+4), V³⁺ (+3), V²⁺ (+2) |
| Cr | +2, +3, +6 | Cr₂O₇²⁻ (+6), Cr³⁺ (+3) |
| Mn | +2, +4, +7 | MnO₄⁻ (+7), MnO₂ (+4), Mn²⁺ (+2) |
| Fe | +2, +3 | FeSO₄ (+2), FeCl₃ (+3) |
| Co | +2, +3 | CoCl₂ (+2), [Co(NH₃)₆]³⁺ (+3) |
| Ni | +2 | NiCl₂ (+2) |
| Cu | +1, +2 | Cu₂O (+1), CuSO₄ (+2) |
The maximum oxidation state for the early transition metals corresponds to the total number of 3d and 4s electrons (e.g., Mn can reach +7, corresponding to loss/sharing of all 3d⁵ 4s² electrons). Beyond manganese, the maximum oxidation state tends to decrease as the increasing nuclear charge makes it harder to remove additional electrons.
Vanadium is a favourite exam topic because of its four distinct coloured oxidation states in aqueous solution:
| Oxidation State | Species | Colour |
|---|---|---|
| +5 | VO₂⁺ | Yellow |
| +4 | VO²⁺ | Blue |
| +3 | V³⁺ | Green |
| +2 | V²⁺ | Violet/lavender |
These can be demonstrated by reducing an acidified solution of ammonium vanadate (NH₄VO₃) with zinc in acidic conditions: the solution progresses through yellow → blue → green → violet.
Most transition metal compounds are coloured. This is because the partially filled d sub-shell allows d-d electronic transitions when the ion is surrounded by ligands. The energy gap between split d orbitals corresponds to wavelengths in the visible spectrum.
| Ion | Colour in Aqueous Solution | d Electron Count |
|---|---|---|
| Ti³⁺ | Purple | 3d¹ |
| V²⁺ | Violet | 3d³ |
| Cr³⁺ | Green/violet | 3d³ |
| Mn²⁺ | Very pale pink | 3d⁵ |
| Fe²⁺ | Pale green | 3d⁶ |
| Fe³⁺ | Yellow/brown | 3d⁵ |
| Co²⁺ | Pink | 3d⁷ |
| Ni²⁺ | Green | 3d⁸ |
| Cu²⁺ | Blue | 3d⁹ |
Compounds of Sc³⁺ and Zn²⁺ are typically colourless because Sc³⁺ has no d electrons (3d⁰) and Zn²⁺ has a full d sub-shell (3d¹⁰) — in neither case is a d-d transition possible.
Transition metals and their compounds are widely used as catalysts. Their effectiveness is linked to:
Key examples:
Compared to Group 1 and Group 2 metals, transition metals generally have:
| Property | Na (Group 1) | Mg (Group 2) | Fe (Transition) |
|---|---|---|---|
| Melting point / °C | 98 | 650 | 1538 |
| Density / g cm⁻³ | 0.97 | 1.74 | 7.87 |
| Atomic radius / pm | 186 | 160 | 126 |
Transition metals are d-block elements that form at least one stable ion with an incomplete d sub-shell (excluding Sc and Zn). Their characteristic properties — variable oxidation states, coloured compounds, and catalytic activity — arise from their partially filled d orbitals. In ions, 4s electrons are always lost before 3d electrons. Learn the common ions and colours of each transition metal for the exam.
Edexcel 9CH0 specification Topic 15 — Transition Metals, sub-topic 15.1 covers the definition of a transition metal as a d-block element forming at least one ion with a partially filled d subshell, the typical properties (variable oxidation states, coloured ions, catalytic activity, complex ion formation), and the explicit exclusion of Sc and Zn (refer to the official specification document for exact wording). Examined in Paper 1 (9CH0/01) and Paper 3 (9CH0/03). Builds on Topic 1 (Atomic Structure) for d-orbital electron configurations and on Topic 8 (Redox I) for the variable-oxidation-state behaviour. Foundational for 15.2 (complex ions), 15.3 (colour), and 15.4 (catalysis).
Question (8 marks):
(a) Define a transition metal. Use this definition to explain why Cu is a transition metal but Zn is not, even though both are d-block elements. (4)
(b) Write the full electron configuration of Mn and predict, with reasoning, the most stable ionic oxidation state. State another commonly observed oxidation state and identify a familiar compound containing Mn in that state. (4)
Solution with mark scheme:
(a) Step 1 — definition.
A transition metal is a d-block element that forms at least one stable ion with an incomplete (partially filled) d subshell (1 ≤ d-electron count ≤ 9).
B1 — definition.
Step 2 — Cu vs Zn analysis.
Cu: [Ar] 3d¹⁰ 4s¹ as the atom; Cu²⁺ is [Ar] 3d⁹ — incomplete d subshell — therefore Cu is a transition metal. (Cu⁺ is [Ar] 3d¹⁰ — full — but the existence of Cu²⁺ with d⁹ qualifies Cu.)
M1 — Cu²⁺ d⁹ identified.
Zn: [Ar] 3d¹⁰ 4s² as the atom; Zn²⁺ is [Ar] 3d¹⁰ — full d subshell — therefore Zn is not a transition metal. Zn forms only one ion (Zn²⁺), and that ion has a completed 3d¹⁰ shell.
M1 — Zn²⁺ d¹⁰ identified, full subshell.
A1 — explicit linkage to definition (Zn fails the "partially filled" criterion).
(b) Step 1 — electron configuration of Mn.
Atomic number 25. Configuration: 1s² 2s² 2p⁶ 3s² 3p⁶ 3d⁵ 4s² (or [Ar] 3d⁵ 4s²).
B1 — full configuration.
Step 2 — most stable oxidation state.
Removal of the 4s² gives Mn²⁺: [Ar] 3d⁵ — half-filled d subshell, exchange-energy stabilised. Mn²⁺ is the most stable ionic state, found in MnSO₄, MnCl₂, etc.
M1 — Mn²⁺ identified as most stable, with reasoning (half-filled d⁵).
Step 3 — another common oxidation state.
Mn(VII) in MnO₄⁻ (purple permanganate); Mn²⁺ + 4O is shifted to Mn(+7) by removing all five 3d + two 4s electrons. Other common states: Mn(IV) in MnO₂, Mn(III) in Mn₂O₃.
A1 — Mn(VII) in KMnO₄ (or any other valid example with correct OS).
Total: 8 marks (M2 A2 B4).
Question (6 marks): The d-block of the periodic table contains the elements Sc to Zn in the first row.
(a) Explain why Sc is not classified as a transition metal even though it is a d-block element. (2)
(b) Predict and write the electron configurations of (i) Cr atom and (ii) Cr³⁺ ion. Explain any anomaly. (4)
Mark scheme decomposition by AO:
| Mark | AO | Awarded for |
|---|---|---|
| (a) M1 | AO1 | Sc has [Ar] 3d¹ 4s²; the only stable ion is Sc³⁺ |
| (a) A1 | AO2 | Sc³⁺ is [Ar] (3d⁰) — empty d subshell, fails "partially filled" criterion |
| (b)(i) B1 | AO1 | Cr atom: [Ar] 3d⁵ 4s¹ (not 3d⁴ 4s²) |
| (b)(i) M1 | AO2 | Anomalous configuration explained by exchange-energy stabilisation of half-filled d⁵ subshell |
| (b)(ii) B1 | AO1 | Cr³⁺: [Ar] 3d³ |
| (b)(ii) A1 | AO2 | When ionising, the 4s electron is removed first (4s is higher in energy than 3d once the d subshell starts filling) |
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