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Organic synthesis is the art and science of building target molecules from simpler starting materials through a planned sequence of reactions. At A-Level, you are expected to plan multi-step synthesis routes, choose appropriate reagents and conditions for each step, and understand the logic of retrosynthetic analysis.
In organic synthesis, you begin with a starting material (a simple, readily available compound) and transform it through a series of chemical reactions into a target molecule (the desired product). Each step in the sequence changes the functional group, the carbon skeleton, or both.
The challenge lies in choosing the right reactions in the right order, ensuring that each step is chemically feasible and that side reactions are minimised.
The core of A-Level synthesis planning is knowing which functional group can be converted into which other functional group, and what reagents and conditions are required for each conversion.
| Starting Group | Target Group | Reagent/Conditions |
|---|---|---|
| Alkene | Alcohol | Steam (H2O), H3PO4 catalyst, high T and P |
| Alkene | Halogenoalkane | HBr or HCl (gas) -- electrophilic addition |
| Alkene | Diol | Cold, dilute KMnO4 (alkaline) |
| Alkene | Dihalide | Br2 (in organic solvent) -- decolourises |
| Alkene | Polymer | High pressure, catalyst (addition polymerisation) |
| Starting Group | Target Group | Reagent/Conditions |
|---|---|---|
| Primary alcohol | Aldehyde | K2Cr2O7/H2SO4, distil immediately |
| Primary alcohol | Carboxylic acid | K2Cr2O7/H2SO4, heat under reflux |
| Secondary alcohol | Ketone | K2Cr2O7/H2SO4, heat under reflux |
| Alcohol | Halogenoalkane | NaBr + H2SO4, or SOCl2, or PCl5 |
| Alcohol | Alkene | Conc. H2SO4 or conc. H3PO4, heat (elimination) |
| Alcohol | Ester | Carboxylic acid + conc. H2SO4 catalyst, reflux |
Critical distinction: Distillation vs reflux for primary alcohol oxidation. This is one of the most commonly tested points. Distillation removes the aldehyde product as it forms, preventing further oxidation. Reflux keeps everything in the flask, allowing the aldehyde to be oxidised further to the carboxylic acid.
| Starting Group | Target Group | Reagent/Conditions |
|---|---|---|
| Halogenoalkane | Alcohol | NaOH(aq), heat under reflux |
| Halogenoalkane | Amine | Excess NH3, sealed tube, heat |
| Halogenoalkane | Nitrile | KCN in ethanol/water, heat under reflux |
| Halogenoalkane | Alkene | NaOH in ethanol, heat under reflux |
| Starting Group | Target Group | Reagent/Conditions |
|---|---|---|
| Aldehyde | Primary alcohol | NaBH4/H2O (reduction) |
| Ketone | Secondary alcohol | NaBH4/H2O (reduction) |
| Aldehyde | Carboxylic acid | K2Cr2O7/H2SO4, reflux |
| Aldehyde/Ketone | Hydroxynitrile | HCN + KCN (nucleophilic addition) |
| Nitrile | Carboxylic acid | Dilute acid or dilute NaOH, reflux (hydrolysis) |
| Nitrile | Primary amine | LiAlH4 in dry ether, then dilute acid |
| Carboxylic acid | Acyl chloride | SOCl2 or PCl5 |
| Carboxylic acid | Primary alcohol | LiAlH4 in dry ether |
| Carboxylic acid | Ester | ROH + conc. H2SO4, reflux |
| Acyl chloride | Ester | ROH, room temperature |
| Acyl chloride | Amide | RNH2 or NH3, room temperature |
flowchart TD
ALK[Alkene] -->|"Steam, H3PO4<br>high T and P"| ALC[Alcohol]
ALK -->|HBr| HAL[Halogenoalkane]
ALC -->|"K2Cr2O7/H2SO4<br>distil"| ALD[Aldehyde]
ALC -->|"K2Cr2O7/H2SO4<br>reflux"| CA[Carboxylic Acid]
ALC -->|"NaBr/H2SO4<br>or SOCl2"| HAL
ALC -->|"Conc. H2SO4<br>heat"| ALK
ALD -->|"K2Cr2O7/H2SO4<br>reflux"| CA
ALD -->|NaBH4, water| ALC
ALD -->|"HCN + KCN"| HN[Hydroxynitrile]
HAL -->|"NaOH(aq), reflux"| ALC
HAL -->|"KCN, reflux"| NIT[Nitrile +1C]
HAL -->|"Excess NH3<br>sealed tube"| AM[Amine]
HAL -->|"NaOH in ethanol<br>heat"| ALK
NIT -->|"Dilute acid, reflux"| CA2[Carboxylic Acid +1C]
NIT -->|"LiAlH4, dry ether"| AM2[Amine +1C]
CA -->|SOCl2| ACL[Acyl Chloride]
CA -->|"LiAlH4, dry ether"| ALC
ACL -->|ROH| EST[Ester]
ACL -->|"RNH2"| AMD[Amide]
Retrosynthetic analysis is a problem-solving strategy where you work backwards from the target molecule to the starting material. Instead of asking "what can I make from this starting material?", you ask "what could I make this target molecule from?"
In retrosynthesis notation, a special arrow (=>) is used pointing from target to precursor, indicating "can be made from."
Target: CH3CH2NH2 (ethylamine -- an amine) Starting material: CH3CH2OH (ethanol)
Retrosynthetic analysis:
Forward synthesis:
Target: CH3CH2COCl Starting material: CH3CH2CH2OH
Forward synthesis:
Target: CH3CH2COOH (propanoic acid, 3C) Starting material: CH3CH2Br (bromoethane, 2C)
The chain must grow by 1 carbon. The nitrile route achieves this:
Target: CH3COOC2H5 (ethyl ethanoate) Starting material: Ethanol (the only organic reagent)
You need both the acid component (ethanoic acid) and the alcohol component (ethanol):
Key insight: You must reserve some unreacted ethanol for step 3. If you oxidise all of it, you have no alcohol left to make the ester.
Standard route for introducing an amine group:
Controlled by distillation vs reflux:
Adds one carbon to the chain:
For efficient ester/amide formation:
Sometimes a molecule has two functional groups but you only want to react one of them. A protecting group is a temporary modification applied to one functional group to prevent it from reacting while you perform a transformation on the other group. After the desired reaction, the protecting group is removed to regenerate the original functional group.
If you have a molecule with both an -OH group and a C=C double bond, and you want to react only the C=C:
Protecting groups are essential in complex synthesis because many reagents are not selective enough to react with only one functional group in a polyfunctional molecule.
Confusing distillation and reflux conditions. Distillation = collect the aldehyde as it forms. Reflux = keep everything in the flask and get the carboxylic acid. This single word choice changes the product.
Forgetting to specify excess ammonia. Without "excess," you get a mixture of amines. Always write "excess ammonia, sealed tube, heat."
Using NaBH4 to reduce a carboxylic acid. NaBH4 is too mild. Use LiAlH4 in dry ether for carboxylic acids.
Mixing up aqueous and ethanolic NaOH. Aqueous NaOH + halogenoalkane = substitution (alcohol product). Ethanolic NaOH + halogenoalkane = elimination (alkene product). State the solvent.
Not accounting for all reagents needed. In the "ethanol to ethyl ethanoate" synthesis, students often forget that ethanol is needed as both the oxidation substrate AND the esterification alcohol. Reserve some.
Organic synthesis at A-Level requires you to memorise a toolkit of functional group interconversions and to apply retrosynthetic thinking. The key is to work backwards from the target, identify the functional group transformations needed, and then write the forward synthesis with specific reagents and conditions for each step. Mastery of synthesis routes is one of the most demanding but rewarding aspects of organic chemistry.
Edexcel 9CH0 specification, Topic 18 — Organic synthesis (synoptic across Topics 6–18) covers the design of multi-step synthetic routes from a given starting material to a target molecule, the use of functional group interconversions (FGI) with appropriate reagents and conditions, the consideration of selectivity (chemoselectivity, regioselectivity and stereoselectivity), the use of protecting groups at an introductory level, the recognition of chirality in synthesis (racemic vs enantiopure products) and the interpretation of synthesis problems involving aliphatic, aromatic and bifunctional substrates (refer to the official specification document for exact wording). Examined directly on Paper 2 with high-tariff multi-step questions and on Paper 3 (synoptic problem-solving). Connects to CP6 (distillation), CP7 (preparation of organic solid), CP14 (aspirin), CP15 (ester preparation) and CP16 (chromatographic identification).
Question (8 marks):
(a) Outline a 3-step synthesis of ethyl ethanoate (CH3COOCH2CH3) starting from ethanol (CH3CH2OH). Give reagents and conditions for each step. (4)
(b) Outline a 3-step synthesis of 4-aminobenzoic acid (NH2C6H4COOH) starting from methylbenzene (C6H5CH3). State the regioselectivity issues at each step. (4)
Solution with mark scheme:
(a) Step 1 — oxidise ethanol to ethanoic acid. Reflux with excess acidified potassium dichromate(VI) (K2Cr2O7 + dilute H2SO4). The strong oxidising conditions take the primary alcohol all the way to the carboxylic acid (not stopping at the aldehyde). Solution turns from orange to green.
M1 — correct reagents/conditions for oxidation to carboxylic acid (note: distillation of an aldehyde would require gentle heating; reflux ensures full oxidation to -COOH).
Step 2 — esterify ethanoic acid with a second portion of ethanol. Reflux with concentrated H2SO4 catalyst.
M1 — esterification step correctly identified.
Step 3 — purification. Distil off the ester (b.p. 77 °C); wash with aqueous Na2CO3 to remove residual acid; dry with anhydrous Na2SO4; redistil.
M1 A1 — purification step / overall product correctly identified as ethyl ethanoate.
(b) Step 1 — nitration of methylbenzene. Reagents: conc. HNO3 + conc. H2SO4 at 50–55 °C. The methyl group is 2,4-directing (alkyl groups donate electron density into the ring by hyperconjugation/+I), so the major product is 4-nitromethylbenzene (with some 2-isomer as minor product, separated by recrystallisation).
M1 — nitration with correct regioselectivity (4-position favoured by steric arguments over 2-position).
Step 2 — oxidation of methyl to carboxylic acid. Reagents: hot acidified KMnO4 (or hot K2Cr2O7), prolonged reflux. The alkyl side chain is oxidised to -COOH. Product: 4-nitrobenzoic acid.
M1 — oxidation step correctly identified.
Step 3 — reduction of -NO2 to -NH2. Reagents: Sn + concentrated HCl, reflux; then add NaOH to liberate the free amine. Product: 4-aminobenzoic acid (PABA).
M1 A1 — reduction step + final product correctly identified.
Total: 8 marks (M7 A1).
Question (8 marks): Suggest a synthesis of 2-aminopropanoic acid (alanine, CH3CH(NH2)COOH) from propanal (CH3CH2CHO).
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