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Knowing that a result must be tested for significance is one thing; knowing which test to run is another, and it is one of the most reliably examined skills in Edexcel Paper 3. The good news is that test selection is not a matter of memory or intuition — it is a mechanical decision fixed by just three features of the study: whether the hypothesis concerns a difference or a correlation, whether the design is independent (unrelated) or related, and the level of measurement of the data. Answer those three questions in order and the correct test drops out. Edexcel 9PS0 examines a specific set of five non-parametric tests — the sign test, Mann-Whitney U, Wilcoxon signed-rank, Spearman's rho and chi-square — and this lesson teaches you to select the right one from any described study, to state the criteria that justify each, and to compare a calculated value against a critical value to reach a conclusion. The formulae for chi-square and Spearman's rho are covered, and the decision logic is built into a table and a flowchart you can reproduce under exam conditions.
Key Definition: Statistical test selection is the process of choosing the correct inferential test for a study from three criteria — the type of hypothesis (difference vs correlation), the experimental design (independent vs related), and the level of measurement (nominal, ordinal or interval) — so that the analysis matches the data.
By the end of this lesson you will be able to:
Edexcel 9PS0 — Paper 3: Psychological Skills (Research Methods). This lesson develops the test-selection and test-application content assessed in Section A of Paper 3, where candidates are given a described study and asked to name and justify the appropriate statistical test, or to interpret a calculated value against a critical value. Our sequence teaches the three-question decision procedure first, then each test in turn, so the ordering reflects our teaching rationale rather than the specification's own.
| Our lesson covers | Edexcel 9PS0 research-methods area |
|---|---|
| The three test-choice criteria (hypothesis, design, level of data) | Factors affecting the choice of statistical test |
| Sign test; Mann-Whitney U; Wilcoxon signed-rank | Tests of difference |
| Spearman's rho | Test of correlation |
| Chi-square (χ2) | Test of association / difference in frequencies |
| Comparing calculated and critical values | Use of critical values in interpreting significance |
Assessment Objectives. These items are dominated by AO2 (applying the three criteria to a novel study to select and justify a test; reading a critical-values table; interpreting a calculated value) and AO3 (evaluating whether a chosen test is appropriate and what its result implies), on an AO1 base of accurate knowledge of each test and its conditions. This is application-heavy: a scenario-free "list of tests" answer scores poorly, and the justification — naming the design and level of data — is where most marks sit.
Connects to…
Every test-selection decision reduces to three questions, asked in this order.
The cell where your answers intersect names the test. Because all five Edexcel tests are non-parametric, interval data are treated using the ordinal tests (Mann-Whitney, Wilcoxon, Spearman) unless a question specifies otherwise — the rank-based tests are perfectly valid on interval data, they simply convert the scores to ranks first.
graph TD
A[What does the hypothesis test?] -->|Difference| B[What is the design?]
A -->|Correlation / association| C[Level of measurement?]
B -->|Independent groups<br/>UNRELATED| D[Level of measurement?]
B -->|Repeated measures / matched pairs<br/>RELATED| E[Level of measurement?]
D -->|Nominal| D1[Chi-square]
D -->|Ordinal / interval| D2[Mann-Whitney U]
E -->|Nominal| E1[Sign test]
E -->|Ordinal / interval| E2[Wilcoxon signed-rank]
C -->|Nominal| C0[Chi-square<br/>test of association]
C -->|Ordinal / interval| C1["Spearman's rho"]
| Nominal | Ordinal / Interval | |
|---|---|---|
| Difference — independent (unrelated) | Chi-square (χ2) | Mann-Whitney U |
| Difference — related (repeated measures / matched pairs) | Sign test | Wilcoxon signed-rank |
| Correlation / association | Chi-square (χ2) | Spearman's rho (rs) |
Working through the three questions in order makes the choice all but automatic. First, decide difference or correlation — this picks the row block. Second, for a difference, decide independent or related — this picks the row. Third, identify the level of measurement — this picks the column. Chi-square appears twice because it serves both as a test of difference between independent categories and as a test of association between two categorical variables; either way it requires nominal (frequency) data.
Exam Tip: This table is the single most-tested piece of methods knowledge on Paper 3. When you name a test, always justify it by stating all three criteria: "a Mann-Whitney U test, because the hypothesis predicts a difference, the design is independent groups (unrelated), and the data are ordinal." Naming the test alone rarely earns full marks — the justification is where the credit lies.
The surest way to master selection is to reason not only about the correct test but about why the others are wrong, because eliminating the near-misses forces you to check each criterion. Three short scenarios show the discipline.
Scenario 1. A researcher measures reaction time (in milliseconds) for the same 15 participants in a quiet room and again in a noisy room, predicting slower times in noise. Working the three questions: the hypothesis is a difference, the design is related (the same people in both conditions — repeated measures), and reaction time in ms is treated as ordinal for a non-parametric test. The correct test is therefore Wilcoxon signed-rank. Why not the others? Mann-Whitney is ruled out because the design is not independent (it is the same participants, not two separate groups); the sign test is a defensible but weaker choice that would throw away the magnitude of each change; Spearman is wrong because this is a difference, not a correlation; chi-square is wrong because the data are measured scores, not frequency counts in categories.
Scenario 2. A researcher records whether 80 people (40 dog-owners, 40 cat-owners) describe themselves as "introvert" or "extrovert", testing for an association between pet ownership and personality type. Here both variables are categorical (nominal — each person falls into a box), the groups are independent, and the prediction is an association, so the correct test is chi-square. Why not the others? Mann-Whitney, Wilcoxon and Spearman all require at least ordinal data and cannot be run on pure categories; the sign test needs a related design and a direction of change, neither of which is present. The give-away that points to chi-square is that the data are counts of people in categories rather than scores or ranks.
Scenario 3. A researcher ranks 12 students on both hours of sleep and concentration score, predicting that more sleep goes with better concentration. The hypothesis is a correlation and the data are ordinal (ranks), so the correct test is Spearman's rho. Why not the others? All three difference tests (sign, Mann-Whitney, Wilcoxon) are ruled out immediately because there is no manipulation and no comparison of conditions — there is a single group with two paired measures; chi-square is wrong because the data are ranks, not frequencies. Practising this "choose and eliminate" routine is what converts the decision table from something memorised into something understood.
Use the sign test when the hypothesis predicts a difference, the design is related, and the data are nominal — or can be reduced to the direction of change (better/worse, up/down) for each participant.
The sign test deliberately throws away information — it uses only the direction of each change, not its size, so a change of −5 counts the same as −1. This makes it easy to calculate but relatively insensitive, which is why the Wilcoxon test (below) is preferred when the magnitude of each change is available.
Use Mann-Whitney U when the hypothesis predicts a difference, the design is independent (unrelated), and the data are ordinal (or interval treated as ordinal).
Use Wilcoxon when the hypothesis predicts a difference, the design is related, and the data are ordinal (or interval treated as ordinal).
Wilcoxon is the more powerful relative of the sign test: both suit related designs, but Wilcoxon uses the magnitude of each change (via the ranks) rather than only its direction, so it extracts more from the same data.
Use Spearman's rho when the hypothesis predicts a correlation and the data are ordinal (or interval treated as ordinal).
The formula is
rs=1−n(n2−1)6∑d2
where d is the difference between the two ranks for each pair and n is the number of pairs. The result always lies in the range −1≤rs≤+1: a value near +1 indicates a strong positive relationship, near −1 a strong negative one, and near 0 little or no monotonic relationship.
Use chi-square when the data are nominal (frequency counts in independent categories) and the hypothesis predicts either a difference between those categories or an association between two categorical variables.
The formula is
χ2=∑E(O−E)2
where O is each observed frequency and E the corresponding expected frequency. The larger the gap between what is observed and what chance would predict, the larger χ2 becomes. Chi-square is entered into the critical-values table using degrees of freedom, not N: for a contingency table, df=(rows−1)×(columns−1), so a 2×2 table has df=1.
Exam Tip: The direction of the calculated-versus-critical comparison differs by test, and stating it wrongly loses the conclusion mark. For the sign test, Mann-Whitney (U) and Wilcoxon (T), the calculated value must be equal to or less than the critical value. For Spearman's rho and chi-square, it must be equal to or greater than the critical value. A handy memory aid: the correlation and association tests (rho, χ2) need to be bigger.
A researcher asks 100 people whether they prefer therapy A or B, and records their sex, predicting an association between sex and preference.
| Prefer A | Prefer B | Row total | |
|---|---|---|---|
| Male | 30 | 20 | 50 |
| Female | 20 | 30 | 50 |
| Column total | 50 | 50 | 100 |
First identify the test: the data are frequencies in categories (nominal), the groups are independent, and the prediction is an association — so chi-square is correct. The expected frequency for each cell, if there were no association, is E=grand totalrow total×column total. Every cell here expects 10050×50=25. Applying the formula, each of the four cells contributes 25(30−25)2=1 or 25(20−25)2=1, so χ2=1+1+1+1=4.0. With df=(2−1)(2−1)=1, the critical value at p≤0.05 (two-tailed) is 3.84. As the calculated value (4.0) exceeds the critical value (3.84), the result is significant: there is a significant association between sex and therapy preference.
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