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This lesson covers pressure, including pressure in solids and fluids (liquids and gases), upthrust and atmospheric pressure — as required by the Edexcel GCSE Physics specification (1PH0), Topic 2: Motion and Forces. You need to know the equations for pressure, understand how pressure varies with depth, and explain floating and sinking.
Pressure is the force applied per unit area. It describes how concentrated a force is — the smaller the area, the greater the pressure for the same force.
Pressure = Force ÷ Area
P = F / A
| Quantity | Symbol | Unit |
|---|---|---|
| Pressure | P | Pascals (Pa) |
| Force | F | Newtons (N) |
| Area | A | Square metres (m²) |
1 Pa = 1 N/m² — a pressure of one pascal means a force of one newton is spread over one square metre.
Exam Tip: Make sure you convert units correctly. Areas should be in m² — if given in cm², divide by 10,000 (since 1 m² = 10,000 cm²). This is a very common source of errors.
A box weighs 600 N and has a base area of 2 m². What pressure does it exert on the floor?
P = F / A = 600 / 2 = 300 Pa
A woman weighing 600 N stands in high-heeled shoes. The total area of both heels in contact with the ground is 0.0002 m². What pressure do the heels exert?
P = F / A = 600 / 0.0002 = 3,000,000 Pa (3 MPa)
This is much greater than the pressure from flat shoes (perhaps 30,000 Pa) — which explains why high heels can damage soft floors.
A hydraulic press needs to exert a pressure of 500,000 Pa. If the piston has an area of 0.04 m², what force is produced?
F = P × A = 500,000 × 0.04 = 20,000 N
Pressure in a liquid increases with depth and depends on the density of the liquid. The equation is:
Pressure = Density × Gravitational Field Strength × Height (depth)
P = ρ g h
| Quantity | Symbol | Unit |
|---|---|---|
| Pressure | P | Pascals (Pa) |
| Density | ρ (rho) | Kilograms per cubic metre (kg/m³) |
| Gravitational field strength | g | Newtons per kilogram (N/kg) — use 9.8 N/kg |
| Height (depth) of liquid | h | Metres (m) |
Calculate the pressure at a depth of 25 m in the sea. The density of seawater is 1025 kg/m³ and g = 9.8 N/kg.
P = ρgh = 1025 × 9.8 × 25 = 251,125 Pa ≈ 251 kPa
A diver descends to a depth where the water pressure is 196,000 Pa. The density of the water is 1000 kg/m³. What is the depth?
h = P / (ρg) = 196,000 / (1000 × 9.8) = 20 m
Exam Tip: Remember that P = ρgh gives the pressure due to the liquid only. The total pressure on a diver includes atmospheric pressure (about 101,325 Pa) plus the water pressure. Read the question carefully to see if it asks for total pressure or just the pressure from the liquid.
Atmospheric pressure is the pressure exerted by the weight of air in the Earth's atmosphere above us.
| Altitude | Atmospheric Pressure | Reason |
|---|---|---|
| Sea level | ~101 kPa | Maximum column of air above |
| Top of a mountain | ~70 kPa | Less air above, fewer collisions |
| Edge of atmosphere | ~0 kPa | Almost no air above |
graph TD
A["Atmospheric Pressure"] --> B["Caused by the weight<br/>of air above a surface"]
A --> C["Acts in all directions"]
A --> D["Decreases with<br/>increasing altitude"]
D --> E["Less air above<br/>= less weight<br/>= lower pressure"]
style A fill:#2c3e50,color:#fff
style B fill:#2980b9,color:#fff
style C fill:#27ae60,color:#fff
style D fill:#e67e22,color:#fff
style E fill:#c0392b,color:#fff
When an object is placed in a fluid (liquid or gas), the fluid exerts an upward force on the object called upthrust (or buoyant force).
The upthrust on an object is equal to the weight of fluid displaced by the object.
If an object displaces 0.5 m³ of water (density 1000 kg/m³):
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