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This lesson covers the forces acting on falling objects and the concept of terminal velocity — as required by the Edexcel GCSE Physics specification (1PH0), Topic 2: Motion and Forces. You need to understand how the balance between weight and air resistance changes as an object falls, and what determines the terminal velocity of different objects.
When an object falls through a fluid (such as air or water), two main forces act on it:
Exam Tip: Weight does not change as an object falls (at GCSE level). Only air resistance changes — it increases with speed. This distinction is essential for explaining terminal velocity.
flowchart TD
A["Object released<br/>from rest"] --> B["Stage 1: Weight >> Air Resistance<br/>Resultant force = large downward<br/>Object accelerates quickly"]
B --> C["Stage 2: Speed increases<br/>Air resistance increases<br/>Resultant force decreases<br/>Acceleration decreases"]
C --> D["Stage 3: Air Resistance = Weight<br/>Resultant force = 0<br/>Acceleration = 0<br/>TERMINAL VELOCITY reached"]
D --> E["Object continues at<br/>constant speed<br/>(terminal velocity)"]
style A fill:#2c3e50,color:#fff
style B fill:#c0392b,color:#fff
style C fill:#e67e22,color:#fff
style D fill:#27ae60,color:#fff
style E fill:#2980b9,color:#fff
Stage 1: Just after release
Stage 2: Gaining speed
Stage 3: Terminal velocity
Terminal velocity is the maximum constant velocity reached by an object falling through a fluid, when the drag force (air resistance) equals the weight of the object and the resultant force is zero.
Exam Tip: A very common exam mistake is to say that at terminal velocity "the forces are balanced so the object stops." The object does NOT stop — it continues at constant speed. Balanced forces mean no acceleration, not no movement.
The parachutist is the classic example used in the Edexcel specification. It involves two terminal velocities — one before the parachute opens and one after.
| Stage | What Happens | Forces | Resultant | Velocity |
|---|---|---|---|---|
| 1. Jumps from aircraft | Leaves the plane | W >> R (speed is low) | Large downward | Increasing rapidly |
| 2. Falling faster | Speed builds up | W > R (R increasing) | Decreasing downward | Still increasing, but less rapidly |
| 3. First terminal velocity | Air resistance = weight | W = R | Zero | Constant (~55 m/s) |
| 4. Parachute opens | Large surface area suddenly increases R | R >> W | Large upward | Decreasing rapidly |
| 5. Slowing down | Speed decreases, so R decreases | R > W (R decreasing) | Decreasing upward | Still decreasing, but less rapidly |
| 6. Second terminal velocity | R decreases back to equal W | W = R | Zero | Constant (~5 m/s) |
| 7. Landing | Hits the ground | Normal force acts upward | Upward (deceleration) | Reaches zero |
Exam Tip: The parachutist question appears very frequently in Edexcel Physics exams. Make sure you can describe all stages, referring to the forces at each point and whether the parachutist is accelerating, decelerating or at constant velocity.
The velocity-time graph for a parachutist has a distinctive shape:
The terminal velocity of an object depends on several factors:
| Factor | Effect on Terminal Velocity | Explanation |
|---|---|---|
| Greater mass/weight | Higher terminal velocity | A heavier object needs more air resistance to balance its weight, which requires a higher speed |
| Larger surface area | Lower terminal velocity | A larger area creates more air resistance at any given speed, so balance is reached at a lower speed |
| Streamlined shape | Higher terminal velocity | A streamlined shape experiences less drag, so a higher speed is needed to generate enough drag |
| Denser fluid | Lower terminal velocity | A denser fluid (e.g. water vs air) creates more drag at any given speed |
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