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At GCSE you extend trigonometry beyond right-angled triangles to cover the sine rule, cosine rule, the formula for the area of a triangle, exact trigonometric values, and applications in 3D and bearings.
Memorise these exact values (from equilateral and right isosceles triangles):
| Angle | sin | cos | tan |
|---|---|---|---|
| 0° | 0 | 1 | 0 |
| 30° | 1/2 | √3/2 | 1/√3 = √3/3 |
| 45° | 1/√2 = √2/2 | 1/√2 = √2/2 | 1 |
| 60° | √3/2 | 1/2 | √3 |
| 90° | 1 | 0 | undefined |
Example: Find the exact value of sin 30° × tan 60°. = (1/2) × √3 = √3/2
sin θ = opposite/hypotenuse; cos θ = adjacent/hypotenuse; tan θ = opposite/adjacent
For any triangle with sides a, b, c opposite to angles A, B, C:
a/sin A = b/sin B = c/sin C
(Or inverted: sin A/a = sin B/b = sin C/c — use this form when finding an angle.)
Finding a side: Example: B = 73°, C = 41°, b = 14 cm. Find c. A = 180° − 73° − 41° = 66° c/sin 41° = 14/sin 73° → c = 14 sin 41°/sin 73° ≈ 9.65 cm
Finding an angle: Example: a = 8 cm, b = 11 cm, A = 35°. Find B. sin B/11 = sin 35°/8 → sin B = 11 sin 35°/8 ≈ 0.789 → B ≈ 52.0° or 128.0° (ambiguous case)
When finding an angle using the sine rule, there may be two possible answers (one acute, one obtuse). Check whether the obtuse angle is valid given the other angles in the triangle.
Finding a side: a² = b² + c² − 2bc cos A
Example: b = 7 cm, c = 10 cm, A = 55°. Find a. a² = 49 + 100 − 2(7)(10)cos 55° = 149 − 140 × 0.5736 = 149 − 80.3 = 68.7 a = √68.7 ≈ 8.29 cm
Finding an angle: cos A = (b² + c² − a²)/(2bc)
Example: a = 9 cm, b = 7 cm, c = 5 cm. Find angle A. cos A = (49 + 25 − 81)/70 = −7/70 = −0.1 A = cos⁻¹(−0.1) ≈ 95.7°
A negative cosine value indicates an obtuse angle (between 90° and 180°).
Area = (1/2) ab sin C
where a and b are two sides and C is the included angle between them.
Example: Two sides 8 cm and 11 cm, included angle 65°. Area = (1/2)(8)(11) sin 65° = 44 × 0.906 ≈ 39.87 cm²
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