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You have now worked through the whole of Topic B5 of OCR Gateway Science A — reproduction and meiosis, DNA and the genome, monohybrid inheritance, inherited disorders and family trees, variation and mutation, natural selection, the evidence for evolution and classification, and selective breeding and genetic engineering. This final lesson pulls it all together. It shows how the topic forms a single through-line from DNA to evolution, drills the Punnett-square technique and the ratio and probability calculations that earn reliable marks, recaps the key vocabulary, and warns you about the misconceptions that catch students out. Treat it as a revision and exam-technique session rather than new content.
By the end of this lesson you should be able to trace the connections across B5, perform every B5 genetic calculation confidently, use the key terms precisely, and avoid the most common B5 errors.
The real strength of B5 is that it is not a list of separate facts but one connected story, running from the molecule of DNA all the way up to the evolution of species.
flowchart TD
A["DNA / genes<br/>(code for proteins)"] --> B["Mutation<br/>(random change → new alleles)"]
B --> C["Variation<br/>(differences within a species)"]
C --> D["Inheritance<br/>(alleles passed to offspring)"]
C --> E["Natural selection<br/>(best-suited survive and reproduce)"]
E --> F["Evolution<br/>(species change over generations)"]
D -.->|"same mechanism<br/>of inheritance"| E
Read the chain as a story: DNA carries genes that code for proteins; a mutation is a random change to the DNA that creates a new allele; new alleles are the source of variation within a species; this variation is inherited by offspring through the alleles in gametes; and when some variants are better suited to the environment, natural selection means they survive and reproduce more, so over many generations the species evolves. The same idea — alleles passed from parents to offspring — underlies both the inheritance you predict with Punnett squares and the selection that drives evolution. Being able to tell this story, moving between the molecular scale and the whole-population scale, is exactly what lifts a synoptic answer into the top band.
| Stage | Key idea | Earlier lesson |
|---|---|---|
| DNA / genes | A gene is a section of DNA that codes for a protein | DNA, genes and the genome |
| Mutation | A random change to DNA produces a new allele | Variation and mutation |
| Variation | Differences within a species (genetic, environmental or both) | Variation and mutation |
| Inheritance | Alleles pass from parents to offspring; predicted with Punnett squares | Monohybrid inheritance; inherited disorders |
| Natural selection | The best-suited survive, reproduce and pass on their alleles | Evolution by natural selection |
| Evolution | Over many generations the species changes; evidence from fossils | Evidence for evolution and classification |
The calculations in B5 are all built on the Punnett square and on turning its results into ratios, fractions, percentages and probabilities. Here is the technique again, with fresh worked examples so you can check your method.
Worked example: Two pea plants heterozygous for height (Tt) are crossed. Tall (T) is dominant to short (t). Predict the offspring ratio.
| T | t | |
|---|---|---|
| T | TT | Tt |
| t | Tt | tt |
The boxes are TT, Tt, Tt, tt. Three have at least one T (tall); one is tt (short).
Answer: the expected phenotype ratio is 3 tall : 1 short — that is 43 (75%) tall and 41 (25%) short.
Worked example: A heterozygous tall pea plant (Tt) is crossed with a short plant (tt). Predict the offspring ratio.
| T | t | |
|---|---|---|
| t | Tt | tt |
| t | Tt | tt |
The boxes are Tt, tt, Tt, tt — two tall (Tt) and two short (tt).
Answer: the expected ratio is 1 tall : 1 short (50% each).
Worked example: In the 3 : 1 cross above, if the plant produces 80 seeds, how many would you expect to grow into short plants?
Short is 41 of the offspring, so:
41×80=20
Answer: about 20 short plants. (Say "about" or "expect" — it is a prediction, not a guarantee.)
Exam Tip: A Punnett square gives a probability, not a certainty. Convert a ratio to a percentage through the fraction (3 : 1 → 43 and 41 → 75% and 25%), and to a number of offspring by multiplying the fraction by the total. Always lay the square out clearly and read the phenotypes from the alleles.
Two further skills appear regularly and are worth rehearsing together, because they use the same logic. The first is deducing parents' genotypes from their offspring: a recessive offspring (e.g. bb or ff) must have received a recessive allele from each parent, so both parents must carry that recessive allele. If the parents themselves show the dominant characteristic, they must each be heterozygous. The second is reading a family (pedigree) tree: if two unaffected parents have an affected child, the allele is recessive and both parents are carriers; for a recessive disorder, every affected person is homozygous recessive. Spotting that one relationship usually unlocks the rest of a pedigree question, and lets you draw a Punnett square to predict the chance the next child is affected.
Exam Tip: The single most powerful deduction across these questions is that a recessive offspring reveals a hidden recessive allele in each parent. Whether you are working out parental genotypes or analysing a family tree, look first for an individual showing the recessive characteristic — it tells you the most.
Use this as a final recall list. Cover the right-hand column and test yourself.
| Prompt | Answer |
|---|---|
| Type of division that makes gametes | Meiosis (four genetically different haploid cells) |
| Type of division for growth/repair | Mitosis (two identical diploid cells) |
| A version of a gene | An allele |
| Two same alleles / two different alleles | Homozygous / heterozygous |
| The alleles present / the visible characteristic | Genotype / phenotype |
| Allele that shows with one copy | Dominant (capital letter) |
| Allele needing two copies to show | Recessive (lower-case letter) |
| Carrier of cystic fibrosis genotype | Ff (heterozygous) |
| Human sex chromosomes (female / male) | XX / XY |
| A random change to the DNA base sequence | A mutation (makes a new allele) |
| Mechanism of evolution | Natural selection |
| Permanent loss of a whole species | Extinction |
| Genus + species two-word name | The binomial name |
| Choosing and breeding for desired traits | Selective breeding (artificial selection) |
| Transferring a gene between organisms | Genetic engineering |
OCR uses specific command words that tell you exactly what kind of answer to give. Reading them correctly is worth easy marks.
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