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This lesson covers the four operations applied to fractions and mixed numbers — adding, subtracting, multiplying and dividing — together with finding a fraction of an amount and the idea of a reciprocal. Fluency with fractions is essential across the whole of OCR GCSE Mathematics (J560), especially on the non-calculator Paper 1 where calculator shortcuts are not available, and it feeds directly into ratio, proportion and algebra later.
This lesson mainly builds AO1 fluency in fraction arithmetic, with AO2 reasoning when you decide whether an answer is sensible, and AO3 problem-solving in the multi-step worded examples.
| Term | Meaning |
|---|---|
| Numerator | The top number of a fraction (how many parts) |
| Denominator | The bottom number (how many equal parts in the whole) |
| Mixed number | A whole number together with a proper fraction, e.g. 243 |
| Improper fraction | A fraction whose numerator ≥ denominator, e.g. 411 |
| Equivalent fractions | Fractions of equal value, e.g. 32=128 |
| Reciprocal | The fraction "turned upside down"; ba has reciprocal ab |
| Lowest common denominator (LCD) | The LCM of the denominators, used to add or subtract |
Everything in this lesson rests on equivalent fractions — different-looking fractions with the same value. Multiplying (or dividing) the numerator and denominator by the same number does not change a fraction's value, because you are really multiplying by a disguised 1. For instance 32=3×42×4=128, and 128=12÷48÷4=32 again.
Write 2418 in its simplest form.
The HCF of 18 and 24 is 6, so divide both by 6: 2418=43.
Answer: 43.
This skill matters because every fraction answer should be given in its simplest form unless the question says otherwise, and because rewriting fractions with a common denominator (next section) is just making equivalent fractions on purpose.
To add or subtract fractions you need a common denominator. Find the LCM of the denominators, rewrite each fraction with that denominator (using equivalent fractions), then add or subtract the numerators only. The denominator tells you the size of the parts, so the parts must be the same size before you can combine them — you cannot add fifths to quarters any more than you can add metres to kilograms without converting first.
Work out 52+41.
The LCM of 5 and 4 is 20. Rewrite: 52=208 and 41=205.
208+205=2013.
Answer: 2013 (already in simplest form).
Common error: Adding the denominators too, writing 93. Once the denominators match, you add the numerators only.
Work out 65−83.
LCM of 6 and 8 is 24. Rewrite: 65=2420 and 83=249.
2420−249=2411.
Answer: 2411.
Work out 21+31+41.
The LCM of 2, 3 and 4 is 12. Rewrite each: 21=126, 31=124, 41=123.
126+124+123=1213=1121.
Answer: 1121. With three or more fractions, find a single common denominator for all of them at once rather than combining two at a time.
To add or subtract mixed numbers, the safest method is to convert each to an improper fraction first, work as above, then convert back.
Work out 321+132.
Convert: 321=27 and 132=35. LCM of 2 and 3 is 6.
27+35=621+610=631=561.
Answer: 561.
Work out 441−132.
Convert: 441=417, 132=35. LCM of 4 and 3 is 12.
417−35=1251−1220=1231=2127.
Answer: 2127.
Common error: Subtracting the whole numbers and fractions separately and getting stuck when the second fraction is bigger (41−32 is negative). Converting to improper fractions avoids this entirely.
Multiplying fractions is actually simpler than adding them — there is no need for a common denominator. To multiply, multiply the numerators together and the denominators together; cancel common factors first to keep numbers small. This works because "83 of 94" means taking three-eighths of four-ninths, and multiplying tops and bottoms captures exactly that. To divide, multiply by the reciprocal of the second fraction ("keep, change, flip"). Dividing by 32 is the same as multiplying by 23, because asking "how many two-thirds fit into a number" is the inverse of multiplying by two-thirds.
Work out 83×94.
Cancel before multiplying: 4 and 8 share a factor of 4 (→1 and 2); 3 and 9 share a factor of 3 (→1 and 3).
83×94=21×31=61.
Answer: 61.
Work out 65÷910.
Multiply by the reciprocal of 910:
65÷910=65×109=6045=43.
Answer: 43.
Common error: Flipping the first fraction instead of the second. Keep the first, change ÷ to ×, flip the second.
The reciprocal of a number is 1 divided by that number; for a fraction you simply swap numerator and denominator. The reciprocal of a whole number n is n1, and any number multiplied by its reciprocal gives 1.
Write down the reciprocal of (a) 73, (b) 5, (c) 221.
(a) Swap: 37. (b) 51. (c) First write 221=25, then the reciprocal is 52.
Answers: (a) 37, (b) 51, (c) 52.
To find a fraction of an amount, divide by the denominator and multiply by the numerator.
Work out 83 of £56.
56÷8=7 (so £7), then 7×3=21 (so £21).
Answer: £21.
OCR Exam Tip: "83 of" means "83×". Divide by the bottom, multiply by the top — that order keeps the numbers small.
Work out 232×121.
Convert both to improper fractions: 232=38, 121=23.
38×23=3×28×3=624=4.
Answer: 4. (Cancelling the 3s first gives 18×21=4 more quickly.)
Common error: Multiplying the whole numbers and the fractions separately (2×1 and 32×21). That does not work for multiplication — you must convert to improper fractions first.
A plank is 421 m long. How many 43 m pieces can be cut from it?
This is 421÷43. Convert: 421=29.
29÷43=29×34=636=6.
Answer: 6 pieces (with none left over).
Work out 21+31×43.
By BIDMAS, multiply first: 31×43=123=41.
Then add: 21+41=42+41=43.
Answer: 43.
In a class of 32 students, 83 walk to school and 41 of the remainder cycle. Work out how many students cycle.
Walkers: 83×32=12. Remainder =32−12=20. Cyclists: 41×20=5.
Answer: 5 students cycle.
Which is larger, 85 or 127?
Put both over a common denominator (the LCM of 8 and 12 is 24): 85=2415 and 127=2414. Since 15>14, 85 is the larger.
Answer: 85>127.
Common error: Assuming 127 is bigger "because the numbers are bigger". The size of a fraction depends on the relationship between numerator and denominator, so always compare over a common denominator (or convert to decimals).
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