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Anything that is moving has energy because of its motion — this is its kinetic energy. A sprinter, a thrown cricket ball, a speeding car and a falling raindrop all carry kinetic energy, and the faster and heavier they are, the more they have. Kinetic energy explains why a fast car needs a far greater distance to stop than a slow one, why a heavy lorry is so much more dangerous in a crash than a bicycle, and why even a small object moving very fast (like a bullet) can do enormous damage. This lesson, part of Topic P7 (Energy) of OCR Gateway Science A, defines kinetic energy, introduces and rearranges the equation Ek=21mv2, and explores the all-important effect of doubling the speed.
By the end of this lesson you should be able to define kinetic energy, use and rearrange Ek=21mv2, carry out calculations including finding v or m, and explain why doubling the speed of an object quadruples its kinetic energy.
Kinetic energy is the energy an object has because it is moving. Any moving object — whatever its direction — has energy stored in its kinetic store. The amount of kinetic energy depends on two things:
When an object speeds up, energy is transferred into its kinetic store; when it slows down, energy is transferred out of its kinetic store (often to the thermal store, by friction, when braking). Kinetic energy, like all energy, is measured in joules (J).
Exam Tip: Kinetic energy depends on mass and speed. Because the speed is squared in the equation, speed matters far more than mass — a small increase in speed makes a big increase in kinetic energy.
The kinetic energy of a moving object is given by:
Ek=21mv2
where Ek is the kinetic energy (in joules, J), m is the mass (in kilograms, kg) and v is the speed (in metres per second, m/s).
Two things in this equation catch people out, so note them carefully:
Calculate the kinetic energy of a 1200 kg car travelling at 20 m/s.
Step 1 — write the equation: Ek=21mv2.
Step 2 — square the speed first: v2=202=400.
Step 3 — substitute: Ek=21×1200×400.
Step 4 — calculate: Ek=0.5×1200×400=240000 J.
Answer: the car has 240000 J (= 240 kJ) of kinetic energy.
A runner of mass 60 kg sprints at 8 m/s. Calculate their kinetic energy.
Step 1 — write the equation: Ek=21mv2.
Step 2 — square the speed: v2=82=64.
Step 3 — substitute: Ek=21×60×64.
Step 4 — calculate: Ek=0.5×60×64=1920 J.
Answer: the runner has 1920 J of kinetic energy.
Exam Tip: Always square the speed first, then multiply by the mass, then halve. A common error is to halve the mass and forget to square the speed, or to square the whole of mv — neither is correct. Lay the working out step by step.
Sometimes you are given the kinetic energy and asked to find the speed or the mass. Rearranging takes a little care because of the square.
To find the speed v:
v=m2Ek
(Multiply Ek by 2, divide by the mass, then take the square root.)
To find the mass m:
m=v22Ek
(Multiply Ek by 2, then divide by the speed squared.)
A ball of mass 0.5 kg has 25 J of kinetic energy. Calculate its speed.
Step 1 — rearrange for speed: v=m2Ek.
Step 2 — substitute: v=0.52×25=0.550.
Step 3 — simplify inside the root: 0.550=100.
Step 4 — take the square root: v=100=10 m/s.
Answer: the ball is moving at 10 m/s.
A moving object has 400 J of kinetic energy and a speed of 4 m/s. Calculate its mass.
Step 1 — rearrange for mass: m=v22Ek.
Step 2 — square the speed: v2=42=16.
Step 3 — substitute: m=162×400=16800.
Step 4 — calculate: m=50 kg.
Answer: the object has a mass of 50 kg.
Exam Tip: To find a speed from kinetic energy, don't forget the final square root — it is the step most often missed. A quick check: substitute your answer back into Ek=21mv2 and see if you get the original energy.
Because the speed is squared in the equation, changing the speed has a dramatic effect on the kinetic energy. This is one of the most important ideas in the whole topic.
If you double the speed (multiply v by 2), the kinetic energy is multiplied by 22=4 — it becomes four times as large. If you treble the speed (×3), the kinetic energy becomes 32=9 times as large. In general, multiplying the speed by a factor multiplies the kinetic energy by the square of that factor.
The table below shows the kinetic energy of a 1000 kg car at different speeds. Watch how the kinetic energy grows far faster than the speed.
| Speed / m/s | v2 | Ek=21mv2 / J |
|---|---|---|
| 10 | 100 | 50 000 |
| 20 | 400 | 200 000 |
| 30 | 900 | 450 000 |
| 40 | 1600 | 800 000 |
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