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You have now met every idea in Topic P4 — from the field of a simple bar magnet to the transformers that power the National Grid. This final lesson draws those threads together. The big themes of P4 are really two mirror-image effects: the motor effect (current + field → force/movement) and the generator effect (movement + field → induced voltage). Almost every device in the topic is one or other of these. This lesson, part of Topic P4 (Magnetism and magnetic fields) of OCR Gateway Science A, brings the motor and generator effects side by side, pulls together the Higher-tier equations F=BIL and the transformer relations, picks apart the most common exam mistakes, and walks through a worked multi-step problem of the kind that ties several ideas together.
By the end of this lesson you should be able to compare the motor and generator effects and the devices based on each, select and use the correct P4 equation, avoid the classic P4 exam mistakes, and work through a multi-step magnetism problem with confidence.
The whole of P4 hangs on two opposite effects. Getting them clearly separated in your mind is the single most valuable exam skill in this topic.
| Motor effect | Generator effect | |
|---|---|---|
| What goes in | Current in a wire + a magnetic field | Movement of a wire (or magnet) + a magnetic field |
| What comes out | A force / movement | An induced potential difference (and current) |
| Fleming's rule | Left hand | Right hand |
| Devices | Electric motor, loudspeaker | Generator/dynamo, microphone, transformer |
| Higher equation | F=BIL | (transformer) VsVp=NsNp |
Notice the pleasing symmetry: a motor and a generator are built from almost identical parts (a coil, magnets, a commutator or slip rings), but run in opposite directions — put electricity in and a motor gives you movement; put movement in and a generator gives you electricity. The same pairing links the loudspeaker (motor effect: electricity → sound) and the microphone (generator effect: sound → electricity).
graph LR
E[Electrical energy] -->|motor effect| M[Movement]
M -->|generator effect| E
Exam Tip: Decide first which effect a question is about. Current in, force out → motor effect → left hand. Movement in, voltage out → generator effect → right hand. Choosing the right effect (and the right hand) before anything else stops most P4 mistakes.
P4 has a small set of equations, and Higher-tier questions reward picking the correct one quickly. Identify what you are given and what you are asked for.
| If the question is about… | …use | Tier |
|---|---|---|
| Force on a current-carrying wire | F=BIL | Higher |
| Transformer voltages and turns | VsVp=NsNp | Higher |
| An ideal transformer's currents | VpIp=VsIs | Higher |
Two reminders that protect easy marks:
Exam Tip: Write down the equation first, then substitute, then give the answer with a unit. Examiners award method marks for the equation and substitution even if the final arithmetic slips — so never jump straight to a number.
Many of the best exam questions combine two ideas. Here is a worked example that uses both transformer equations together.
A power station produces 25 kW of electrical power. A step-up transformer raises the voltage from 5000 V to 100000 V for transmission. The transformer can be treated as ideal.
(a) Calculate the current in the primary coil. (b) Calculate the current in the secondary (transmission) cable. (c) The transformer's primary coil has 400 turns. Calculate the number of turns on the secondary coil. (Higher)
Part (a) — primary current. The power delivered to the primary is P=VpIp, so:
Ip=VpP=500025000=5.0 A
(Note 25 kW=25000 W.)
Part (b) — secondary current. For an ideal transformer, VpIp=VsIs, so:
Is=VsVpIp=1000005000×5.0=10000025000=0.25 A
The voltage was stepped up ×20 (from 5000 to 100000 V), so the current was stepped down ×20 (from 5.0 to 0.25 A) — exactly as expected, keeping the power at 25 kW.
Part (c) — secondary turns. Using VsVp=NsNp, rearranged for Ns:
Ns=Np×VpVs=400×5000100000=400×20=8000 turns
Answers: (a) 5.0 A; (b) 0.25 A; (c) 8000 turns. The low transmission current of 0.25 A is exactly why the grid steps the voltage up — it keeps the I2R heating loss in the cables tiny.
Exam Tip: In a multi-step problem, carry your answers forward: the current you find in part (a) feeds straight into part (b). Always sanity-check with the step-up/step-down logic — if the voltage went up ×20, the current must come down ×20.
The topic has a handful of classic traps. Knowing them in advance is worth several marks.
Exam Tip: Before writing a field diagram, mentally tick the three rules — arrows N→S outside, never cross, closest at the poles. Before a calculation, tick the units. These two habits remove the most common P4 errors.
When you revise this topic, a short checklist catches the points examiners return to year after year. Try to answer each from memory:
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