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Edexcel A-Level Maths: Trigonometry

6 exam-style questions with full mark schemes and model answers. Write your own answer and the AI examiner marks it against the mark scheme.

Question 112 marksExpress

The function fff is defined by f(θ)=5cosθ+12sinθf(\theta) = 5\cos\theta + 12\sin\thetaf(θ)=5cosθ+12sinθ, where θ\thetaθ is measured in degrees.

(a) Express f(θ)f(\theta)f(θ) in the form Rcos(θα)R\cos(\theta - \alpha)Rcos(θα), where R>0R > 0R>0 and 0<α<900 < \alpha < 90^{\circ}0<α<90. Give the exact value of RRR and the value of α\alphaα to one decimal place. (4 marks)

(b) Hence solve the equation 5cosθ+12sinθ=6.55\cos\theta + 12\sin\theta = 6.55cosθ+12sinθ=6.5 for 0θ<3600 \leq \theta < 360^{\circ}0θ<360, giving your answers to one decimal place. (5 marks)

(c) State the maximum value of f(θ)f(\theta)f(θ) and the smallest positive value of θ\thetaθ at which this maximum occurs. (3 marks)

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Question 210 marksProve

(a) Starting from the addition formula for cos(A+B)\cos(A + B)cos(A+B), prove the double-angle identity

cos2θ12sin2θ\cos 2\theta \equiv 1 - 2\sin^2\thetacos2θ12sin2θ

(4 marks)

(b) Hence solve the equation

cos2θ+3sinθ2=0\cos 2\theta + 3\sin\theta - 2 = 0cos2θ+3sinθ2=0

for 0θ<2π0 \leq \theta < 2\pi0θ<2π, giving your answers in terms of π\piπ. (6 marks)

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Question 38 marksFind

The diagram referred to below shows a sector OABOABOAB of a circle of centre OOO and radius 8 cm8\ \text{cm}8 cm. The angle AOBAOBAOB is 0.750.750.75 radians. The chord ABABAB divides the sector into a triangle OABOABOAB and a shaded segment.

(a) Find the length of the arc ABABAB and hence the perimeter of the sector OABOABOAB. (3 marks)

(b) Find the area of the sector OABOABOAB and hence the area of the shaded segment, giving each answer to 3 significant figures. (5 marks)

(Work in radians throughout.)

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Question 46 marksSolve

Solve the equation

2tan2x+secx=12\tan^2 x + \sec x = 12tan2x+secx=1

for 0x<3600 \leq x < 360^{\circ}0x<360, giving your answers to one decimal place where appropriate. (6 marks)

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Question 55 marksProve

Prove that

11sinθ+11+sinθ2sec2θ\frac{1}{1 - \sin\theta} + \frac{1}{1 + \sin\theta} \equiv 2\sec^2\theta1sinθ1+1+sinθ12sec2θ

(5 marks)

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Question 64 marksShow that

When θ\thetaθ is small and measured in radians, use the small-angle approximations for sin\sinsin and cos\coscos to show that

cos3θ1θsin2θ94\frac{\cos 3\theta - 1}{\theta\sin 2\theta} \approx -\frac{9}{4}θsin2θcos3θ149

(4 marks)

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